how to get sunday date between two date - php

Question

I try this
<?php
$startdate = '2016-07-15';
$enddate = '2016-07-17';
$sundays = [];
$startweek=date("W",strtotime($startdate));
$endweek=date("W",strtotime($enddate));
$year=date("Y",strtotime($startdate));
for($i=$startweek;$i<=$endweek;$i++) {
$result=$this->getWeek($i,$year);
if($result>$startdate && $result<$enddate) {
$sundays[] = $result;
}
}
print_r($sundays);
public function getWeek($week, $year)
{
$dto = new \DateTime();
$result = $dto->setISODate($year, $week, 0)->format('Y-m-d');
return $result;
}
?>
this return blank array. but in between two dates 2016-07-17 is Sunday.
I get output as 2016-07-17
I refer this here
But in this link return output as no of sunday not date.

Answer 1

Give this a try:
$startDate = new DateTime('2016-07-15');
$endDate = new DateTime('2016-07-17');
$sundays = array();
while ($startDate <= $endDate) {
if ($startDate->format('w') == 0) {
$sundays[] = $startDate->format('Y-m-d');
}
$startDate->modify('+1 day');
}
var_dump($sundays);
If you want later to use the DateTime objects instead of the formatted date, then you must use DateTimeImmutable for the $startDate variable:
$startDate = new DateTimeImmutable('2016-07-15');
$endDate = new DateTimeImmutable('2016-07-17');
$sundays = array();
while ($startDate <= $endDate) {
if ($startDate->format('w') == 0) {
$sundays[] = $startDate;
}
$startDate->modify('+1 day');
}
var_dump($sundays);

Answer 2

function getDateForSpecificDayBetweenDates($startDate, $endDate, $weekdayNumber)
{
$startDate = strtotime($startDate);
$endDate = strtotime($endDate);
$dateArr = array();
do
{
if(date("w", $startDate) != $weekdayNumber)
{
$startDate += (24 * 3600); // add 1 day
}
} while(date("w", $startDate) != $weekdayNumber);
while($startDate <= $endDate)
{
$dateArr[] = date('Y-m-d', $startDate);
$startDate += (7 * 24 * 3600); // add 7 days
}
return($dateArr);
}
$dateArr = getDateForSpecificDayBetweenDates('2010-01-01', '2010-12-31', 0);
print "<pre>";
print_r($dateArr);
Try out this code..

Answer 3

Try this
$start = new DateTime($startDate);
$end = new DateTime($endDate);
$sundays = [];
while ($start->getTimestamp() != $end->getTimestamp()) {
if ($start->format('w') == 0) {
$sundays[] = $start->format('Y-m-d');
}
$start->add('+1 DAY');
}

Answer 4

This will return you all sundays between two dates.
$startdate = '2016-05-1';
$enddate = '2016-05-20';
function getSundays($start, $end) {
$timestamp1 = strtotime($start);
$timestamp2 = strtotime($end);
$sundays = array();
$oneDay = 60*60*24;
for($i = $timestamp1; $i <= $timestamp2; $i += $oneDay) {
$day = date('N', $i);
// If sunday
if($day == 7) {
// Save sunday in format YYYY-MM-DD, if you need just timestamp
// save only $i
$sundays[] = date('Y-m-d', $i);
// Since we know it is sunday, we can simply skip
// next 6 days so we get right to next sunday
$i += 6 * $oneDay;
}
}
return $sundays;
}
var_dump(getSundays($startdate, $enddate));

Answer 5

Use Carbon
$arrayOfDate = [];
$startDate = Carbon::parse($startDate)->modify('this sunday');
$endDate = Carbon::parse($endDate);
for ($date = $startDate; $date->lte($endDate); $date->addWeek()) {
$arrayOfDate[] = $date->format('Y-m-d');
}
return $arrayOfDate;