php search engine for a database with foreignkeys - php

hi all Im trying to create a php search page that will bring up a list of books from a mysql database, then when the book name is clicked bring up a a list of books that are in a relationship table with them. I'm slightly struggling with the code and was hoping someone would be able to lend a hand
-This is my search.php file
<?php
$i=0;
$column_name = 'title'; // column to search by
$k =$_GET['k'];
$terms = explode(" ",$k);
//connect before calling mysql_real_escape_string
mysql_connect("localhost","","");
mysql_select_db("test");
$query ="SELECT id,title,author
FROM books WHERE";
foreach ($terms as $each){
$i++;
$each = '%' . $each . '%'; // add wildcard
$each = mysql_real_escape_string($each); // prevent sql injection
if($i==1)
$query .= " $column_name LIKE '$each' ";
else
$query .= " OR $column_name LIKE '$each' ";
}
echo 'QUERY: ' . $query;
$query = mysql_query($query) OR DIE(mysql_error());
//Code below is for using the relationships table assuming you have a column name id that
//references to the relationships table. Also, you should add a index on the column id.
$results = "";
while($row = mysql_fetch_array($query)) {
$results .= '<li>
'.$row['title'].' author: '.$row['author'].'
</li>';
}
$results = '<ul>' . $results . '</ul>';
echo $results;

Remove a "; from this line:
FROM books WHERE "; ";
You must declare $i
$i = 0;
To prevent sql injection you can use:
foreach ($terms as $each){
$i++;
$each = '%' . $each . '%'; // add wildcard
$each = mysql_real_escape_string($each); // prevent sql injection
if($i==1)
$query .= " $keywords LIKE '$each' ";
else
$query .= " OR $keywords LIKE '$each' ";
}
Also, ake sure the user cannot set the variable to a table that does not exist
Full Code
<?php
$i=0;
$column_name = 'title'; // column to search by
$k =$_GET['k'];
$terms = explode(" ",$k);
//connect before calling mysql_real_escape_string
mysql_connect("localhost","","");
mysql_select_db("test");
$query ="SELECT id,title,author
FROM books WHERE";
foreach ($terms as $each){
$i++;
$each = '%' . $each . '%'; // add wildcard
$each = mysql_real_escape_string($each); // prevent sql injection
if($i==1)
$query .= " $column_name LIKE '$each' ";
else
$query .= " OR $column_name LIKE '$each' ";
}
echo 'QUERY: ' . $query;
$query = mysql_query($query) OR DIE(mysql_error());
//Code below is for using the relationships table assuming you have a column name id that
//references to the relationships table. Also, you should add a index on the column id.
$results = "";
while($row = mysql_fetch_array($query)) {
$results .= '<li>
'.$row['title'].' author: '.$row['author'].'
</li>';
}
$results = '<ul>' . $ results . '</ul>';
echo $results;

