implode to fix update sql - php

I have this function
function updateDbRecord($db, $table, $carry, $carryUrl) {
mysql_select_db($db) or die("Could not select database. " . mysql_error());
$resultInsert = mysql_query("SHOW COLUMNS FROM " . $table . " WHERE Field NOT IN ('id')");
$fieldnames=array();
if (mysql_num_rows($resultInsert) > 0) {
while ($row = mysql_fetch_array($resultInsert)) {
$fieldnames[] = $row['Field'];
$arr = array_intersect_key( $_POST, array_flip($fieldnames) ); #check if value is null otherwise do not INSERT
}
}
$set = "";
foreach($arr as $key => $v) {
$val = is_numeric($v) ? $v : "'" . $v . "'";
$set .= $key . '=' . $val . ', ';
}
$sql = sprintf("UPDATE %s SET %s WHERE id='%s'", $table, $set, $_POST['id']);
mysql_query($sql);
if ($carry == 'yes') {
redirect($carryUrl.'?id='.$_REQUEST['id']);
} else { echo "Done!"; }
echo $sql;
}
It outputs for example: UPDATE projects SET project_name='123', project_bold='123', project_content='123', WHERE id='12'
The last comma before where is preventing it from working. Is there a way of avoiding this? Im aware of the function implode, however I am not sure how to employ it in this situation.

Yes,
$sql = substr($sql,'',-1);

I would use
$sql = rtrim($sql, ',');
Either that or instead of appending to a string, append to an array and use implode.

function updateDbRecord($db, $table, $carry, $carryUrl) {
mysql_select_db($db) or die("Could not select database. " . mysql_error());
$resultInsert = mysql_query("SHOW COLUMNS FROM " . $table . " WHERE Field NOT IN ('id')");
$fieldnames=array();
if (mysql_num_rows($resultInsert) > 0) {
while ($row = mysql_fetch_array($resultInsert)) {
$fieldnames[] = $row['Field'];
$array = array_intersect_key( $_POST, array_flip($fieldnames) ); #check if value is null otherwise do not INSERT
}
}
foreach ($array as $key => $value) {
$value = mysql_real_escape_string($value); // this is dedicated to #Jon
$value = "'$value'";
$updates[] = "$key = $value";
}
$implodeArray = implode(', ', $updates);
$sql = sprintf("UPDATE %s SET %s WHERE id='%s'", $table, $implodeArray, $_POST['id']);
mysql_query($sql);

Related

How to print PDO CRUD Statements and Values of bindParams -PHP PDO

I am new to PDO PHP. I have created a post data function in order to achieve the insertion functionality. Here is my code.
public function PostData($conn, $table, $data)
{
try {
$query = "INSERT INTO " . $table . "(";
$arraylen = count($data);
$keyloopcount = 0;
foreach ($data as $key => $values) {
$query .= $key;
if ($keyloopcount != $arraylen - 1) {
$query .= ",";
}
$keyloopcount++;
}
$valloopcount = 0;
$query .= ") VALUES (";
foreach ($data as $key => $values) {
$query .= "':" . $key . "'";
if ($valloopcount != $arraylen - 1) {
$query .= ",";
}
$valloopcount++;
}
$query .= ")";
$stmt = $conn->prepare($query);
foreach ($data as $key => &$values) {
$stmt->bindParam(':'.$key, $values, PDO::PARAM_STR);
}
if ($stmt->execute()) {
$stmt->debugDumpParams();
echo "me";
} else {
echo "die";
}
} catch (PDOException $ex) {
echo $ex->getMessage();
}
}
When I execute this query. It doesn't show any exceptions. but when I look into my Database. It shows inserted records as follows.
I am wondering if there is a way I can debug what are the values in the binded params. I have also looked for $stmt->debugDumpParams(); as shown in the code. But it doesn't shows the values of params.
Need Guidance. TIA.
I sorted it out. I was making a silly mistake. The solution was so simple and easy.
Solution
The problem was lying in the part of the code.
foreach ($data as $key => $values) {
$query .= "':" . $key . "'";
if ($valloopcount != $arraylen - 1) {
$query .= ",";
}
$valloopcount++;
}
Changed the code to:
foreach ($data as $key => $values) {
$query .= ":" . $key;
if ($valloopcount != $arraylen - 1) {
$query .= ",";
}
$valloopcount++;
}
Resultant Query Before Amendment:
INSERT INTO cmp_categories(cat_name,cat_slug,cat_desc) VALUES (':cat_name',':cat_slug',':cat_desc')
Resultant Query AfterAmendment:
INSERT INTO cmp_categories(cat_name,cat_slug,cat_desc) VALUES (:cat_name,:cat_slug,:cat_desc)
More Clearly,
Removed ' from VALUES clause. ':cat_desc' => :cat_desc

