php json to load jquery datagrid - php

Question

I've this php code that passes results to a jquery getJSON function that doesn't work properly.
here is my code:
$data["total"]=mysql_num_rows($s);
while ($r = mysql_fetch_array($s))
{
$ris_sql["utente"]=tv($r["utente"]);
$ris_sql["contratto"]=tv($r["contratto"]);
$ris_sql["login"]=tv($r["login"]);
$ris_sql["piattaforma"]=tv($r["piattaforma"]);
$ris_sql["azione"]=tv(format_valid($r["azione"]));
$ris_sql["data"]=tv($r["data"]);
$ris_sql["note"]=tv(str_replace("<br>","",$r["note"]));
$riga[]=$ris_sql;
}
$data["rows"]=json_encode($riga, JSON_FORCE_OBJECT);
echo json_encode($data);
If I try to use firebug I see that my rows elements in JSON result like a string instead a series of objects, what is wrong in my code??

Answer 1

You are double-encoding the $riga JSON. Don't separately encode the $riga part prior to encoding the rest of the $data array you're sending back to the browser.
// Instead of
$data["rows"] = json_encode($riga, JSON_FORCE_OBJECT);
// This double-encodes the contents of $data before outputting back to the browser or ajax call
echo json_encode($data);
// Just do:
echo json_encode($data, JSON_FORCE_OBJECT);
If the format isn't what you expect, instead you can cast $riga from an array to an object and then encode the whole thing without JSON_FORCE_OBJECT.
// Cast $riga from an assoc array to an instance of stdClass
$data['rows'] = (object)$riga;
// And then JSON encode the whole $data
echo json_encode($data);