I want an id column generated by php loop and I tried the code below.
This code is working but it skips first row. For e.g. if there are 153 rows, it shows only 152 rows because it skips first row and starts numbering from second row.
$i = 0;
$result = mssql_query ($sql);
$cell = mssql_fetch_array($result);
while ($i <= $cell & $cell = mssql_fetch_array($result))
{
$i = $i + 1;
echo "<tr><td>".$i."</td>";
echo "<td>".$cell[0]."</td>";
echo "<td>".$cell[1]."</td>";
echo "<td>".$cell[2]."</td>";
echo "<td>".$cell[3]."</td>";
echo "<td>".$cell[4]."</td>";
echo "<td>".$cell[5]."</td>";
echo "</tr>";
}
$cell = mssql_fetch_array($result);
^^^^^^^^^^^^^^^^^
fetches the first record
while ($i <= $cell & $cell = mssql_fetch_array($result))
^^^^^^^^^^^^^^^^^
fetches the second record
You're never outputting the first record you're fetching.
No idea what you're trying to do with that $i condition.
$i = 0;
$result = mssql_query ($sql);
//$record = mssql_fetch_array($result); - you don't need this
while ($cell = mssql_fetch_array($result)) //you dont need $i <= $cell
{
$i++; //$i = $i + 1;
echo "<tr><td>".$i."</td>";
echo "<td>".$cell[0]."</td>";
echo "<td>".$cell[1]."</td>";
echo "<td>".$cell[2]."</td>";
echo "<td>".$cell[3]."</td>";
echo "<td>".$cell[4]."</td>";
echo "<td>".$cell[5]."</td>";
echo "</tr>";
}
I'm guessing you probably want && instead of & here:
while ($i <= $cell & $cell = mssql_fetch_array($result))
Related
I'm stuck trying to use nested loops to make a reflective pattern from numbers.
I've already tried, but the output looks like this:
|0|1|2|
|0|1|2|
|0|1|2|
This is my code:
<?php
echo "<table border =\"1\" style='border-collapse: collapse'>";
for ($row=1; $row <= 3; $row++) {
echo "<tr> \n";
for ($col=1; $col <= 3; $col++) {
$p = $col-1;
echo "<td>$p</td> \n";
}
echo "</tr>";
}
echo "</table>";
?>
I expected this result:
|0|1|0|
|1|2|1|
|0|1|0|
Each columns' and rows' cell values must increment to a given amount then decrement to form a mirror / palindromic sequence.
First declare the square root of the of the table cell count. In other words, if you want a 5-by-5 celled table (25 cells), declare $size = 5
Since your numbers are starting from zero, the highest integer displayed should be $size - 1 -- I'll call that $max.
I support your nested loop design and variables are appropriately named $row and $col.
Inside of those loops, you merely need to make the distinction between your "counters" as being higher or lower than half of the $max value. If it is higher than $max / 2, you subtract the "counter" (e.g. $row or $col) from $max.
By summing the two potentially adjusted "counters" and printing them within your inner loop, you generate the desired pattern (or at least the pattern I think you desire). This solution will work for $size values from 0 and higher -- have a play with my demo link.
Code: (Demo)
$size = 5;
$max = $size - 1;
echo "<table>\n";
for ($row = 0; $row < $size; ++$row) {
echo "\t<tr>";
for ($col = 0; $col < $size; ++$col) {
echo "<td>" . (($row >= $max / 2 ? $max - $row : $row) + ($col >= $max / 2 ? $max - $col : $col)) . "</td>";
}
echo "</tr>\n";
}
echo "</table>";
Output:
<table>
<tr><td>0</td><td>1</td><td>2</td><td>1</td><td>0</td></tr>
<tr><td>1</td><td>2</td><td>3</td><td>2</td><td>1</td></tr>
<tr><td>2</td><td>3</td><td>4</td><td>3</td><td>2</td></tr>
<tr><td>1</td><td>2</td><td>3</td><td>2</td><td>1</td></tr>
<tr><td>0</td><td>1</td><td>2</td><td>1</td><td>0</td></tr>
</table>
There are a lot of ways to achive that.