Related

SQL update with PHP arrays

Let's say i have and array like this
$array= Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
Keys from this array are name of columns in table and values are value of columns which i need to update.
I want to update the table based on keys and values.
I am using ADODB
Please help me
try this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
$sql .= $key . " = " . $value . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
and of course the WHERE clause:
$sql .= " WHERE condition = value";
you will get the string:
UPDATE table SET id = 3, name = NAME, age = 12 WHERE condition = value
L.E: You might need to add apostrophes to strings so I have to change my code to something like this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= " WHERE condition = value";
which will produce this:
UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE condition = value
L.E 2: If you want the id column in your condition, the code becomes this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if($key == 'id'){
$sql_condition = " WHERE " . $key . " = " . $value;
continue;
}
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= $sql_condition;
which will produce this result:
UPDATE table SET name = 'NAME', age = 12 WHERE id = 3
Hope this helps! :D
foreach ($update_array as $key => $testimonials) {
$name = mysql_real_escape_string($testimonials->name);
$content = mysql_real_escape_string($testimonials->content);
$id = intval($testimonials->id);
$sql = "UPDATE testimonials SET name='$name', content='$content' WHERE id=$id";
$result = mysql_query($sql);
if ($result === FALSE) {
die(mysql_error());
}
}
Source : https://stackoverflow.com/a/7884331/3793639
Other sources to check.
PHP SQL Update array and Simple UPDATE MySQl table from php array
You could use something like this for achieving that:
foreach($values as $value) {
if(!key_exists($value, $item)) {
return false;
}
$table->{$value} = $items[$value];
}
Assuming that the key index is always id and that adodb can use named placeholders you could do this:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$set = array();
$data = array();
while(list($key,$value)=each($array)) {
$data[':'.$key] = $value;
if($key!='id') {
$set[] = $key . ' = :' . $key;
// if no placeholders use $set[] = $key . " = '" . database_escape_function($value) . "'";
}
}
$sql = "UPDATE table SET ".implode($set, ',')." WHERE id=:id";
//$data is now Array(':id'=>'3', ':name'=>'NAME', ':age'=>'12');
//$sql is now "UPDATE table SET name=:name, age=:age WHERE id=:id";
$stmt = $DB->Prepare($sql);
$stmt = $DB->Execute($stmt, $data);
This is probably the shortest and easiest for you, you can also use something like this to achieve it:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$sql = "UPDATE table SET ";
$sql .= implode(', ', array_map(function($key, $value){
return is_numeric($value) ? "{$key} = {$value}" : "{$key} = '". mysql_real_escape_string($value). "'";
}, array_keys($array), $array));
$sql .= " WHERE id = 123";
// Result : UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE id = 123

php Search engine the keywords are not working

When i would search for the keywords that i have specified in my database it will return everything from my database not just the corresponding links that have the keywords attached to the link. here is my code
<?php
$q = $_GET['q'];
$terms = explode(" ", $q);
$query = "SELECT * FROM search ";
foreach ($terms as $each){
$i=0;
$i++;
if ($i == 1)
$query .= "keywords LIKE '%$each%' ";
else
$query .= "OR keywords LIKE '%$each%' ";
}
//connect
mysql_connect("localhost", "root", "");
mysql_select_db("search");
$query = mysql_query("SELECT * FROM search");
$numrows = mysql_num_rows($query);
if ($numrows > 0){
while($row = mysql_fetch_assoc($query)){
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo "<h3><a href='$link'>$title</a></h3><h4>$link</h4>$description<br /><br />";
}
}
else
echo "<b>No Results Found</b><br><br>Suggestions:<br>
Make sure all words are spelled correctly.<br>
Try different keywords.<br>
Try more general keywords.";
//disconnect
mysql_close();
?>
<?php
$q = $_GET['q'];
$terms = explode(" ", $q);
//connect
mysql_connect("localhost", "root", "");
mysql_select_db("search");
$query = "SELECT * FROM search ";
$i=1;
foreach ($terms as $each){
if ($i == 1) {
$query .= "WHERE ";
$query .= "keywords LIKE '" . mysql_real_escape_string("%" . $each . "%") . "' ";
} else {
$query .= "OR keywords LIKE '" . mysql_real_escape_string("%" . $each . "%") . "' ";
}
$i++;
}
$query = mysql_query($query);
$numrows = mysql_num_rows($query);
if ($numrows > 0){
while($row = mysql_fetch_assoc($query)){
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo "<h3><a href='$link'>$title</a></h3><h4>$link</h4>$description<br /><br />";
}
} else {
echo "<b>No Results Found</b><br><br>Suggestions:<br>
Make sure all words are spelled correctly.<br>
Try different keywords.<br>
Try more general keywords.";
}
//disconnect
mysql_close();
?>
Fixes:
1) Removed second $query that was being defined. It selected all rows.
2) Moved initial $i declaration. It was being set back to 0 each loop.
3) Added WHERE
4) Moved $i++ after the if statement and set initial $i to 1.
5) Added mysql_real_escape_string so that data is escaped properly.
Recommendations:
I highly recommend taking a look at MySQLi (http://us2.php.net/mysqli) or PDO (http://us3.php.net/pdo)
Please let me know if this works or if you need further assistance.
A first sight, i see a couple of errors.
$i=0;
$i++;
if ($i == 1)
$i Will ALWAYS be one are.
you might want to move $i = 0; BEFORE the foreach
$query = mysql_query("SELECT * FROM search");
You build a query, but in the end you're not using it. you probably want to do : $query = mysql_query($query); instead. ( and also for code clarity using a different variable name for the output ? ) .
mysql_query is deprecated. Useless you're in a hurry, check PDO
First, you're missing the WHERE keyword before the conditions. So it should be:
foreach ($terms as $i => $each){
$each = mysql_real_escape_string($each); // Prevent SQL injection
if ($i == 0)
$query .= "WHERE keywords LIKE '%$each%' ";
else
$query .= "OR keywords LIKE '%$each%' ";
}
You don't need to increment your own counter variable, you can use the array indexes from $terms.
Second, after all that work to create $query, you're not using it. You wrote:
$query = mysql_query("SELECT * FROM search");
That should be:
$query = mysql_query($query);
BTW, it's generally a bad idea to reuse variables like that, it gets confusing when you use the same variable for different things. I suggest you call the second $query something like $results.
Change this line
$query .= "keywords LIKE '%$each%' ";
By
$query .= " Where keywords LIKE '%$each%' ";
And also cnhange this line
$query = mysql_query("SELECT * FROM search");
By
$query = mysql_query($query);

