I have a string on my databas, that I'm trying to insert into a json object as an Array, not a string..:
$arrayInString = "[2,3,5,5,6]"; // this comes from the database
$jsonObject = array('numbers' => $arrayInString);
$json = json_encode($jsonObject, JSON_UNESCAPED_SLASHES);
echo $json;
When I execute this.. my Json object is..
numbers: "[2,3,5,5,6]";
and not
numbers: [2,3,5,5,6];
Like I originally wanted.. can't get this to work, can anyone help?
Like was said you need to decode the passed data from the database and then build your array output. Something like this:
$arrayInString = "[2,3,5,5,6]"; // this comes from the database
// decode the JSON from the database as we build the array that will be converted back to json
$jsonObject = array('numbers' => json_decode($arrayInString));
echo json_encode($jsonObject, JSON_UNESCAPED_SLASHES);
The slightly modified code above outputs:
{"numbers":[2,3,5,5,6]}
You need to json_decode your $arrayInString variable before you add it to the associative array.
Related
How to add another object with value in data?
Something start like :
$data=[{name:"apple"}]
And i wanted output like this
$data=[{name:"apple",city:"gotham"}]
Dont try and build JSON manually, create a PHP data structure that you want and then use json_encode() to make it into a JSON String
$d = [(object)['name' => 'apple', 'city' => 'gotham']];
echo json_encode($d);
RESULT
[{"name":"apple","city":"gotham"}]
If some values already exists, you should decode it to a PHP data struture and then add to it and convert back to JSON String
$data='[{"name":"apple"}]';
$d = json_decode($data);
$d[0]->city = 'Gotham';
$data = json_encode($d);
RESULT
[{"name":"apple","city":"Gotham"}]
Here is the json content:
{
"success":true,
"data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}",
"message":null
}
I'm looking to get the value of download_link. How can I do that?
This is what I tried:
<?php
$jsndata = {"success":true,"data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}","message":null};
$jsn = json_decode($jsndata,true);
$temperatureMin = $jsn['data'][6]['download_link'];
echo $temperatureMin;
?>
You have a json object containing another serialized json object.
Decode the first object, get the second serialized object and decode that:
$jsndata = '{
"success":true,
"data":"{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"}",
"message":null
}';
// Decode the main json object
$jsn = json_decode($jsndata,true);
// Since 'data' is another serialized object, you need to decode that as well:
$data = json_decode($jsn['data'], true);
// Now you can access the contents of 'data'
echo $data['download_link'];
Demo: https://3v4l.org/1PcQp
You need:
- quotes around your JSON
- to remove the quotes around the inner object
$jsndata = '{"success":true,"data":{\"campaign_name\":\"helloworld\",\"download_link\":\"https:\\\/\\\/google.com\\\/accesskey\\\/getfile\\\/m-spqn-e61-2aef2575a0b5250354f2b0fda033e703?token=HUSYjdC5jyJskXUHiKn13l1A1BaAjH2R&dcma=5ecceb0522bcd0db\",\"link\":\"http:\\\/\\\/www.lol.com\\\/remove\\\/remove.php\"},"message":null}' ;
And you need to remove the [6] from your array access:
$temperatureMin = $jsn['data']['download_link'];
I using codeigniter. I want to retrive data from database and convert it into JSON object not JSON array.I'm using following code
public function json()
{
$content = $this->db->get('todolist'); //todolist table name
$data = $content->result_array();
echo json_encode($data);
}
Above code is converting database into JSON array.
Output
[{"todo_id":"1","todo_content":"Homework","date":"2016-05-05","iscomplete":null,"imagelink":"Lighthouse.jpg"},{"todo_id":"2","todo_content":"exam","date":"2015-04-21","iscomplete":null,"imagelink":"Desert.jpg"},{"todo_id":"3","todo_content":"Lab report","date":"2014-08-29","iscomplete":null,"imagelink":"FB_IMG_14700753538617403.jpg"}]
What will be best way to convert it into JSON object
Sangam try to understand the concept, check the following line:
$data = $content->result_array(); // $data is an array
echo json_encode($data); // here you are converting it into an json object
Your $data array contains more than one index in it that's why the json object is having multiple {} inside [];
You want to json_encode($data, JSON_FORCE_OBJECT).
The JSON_FORCE_OBJECT flag, as the name implies, forces the json output to be an object, even when it otherwise would normally be represented as an array.
Refer: PHP Array to Json Object
You can use JSON_FORCE_OBJECT see the example below.
echo json_encode($data, JSON_FORCE_OBJECT);
Assuming you're only getting one row back from your query.
change
echo json_encode($data);
to
echo json_encode($data[0]);
Im not sure what is happening, but if i do
json_encode()
On a single array, i get valid json, but if i do something like
$ar['key'] = "name";
$array[] = json_encode($ar);
$json = json_encode($array);
It will return invalid json like so:
["{"key":"name"}"]
The expected outcome is
[{"key":"name"}]
I have searched for hours trying to find what is going on.
Due to lack of desired outcome, I can only assume you are trying to get a multidimensional array.
The correct way to achieve this would be to build an array of arrays, and then json_encode the parent array.
$data = array();
$data['fruits'] = array('apple','banana','cherry');
$data['animals'] = array('dog', 'elephant');
$json = json_encode($data);
Following this code, $json will have the following value
{"fruits":["apple","banana","cherry"],"animals":["dog","elephant"]}
It could then be parsed properly by javascript using jQuery.parseJSON()
Just json_encode the entire array.
$ar['key'] = "name";
$json = json_encode($ar);
json_encode returns a string, and json encoding a string will return a string.
Also it's json_encode, not $json_encode
I have a JSON that's strangely formatted ...but it's the way I receive it. Because the arrays inside are huge, simply copying and pasting it takes a long time, so I'm wondering if there's a PHP way to do it.
The way I get it is like this:
{"count":459,"results":[{"title":"Something ....}],"params":{"limit..},"type":"Listing","pagination":{"..":5}}
But I want to get only the "results" array, basically the part of [{"title":"Something ....}]. How would I do that?
Do
$arr = json_decode(your_json, true);
If you ned it as JSON again, do
json_encode($arr['results']);
You can get to that part as follows:
$json = '{"count":459,"results":[{"title":"Something ...."}],"params":{"limit":".."},"type":"Listing","pagination":{"..":5}}';
$obj = json_decode($json);
echo $obj->results[0]->title;
Outputs:
Something ....
You have to decode your json. Be sure that the json is valid!
Your decoded json returns an object of type stdClass instead of an array!
See below the tested code:
$json = '{"count":459,"results":[{"title":"Something ...."}],"params":{"limit": "foo"},"type":"Listing","pagination":{"foo":5}}';
$decoded = json_decode($json);
So you can access array results from the object $decoded:
print_r($decoded->results);
But, in the array, there are objects, thus:
echo $decoded->results[0]->title; // Something ....