Display in table format from mysql - php

Question

I have table with product_category and its has more than 20 categories and I want to display them in table format like below image
I like to place categories in 5 td then how I can be fixed towards tr in a table
Below is code I have tried, but its not giving the desired output
And below is the image that might be solution I needed
Below code
<table>
<?php
$fquery5 = mysql_query("select Cat_ID, Cat_Name from product_category where Active_Flag=1");
$count1 = mysql_num_rows($fquery5);
$hor_length = 5;
$ver_length = $count1 / $hor_length;
$data1 = mysql_fetch_row($fquery5);
for ($i = 0; $i <= $ver_length; $i++) {
echo "<tr>";
for ($j = $i + $hor_length; $j <= $count1; $j++) {
echo "<td>";
echo "Id : " . $data1[0] . " = " . $data1[1];
echo "</td>";
}
echo "</tr>";
}
?>
</table>
Added resultant output image answered by #DaveRandom

Answer 1

Try this (FIXED):
<?php
// Number of columns
$hor_length = 5;
// Do the query, get the number of rows in the result
$fquery5 = mysql_query("
SELECT Cat_ID, Cat_Name
FROM product_category
WHERE Active_Flag = 1
");
$numrows = mysql_num_rows($fquery5);
// Start of table
echo "<table>\n<tr>\n";
// Loop the results with a counter
for ($i = 1; $row = mysql_fetch_row($fquery5); $i++) {
// Every iteration echos a cell
echo "<td>Id : " . $row[0] . " = " . $row[1] . "</td>\n";
// If we're at the end of a row, echo a row break, unless it is the last result
if (!($i % $hor_length) && $i < $numrows) {
echo "</tr>\n<tr>\n";
}
}
// Right-pad the end row with empty cells
for ($i--; $i % $hor_length; $i++) {
echo "<td></td>\n";
}
// Echo the end of the table
echo "</tr>\n</table>";
See a working example (manually created the data array since I can't query a DB from codepad)