An easy way to do that is;
<?php
$baseNumber = 0;
echo "<table border='1' style='border-collapse: collapse'>";
for ($row = 0; $row < 3; $row++) {
echo "<tr>";
if ($row % 2 !== 0) {
$baseNumber++;
} else {
$baseNumber = 0;
}
for ($col = 0; $col < 3; $col++) {
echo "<td>" . ($col % 2 === 0 ? $baseNumber : $baseNumber + 1) . "</td>";
}
echo "</tr>";
}
echo "</table>";
this code will do what you want just call the patternGenerator function with the number of distinct numbers you want for your example these numbers are 3 (0,1,2).
the idea in this code is to use two for loops one that starts from the minimum number to the maximum one and the other one that starts after the maximum number decreasing to the minimum.
for example:
if min = 0 and max = 5
the first loop will print 0,1,2,3,4,5
and the second will print 4,3,2,1,0
and that's it.
at first, I created a function that creates just on row called rowGenerator it takes $min and $max as parameters and prints one row
so if we want to print a row like this: |0|1|0| then we will call this function with min = 0 and max = 1 and
if we want to print a row like this: |1|2|1| then we will call it with min = 1 and max = 2.
function rowGenerator($min, $max)
{
echo '<tr>';
for($i = $min; $i<=$max;$i++)
echo '<td>'.$i.'</td>';
for($i = $max-1; $i>=$min;$i--)
echo '<td>'.$i.'</td>';
echo '</tr>';
}
for now, we can print each row independently. now we want to print whole the table if we look at the calls we do for the rowGenerator function it will looks as follow:
(min = 0, max = 1),
(min = 1, max = 2) and
(min = 0, max = 1).
minimums are (0,1,0).
yes, it's the same pattern again. then we need two loops again one to start from 0 and increase the number until reach 1 and the other one to loop from 0 to 0.
and that's what happened in the patternGenerator function. when you call it with the number of distinct numbers the function just get the min that will always be 0 in your case and the max.
function patternGenerator($numberOfDistinct )
{
echo "<table border =\"1\" style='border-collapse: collapse'>";
$min = 0;
$max = $numberOfDistinct - 2;
for($i = $min;$i<=$max; $i++)
{
rowGenerator($i,$i+1);
}
for($i = $max-1;$i>=$min;$i--)
{
rowGenerator($i,$i+1);
}
echo '</table>';
}
this is the output of calling patternGenerator(3):
the output of calling patternGenerator(5):
I have table with product_category and its has more than 20 categories and I want to display them in table format like below image
I like to place categories in 5 td then how I can be fixed towards tr in a table
Below is code I have tried, but its not giving the desired output
And below is the image that might be solution I needed
Below code
<table>
<?php
$fquery5 = mysql_query("select Cat_ID, Cat_Name from product_category where Active_Flag=1");
$count1 = mysql_num_rows($fquery5);
$hor_length = 5;
$ver_length = $count1 / $hor_length;
$data1 = mysql_fetch_row($fquery5);
for ($i = 0; $i <= $ver_length; $i++) {
echo "<tr>";
for ($j = $i + $hor_length; $j <= $count1; $j++) {
echo "<td>";
echo "Id : " . $data1[0] . " = " . $data1[1];
echo "</td>";
}
echo "</tr>";
}
?>
</table>
Added resultant output image answered by #DaveRandom
Try this (FIXED):
<?php
// Number of columns
$hor_length = 5;
// Do the query, get the number of rows in the result
$fquery5 = mysql_query("
SELECT Cat_ID, Cat_Name
FROM product_category
WHERE Active_Flag = 1
");
$numrows = mysql_num_rows($fquery5);
// Start of table
echo "<table>\n<tr>\n";
// Loop the results with a counter
for ($i = 1; $row = mysql_fetch_row($fquery5); $i++) {
// Every iteration echos a cell
echo "<td>Id : " . $row[0] . " = " . $row[1] . "</td>\n";
// If we're at the end of a row, echo a row break, unless it is the last result
if (!($i % $hor_length) && $i < $numrows) {
echo "</tr>\n<tr>\n";
}
}
// Right-pad the end row with empty cells
for ($i--; $i % $hor_length; $i++) {
echo "<td></td>\n";
}
// Echo the end of the table
echo "</tr>\n</table>";
See a working example (manually created the data array since I can't query a DB from codepad)
I need to create 3 HTML columns in PHP with data returned from MySQL. I would like the data split evenly between all 3 columns... How would I go about doing this?
You could try doing something like this:
$result = mysql_query("SELECT value FROM table");
$i = 0;
echo '<table><tr>';
while ($row = mysql_fetch_row($result)){
echo '<td>' . $row[0] . '</td>';
if ($i++ == 2) echo '</tr><tr>'
}
echo '</tr></table>';
note this table has the values ordered like
1 2 3
4 5 6
7 8 9
If you wanted it vertically like
1 4 7
2 5 8
3 6 9
Then you should do something like
$result = mysql_query("SELECT value FROM table");
$data = Array();
while ($row = mysql_fetch_row($result)) $data[] = $row;
for ($i = 0; $i < count($data) / 3; $i++){
echo '<table><tr>';
for ($j = 0; $j < 3; $j++){
echo '<td>' . $data[ $i + $j * 3] . '</td>';
}
echo '</tr><tr>'
}
echo '</tr></table>';
You can create an HTML table and then use a PHP foreach loop to loop through the MySQL result set and put each field in its own table. At the end of each record returned by the MySQL query, end the table row and start a new one.
