Date range array excluding the Sunday & the holiday in PHP - php

Question

I have a function which returns all the dates between two dates in an array, But I need to exclude Sundays in that array.
public function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
After excluding the Sundays, I have a table where I will be storing some dates, I need to exclude those dates from the array too.
like, If I enter the date range as 01-05-2012(DD-MM-YYYY) to 10-05-2012,
The 06-05-2012 will be Sunday & the date 01-05-2012 & 08-05-2012 will be in the table which I mentioned above,
The final out put should be like,
02-05-2012
03-05-2012
04-05-2012
05-05-2012
07-05-2012
09-05-2012
10-05-2012
How to do this in PHP ?
I tried some but couldn't find the right way to do it.

Answer 1

For the Sundays part:
public function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
if (date("D", $current) != "Sun")
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
For the holidays part:
First you need to load the dates into some kind of array and then loop through the array for each of your dates and check if they match.

Answer 2

I found the answer for my question, Thanks for the people who helped me.
public function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$sql = "SELECT * FROM ost_holidays where holiday_date='".date('Y-m-d', $current)."' LIMIT 1";
$sql = db_query($sql);
$sql = db_fetch_array($sql);
if($sql['holiday_date'] != date('Y-m-d',$current))
if (date('w', $current) != 0)
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
The above code is for removing the holidays & the Sundays in the given range.

Answer 3

I did this same above method in Jquery
//Convert dates into desired formatt
function convertDates(str) {
var date = new Date(str),
mnth = ("0" + (date.getMonth() + 1)).slice(-2),
day = ("0" + date.getDate()).slice(-2);
return [date.getFullYear(), mnth, day].join("-");
}
// Returns an array of dates between the two dates
var getDates = function(startDate, endDate, holidays) {
var dates = [],
currentDate = startDate,
addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
};
while (currentDate <= endDate) {
dates.push(currentDate);
currentDate = addDays.call(currentDate, 1);
}
return dates;
};
//Indise Some Function
var datesTemp = [];
var dates = getDates(new Date(prodDet.details.date1), new Date(prodDet.details.date2));
dates.forEach(function(date) {
if (date.getDay() != 0) {
datesTemp.push(convertDates(date));
}
});
datesTemp.forEach(function(date) {
for (var j = 0; j < prodDet.holidays.length; j++) {
if ((prodDet.holidays[j] != date)) {
ideal.idates.push(date);
}
}
});
console.log(ideal.idates);
//Function Ends Here