How to limit the amount of search results on each page like Google?

I am trying to limit the amount of search results on each page like Google does. I am also using a SQL database to organize my keywords and everything. Here is my code
<?php
$q = $_GET['q'];
$terms = explode(" ", $q);
//connect
mysql_connect("localhost", "root", "") or die ("Could Not Connect");
mysql_select_db("search") or die ("Could Not Connect To database");
$query = "SELECT * FROM search ";
$i=1;
foreach ($terms as $each){
if ($i == 1) {
$query .= "WHERE ";
$query .= "keywords LIKE '" . mysql_real_escape_string("%" . $each . "%") . "' ";
} else {
$query .= "OR keywords LIKE '" . mysql_real_escape_string("%" . $each . "%") . "' ";
}
$i++;
}
$query = mysql_query($query);
$numrows = mysql_num_rows($query);
if ($numrows > 0)
{
while($row = mysql_fetch_assoc($query))
{
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo "<h3><a href='$link'>$title</a></h3><h4>$link</h4>$description<br /><br />";
}
} else {
echo "<b>No Results Found</b><br><br>Suggestions:<br>
Make sure all words are spelled correctly.<br>
Try different keywords.<br>
Try more general keywords.";
}
//disconnect
mysql_close();
?>
After your foreach ($terms as $each){} you need to add an ORDER BY and LIMIT to the query, like so:
$query .= "ORDER BY keywords LIMIT 0, 10";
That will give you the first 10 results. Alter the LIMIT vars as needed. The first number is the offset (zero based, aka first result is 0, sixth result is 5) and the second number is the number of rows to return.
The ORDER BY helps with consistent results. You don't need it, but sometimes results can be weird.
See this question for more info if you need it.