A small detail, if return more entries than the "fetch_row" use "break", based on the answer from #Robbie: Spliting mysql data in 3 columns error -3-columns-error
I've got one nagging little bug in this script. I'm going through my cart items and passing them into hidden inputs. The cart_id ($obj->id) is working fine into the value="" but my iteration loop that gives each value a unique name="" (cart_id_1, cart_id_2 etc) is NOT iterating.
<?php
$pass_cart_q = "SELECT c.id FROM carts AS c WHERE c.user_session_id='$sid'";
$result = $mysqli->query($pass_cart_q);
$i = 1;
while ($obj = $result->fetch_object()) {
echo "<input type=\"hidden\" name=\"cart_id_".$i."\" value=\" .$obj->id. \"><br>";
$i = $i++;
}
mysqli_close();?>
Each name field is coming through as cart_id_1
$i=$i++;
That's the problem just do:
$i++
Please replace $i = $i++; with just $i++.
$i = 1;
$i = $i++;
echo $i, "\n"; // 1
$i = 1;
$i = ++$i;
echo $i, "\n"; // 2
$i = 1;
$i++;
echo $i, "\n"; // 2
$i = 1;
++$i;
echo $i, "\n"; // 2
What $i = $i++ will cause it literally this: "make $i equal to $i and then increase it by one", but the $i will still remain the same. To solve this, simply replace $i = $i++; with $i++.
Manual Entry
you are assigning the incremented value to $i variable. and hence it is not able to iterate. instead you should remove that assignment variable $i and it should only be $i++
I'm querying a database for names that are numbered 1-26 alphabetically. I have the following code, but since HTML is structured tr then td, the table appears alphabetically by row as opposed to by column. How can I make it appear in order by column?
$query = mysql_query("SELECT name FROM people WHERE main=1 ORDER BY id");
$i = 0;
while($result = mysql_fetch_array($query)) {
$name = $result['name'];
if ($i % 5 == 0) echo "<tr>\n";
echo "<td width=\"150\">";
echo "".$name."<br />";
echo "</td>\n";
$i++;
if ($i % 5 == 0) echo "</tr>\n";
};
alpha beta charlie
delta echo foxtrot
vs.
alpha charlie echo
beta delta foxtrot
Also, I'm open to reworking the code if there's a more efficient way.
You could just access the output array in strides. Compute how many rows you need as the number of results divided by 5, and use the row count as the stride.
$ncols = 5;
$nrows = $nresults / $ncols + ($nresults % $ncols == 0 ? 0 : 1);
for ($i = 0; $i < $nrows; $i++)
{
// start row
for ($j = 0; $k < $ncols; $j++)
{
// print $results[$nrows * $j + $i]
}
// end row
}
You'll have to transfer your query results into an array $results first. Since you'll have to know the total number of results, this is sort of mandatory, though I'd be curious if anyone has a solution that can work while fetching the results.
Update: See Justin's answer for a cool solution that grows the output while fetching the query results line by line. Since it's currently being worked on, here's a summary (credits to Justin):
$nresults = mysql_num_rows($query);
$ncols = 5;
$nrows = (int) ceil($nresults / $ncols);
$i = 0; $cols = array_fill(0, $nrows, "");
while ($result = mysql_fetch_array($query))
$cols[$i++ % $nrows] .= "<td>$result['name']</td>";
echo "<tr>" . implode("</tr><tr>", $cols) . "</tr>";
Edit:
After the discussion in the comments between myself, Kerrek SB and the OP bswinnerton, the following code seems to be the most effective:
$columns = 3;
$rowcount = mysql_num_rows($query);
$rows = ceil($rowcount / $columns);
$rowdata = array_fill(0, $rows, "");
$ctr = 0;
while ($result = mysql_fetch_array($query))
$rowdata[$ctr++ % $rows] .= '<td>'.$result['name'].'</td>';
echo '<tr>'.implode('</tr><tr>',$rowdata).'</tr>';
This will create three columns, filled vertically (my original answer would create three rows). It also properly initializes the array (preventing PHP warnings), yields a correct row count for result counts that aren't divisible by the column count, and incorporates Kerrek's clever "calc-row-in-the-subscript" trick.
Original Post:
You could use arrays and implode() This way, you only have to make one pass through your results:
$row = 0;
$rows = 3;
$rowdata = array();
while($result = mysql_fetch_array($query))
{
if ($row >= $rows) $row = 0;
$rowdata[$row++] .= '<td>'.$result['name'].'</td>';
}
echo '<tr>'.implode('</tr><tr>',$rowdata).'</tr>';