PHP first 3 then break and continue again? - php

Question

I'm trying to sort everything out using array & loops
lets say this is an array,
$arr = array('One','Two','Three','Four','Five','Six');
i want to select first three of them to be used as
$arr[0], $arr[1] and $arr[2]
this ends up with one,two,three
i want to use the same for next 3..
something to break it and use the same 0 1 2 index again to return second three
here's an example to explain more,
$arr = array('One','Two','Three','Four','Five','Six');
echo $arr[0].$arr[1].$arr[2]; // OneTwoThree
break; // < ??
echo $arr[0].$arr[1].$arr[2]; // FourFiveSix
also, i want to use it with foreach loop
$arr = array('One','Two','Three','Four','Five','Six');
foreach($arr as $num){
echo $num; // OneTwoThree
if($something == 3){ // < ??
break; // < ??
}
echo $num; // FourFiveSix
}
and what im trying to do is using each three arrays of the array to use them later

Answer 1

Use array_chunk and loop over the result:
foreach(array_chunk($arr, 3) as $a) {
echo $a[0], $a[1], $a[2];
}
Here it is with added linebreaks:
foreach(array_chunk($arr, 3) as $a) {
echo $a[0], $a[1], $a[2], "<br>\n";
}
Note: The last element may have less than three elements! A possible fix for this is to use implode to concatenate the elements:
foreach(array_chunk($arr, 3) as $a) {
echo implode('', $a), "<br>\n";
}

Answer 2

Edit: array_chunk() is a lot more sensible...early mornings
<?php
$arr = array('One','Two','Three','Four','Five','Six');
for($i = 0, $i < count($arr); ++$i)
{
if( ! ($i + 1) % 3)
{
continue;
}
echo $arr[$i - 2] . $arr[$i - 1] . $arr[$i]
}