how to check success on insert using OCI

I have the following code but i am not sure how to check if insert is success. execute returns resource id. I would like to check if success and return all errors on fail.
public function persist()
{
$update = FALSE;
if(!is_array($this->tablePrimaryKey)) {
if(!empty($this->fieldVals[$this->tablePrimaryKey])) {
$update = true;
}
}
if ($update) {
$sql = "UPDATE " . $this->tableName . " SET ";
$binds = [];
foreach ($this->fieldVals as $key=>$val) {
if ($key != $this->tablePrimaryKey) {
if(in_array($key, $this->DATE_IDS)) {
$sql .= '"' . strtoupper($key) . '" = sysdate,';
} else {
$bind = 't_' . $key;
$binds[$bind] = $val;
$sql .= '"' . strtoupper($key) . '" = :' . $bind . ',';
}
}
}
$sql = substr($sql,0,-1);
$sql .= " WHERE " . $this->tablePrimaryKey . " = '" . $this->fieldVals[$this->tablePrimaryKey] ."'";
} else {
$binds = $fields = $date_fields = [];
if(!empty($this->tablePrimaryKey) && !is_array($this->tablePrimaryKey)) {
$this->fieldVals[$this->tablePrimaryKey] = $this->generateNewPrimaryKey();
}
foreach ($this->fieldVals as $key=>$val) {
$bind = ':t_' . $key;
if (in_array($key, $this->DATE_IDS)) {
$date_fields[] = strtoupper($key);
} else {
$binds[$bind] = $val;
$fields[] = strtoupper($key);
}
}
$sql = 'INSERT INTO ' . $this->tableName . '("' . implode('","', $fields);
if(count($date_fields) >0) {
$sql .= '","';
$sql .= implode('","', $date_fields);
}
$sql.='") VALUES (' . implode(',', array_keys($binds));
if(count($date_fields) >0) {
$cnt=0;
foreach($date_fields as $date) {
$cnt++;
if(preg_match('/NULL/i', $this->fieldVals[strtolower($date)], $result)) {
$sql .= ",NULL";
} elseif(isset($this->fieldVals[strtolower($date)])) {
$sql .= ",TO_DATE('" . (new DateTime($this->fieldVals[strtolower($date)]))->format("Y-M-d H:i:s") . "', 'yyyy/mm/dd hh24:mi:ss')";
} else {
$sql .= ",sysdate";
}
}
}
$sql .= ')';
}
$this->oiDb->parse($sql, $binds);
return $this->oiDb->execute();
}
I run $result = $oiRequests->hydrate($reportingRequest)->persist();. $reportingRequest is key,value pair of columns/values. $result contains resource id. $oiRequests is my model.
I have tried
$num_rows = oci_fetch_assoc ($result);
print_r($num_rows);
returns
Warning: oci_fetch_assoc(): ORA-24374: define not done before fetch or execute and fetch in /var/SP/oiadm/docroot/dev/uddins/requestportal/requestportal_ajax.php on line 65
Most of the OCI functions return false on error. This means you can do a simple check on the return value and, if it's false, call oci_error().
For the specific case of checking if an INSERT statement worked you can reference the example code for oci_commit(). The relevant part of that example is duplicated here:
// The OCI_NO_AUTO_COMMIT flag tells Oracle not to commit the INSERT immediately
// Use OCI_DEFAULT as the flag for PHP <= 5.3.1. The two flags are equivalent
$r = oci_execute($stid, OCI_NO_AUTO_COMMIT);
if (!$r) {
$e = oci_error($stid);
trigger_error(htmlentities($e['message']), E_USER_ERROR);
}

PHP MySQL not updating fields with values containing decimals

When I try to update a table with the following query string using PHP:
UPDATE card_designs SET `card_price` = '6180',
`annual` = '257.3',
`initial_payment` = '6512.3'
WHERE card_id = '1'
It does not update correctly. card_price value is put in correctly. However annual comes in as 0 and initial_payment comes in as 6255.00.
It doesn't matter if the fields are a VARCHAR, DECIMAL, or DOUBLE. If the value has a decimal it's all messed up.
Also, if I run the above query in a SQL client, the query works fine.
Here is the PHP code that constructs the query. I'm using mysqli:
$sql = "UPDATE ". $table ." SET ";
$updates = array();
foreach ($variables as $field => $value) {
array_push($updates, "`$field` = '$value'");
}
$sql .= implode(', ', $updates);
//Add the $where clauses as needed
if (!empty($where)) {
foreach ($where as $field => $value) {
$value = $value;
$clause[] = "$field = '$value'";
}
$sql .= ' WHERE '. implode(' AND ', $clause);
}
if (!empty( $limit)) {
$sql .= ' LIMIT '. $limit;
}
$query = $this->mysqli->query($sql);
I assume your database table fields datatype is Decimal(9,2)
// Prepare query
$table = "card_designs";
$variables = array(
"card_price" => "6180.00",
"annual" => "257.3",
"initial_payment" => "6512.3"
);
$where = array(
"id" => "1"
);
$sql = "UPDATE ". $table ." SET ";
$updates = array();
foreach ($variables as $field => $value)
{
array_push($updates, "$field = $value");
}
$sql .= implode(', ', $updates);
//Add the $where clauses as needed
if (!empty($where))
{
foreach ($where as $field => $value)
{
$value = $value;
$clause[] = "$field = $value";
}
$sql .= ' WHERE '. implode(' AND ', $clause);
}
if (!empty( $limit))
{
$sql .= ' LIMIT '. $limit;
}
// Run query
if ($mysqli->query($sql))
{
echo "Record updated successfully";
}