While Loop in SQL query

I'm not sure why this SQL query is not working.
I'm new to SQL/PHP so please forgive.
mysql_query("
SELECT * FROM table WHERE name = " . "'Bob'" .
while($i < $size)
{
$i++;
echo "OR name = '";
echo $array[$i] . "'";
} .
" ORDER BY id DESC "
);
Dreamweaver gives me an error saying it is not correct but does not tell me what is wrong.
Is it possible to put a while loop into an sql command?
you can not use a while in a string
$where = "";
if ($size > 0)
{
$where .= " WHERE ";
}
while($i < $size)
{
$i++;
$where .= "OR name = '".$array[$i]."' ";
}
$query = "SELECT * FROM table WHERE name = '".Bob."'".$where." ORDER BY id DESC";
mysql_query($query);
(this code is not tested)
Woot !
You just can't write this :D
Build your OR condition before writing the query and it will be just fine:
$myCondition = " ";
while($i < $size) {
$i++;
$myCondition .= "OR name = '" . $array[$i] . "'";
}
mysql_query(
"SELECT * FROM table WHERE name = " . "'Bob'" . $myCondition . " ORDER BY id DESC ");
echo is to output the string, and it won't return the string.
Something like $str = "aaa" . echo "bbb"; won't work.
For you case, use IN will be better.
foreach ($array as &$name) {
$name = "'".mysql_real_escape_string($name)."'";
}
mysql_query("SELECT * FROM table WHERE name IN (".implode(',', $array).")");
Or use
"SELECT * FROM table WHERE name IN(".implode( ',', $array).")";

SQL Multiple WHERE Clause Problem

I'm attempting the modify this Modx Snippet so that it will accept multiple values being returned from the db instead of the default one.
tvTags, by default, was only meant to be set to one variable. I modified it a bit so that it's exploded into a list of variables. I'd like to query the database for each of these variables and return the tags associated with each. However, I'm having difficulty as I'm fairly new to SQL and PHP.
I plugged in $region and it works, but I'm not really sure how to add in more WHERE clauses for the $countries variable.
Thanks for your help!
if (!function_exists('getTags')) {
function getTags($cIDs, $tvTags, $days) {
global $modx, $parent;
$docTags = array ();
$baspath= $modx->config["base_path"] . "manager/includes";
include_once $baspath . "/tmplvars.format.inc.php";
include_once $baspath . "/tmplvars.commands.inc.php";
if ($days > 0) {
$pub_date = mktime() - $days*24*60*60;
} else {
$pub_date = 0;
}
list($region, $countries) = explode(",", $tvTags);
$tb1 = $modx->getFullTableName("site_tmplvar_contentvalues");
$tb2 = $modx->getFullTableName("site_tmplvars");
$tb_content = $modx->getFullTableName("site_content");
$query = "SELECT stv.name,stc.tmplvarid,stc.contentid,stv.type,stv.display,stv.display_params,stc.value";
$query .= " FROM ".$tb1." stc LEFT JOIN ".$tb2." stv ON stv.id=stc.tmplvarid ";
$query .= " LEFT JOIN $tb_content tb_content ON stc.contentid=tb_content.id ";
$query .= " WHERE stv.name='".$region."' AND stc.contentid IN (".implode($cIDs,",").") ";
$query .= " AND tb_content.pub_date >= '$pub_date' ";
$query .= " AND tb_content.published = 1 ";
$query .= " ORDER BY stc.contentid ASC;";
$rs = $modx->db->query($query);
$tot = $modx->db->getRecordCount($rs);
$resourceArray = array();
for($i=0;$i<$tot;$i++) {
$row = #$modx->fetchRow($rs);
$docTags[$row['contentid']]['tags'] = getTVDisplayFormat($row['name'], $row['value'], $row['display'], $row['display_params'], $row['type'],$row['contentid']);
}
if ($tot != count($cIDs)) {
$query = "SELECT name,type,display,display_params,default_text";
$query .= " FROM $tb2";
$query .= " WHERE name='".$region."' LIMIT 1";
$rs = $modx->db->query($query);
$row = #$modx->fetchRow($rs);
$defaultOutput = getTVDisplayFormat($row['name'], $row['default_text'], $row['display'], $row['display_params'], $row['type'],$row['contentid']);
foreach ($cIDs as $id) {
if (!isset($docTags[$id]['tags'])) {
$docTags[$id]['tags'] = $defaultOutput;
}
}
}
return $docTags;
}
}
You don't add in more WHERE clauses, you use ANDs and ORs in the already existing where clause. I would say after the line $query .= " WHERE stv.name = '".$region... you put in
foreach ($countries as $country)
{
$query .= "OR stv.name = '{$country}', ";
}
but I don't know how you want the query to work.

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