SQL update with PHP arrays - php

Question

Let's say i have and array like this
$array= Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
Keys from this array are name of columns in table and values are value of columns which i need to update.
I want to update the table based on keys and values.
I am using ADODB
Please help me

Answer 1

try this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
$sql .= $key . " = " . $value . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
and of course the WHERE clause:
$sql .= " WHERE condition = value";
you will get the string:
UPDATE table SET id = 3, name = NAME, age = 12 WHERE condition = value
L.E: You might need to add apostrophes to strings so I have to change my code to something like this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= " WHERE condition = value";
which will produce this:
UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE condition = value
L.E 2: If you want the id column in your condition, the code becomes this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if($key == 'id'){
$sql_condition = " WHERE " . $key . " = " . $value;
continue;
}
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= $sql_condition;
which will produce this result:
UPDATE table SET name = 'NAME', age = 12 WHERE id = 3
Hope this helps! :D

Answer 2

foreach ($update_array as $key => $testimonials) {
$name = mysql_real_escape_string($testimonials->name);
$content = mysql_real_escape_string($testimonials->content);
$id = intval($testimonials->id);
$sql = "UPDATE testimonials SET name='$name', content='$content' WHERE id=$id";
$result = mysql_query($sql);
if ($result === FALSE) {
die(mysql_error());
}
}
Source : https://stackoverflow.com/a/7884331/3793639
Other sources to check.
PHP SQL Update array and Simple UPDATE MySQl table from php array

Answer 3

You could use something like this for achieving that:
foreach($values as $value) {
if(!key_exists($value, $item)) {
return false;
}
$table->{$value} = $items[$value];
}

Answer 4

Assuming that the key index is always id and that adodb can use named placeholders you could do this:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$set = array();
$data = array();
while(list($key,$value)=each($array)) {
$data[':'.$key] = $value;
if($key!='id') {
$set[] = $key . ' = :' . $key;
// if no placeholders use $set[] = $key . " = '" . database_escape_function($value) . "'";
}
}
$sql = "UPDATE table SET ".implode($set, ',')." WHERE id=:id";
//$data is now Array(':id'=>'3', ':name'=>'NAME', ':age'=>'12');
//$sql is now "UPDATE table SET name=:name, age=:age WHERE id=:id";
$stmt = $DB->Prepare($sql);
$stmt = $DB->Execute($stmt, $data);

Answer 5

This is probably the shortest and easiest for you, you can also use something like this to achieve it:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$sql = "UPDATE table SET ";
$sql .= implode(', ', array_map(function($key, $value){
return is_numeric($value) ? "{$key} = {$value}" : "{$key} = '". mysql_real_escape_string($value). "'";
}, array_keys($array), $array));
$sql .= " WHERE id = 123";
// Result : UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE id = 123