SQL update with PHP arrays

Let's say i have and array like this
$array= Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
Keys from this array are name of columns in table and values are value of columns which i need to update.
I want to update the table based on keys and values.
I am using ADODB
Please help me
try this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
$sql .= $key . " = " . $value . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
and of course the WHERE clause:
$sql .= " WHERE condition = value";
you will get the string:
UPDATE table SET id = 3, name = NAME, age = 12 WHERE condition = value
L.E: You might need to add apostrophes to strings so I have to change my code to something like this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= " WHERE condition = value";
which will produce this:
UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE condition = value
L.E 2: If you want the id column in your condition, the code becomes this:
$sql = "UPDATE table SET ";
foreach($array as $key=>$value) {
if($key == 'id'){
$sql_condition = " WHERE " . $key . " = " . $value;
continue;
}
if(is_numeric($value))
$sql .= $key . " = " . $value . ", ";
else
$sql .= $key . " = " . "'" . $value . "'" . ", ";
}
$sql = trim($sql, ' '); // first trim last space
$sql = trim($sql, ','); // then trim trailing and prefixing commas
$sql .= $sql_condition;
which will produce this result:
UPDATE table SET name = 'NAME', age = 12 WHERE id = 3
Hope this helps! :D
foreach ($update_array as $key => $testimonials) {
$name = mysql_real_escape_string($testimonials->name);
$content = mysql_real_escape_string($testimonials->content);
$id = intval($testimonials->id);
$sql = "UPDATE testimonials SET name='$name', content='$content' WHERE id=$id";
$result = mysql_query($sql);
if ($result === FALSE) {
die(mysql_error());
}
}
Source : https://stackoverflow.com/a/7884331/3793639
Other sources to check.
PHP SQL Update array and Simple UPDATE MySQl table from php array
You could use something like this for achieving that:
foreach($values as $value) {
if(!key_exists($value, $item)) {
return false;
}
$table->{$value} = $items[$value];
}
Assuming that the key index is always id and that adodb can use named placeholders you could do this:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$set = array();
$data = array();
while(list($key,$value)=each($array)) {
$data[':'.$key] = $value;
if($key!='id') {
$set[] = $key . ' = :' . $key;
// if no placeholders use $set[] = $key . " = '" . database_escape_function($value) . "'";
}
}
$sql = "UPDATE table SET ".implode($set, ',')." WHERE id=:id";
//$data is now Array(':id'=>'3', ':name'=>'NAME', ':age'=>'12');
//$sql is now "UPDATE table SET name=:name, age=:age WHERE id=:id";
$stmt = $DB->Prepare($sql);
$stmt = $DB->Execute($stmt, $data);
This is probably the shortest and easiest for you, you can also use something like this to achieve it:
$array = Array('id'=>'3', 'name'=>'NAME', 'age'=>'12');
$sql = "UPDATE table SET ";
$sql .= implode(', ', array_map(function($key, $value){
return is_numeric($value) ? "{$key} = {$value}" : "{$key} = '". mysql_real_escape_string($value). "'";
}, array_keys($array), $array));
$sql .= " WHERE id = 123";
// Result : UPDATE table SET id = 3, name = 'NAME', age = 12 WHERE id = 123

creating a function to do standard DELETEs using prepared statments and php

I am currently going through a nettuts.com tutorial on building a twitter clone and there they have a function for deleting rows from a database and they are using the query method but i tried converting the function to a prepared statement.However I get the Invalid parameter number: parameter was not defined error.Here is the code for the function
public function delete($table, $arr){
$query = "DELETE FROM " . $table;
$pref = "WHERE ";
foreach ($arr as $key => $value) {
$query .= $pref. $key . " = " . ":" . $key;
$pref = "AND ";
}
$query .= ";";
$result = $this->db->prepare($query);
$result->execute($arr);
}
$connect = new Model();
$connect->delete("ribbits", array("user_id" => 2,
"ribbit" => "trial ribbit"
));
can someone please tell me what I am doing wrong?Thank you!
When you pass your array to ->execute(), the keys need to have the : character before them (just like they appear in the SQL query).
So, in your delete function, build the SQL query like this:
public function delete($table, $arr){
$keys = array();
$values = array();
foreach($arr as $key => $value){
$keys[] = $key . " = :" . $key;
$values[":".$key] = $value;
}
$query = "DELETE FROM " . $table . " WHERE " . implode(" AND ", $keys);
$result = $this->db->prepare($query);
$result->execute($values);
}

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