I have a multidimentional array of 5 items and I want that my loop would compare it like:
1 -> 2, 1 -> 3, 1 -> 4, 1 -> 5, 2->1, 2->3, 2->4, 2->5......// so on and 5 -> 4 in the end.
The problem is that after my array $i value matches 1 and $j value matches 3, the unset is done and the $i value becomes 2 (which is correct) and $j value becomes 4 instead of 3. Could someone tell me why and what I'm doing wrong?
My loop is:
for ($i = 0; $i <= count($myArray); $i++) {
for ($j = $i+1; $j <= count($myArray); $j++) {
if (
// condition 1
&& // condition 2
) {
unset($myArray[$i]);
$i++;
}
}
}
I think that's the problem is when you unset the element in the array, you increment the counter of the loop $i. In this way, the elements of the array that are not configured are removed, this empty array position will be maintained, it will not be reordered, you will have to do it manually or using array_values method.
In the last tour of the array, it will break because you are comparing the number of array elements as equal. You must use index < count($array)
The code would be like this:
for ($i = 0; $i < count($myArray); $i++) {
for ($j = $i+1; $j < count($myArray); $j++) {
if (
// condition 1
&& // condition 2
) {
unset($myArray[$i]);
// $i++;
}
}
}
try something like this
for ($i = 0; $i <= count($myArray); $i++) {
for ($j = 0; $j <= count($myArray); $j++) {
if ($j!=$i)
{
if (
// condition 1
&& // condition 2
) {
unset($myArray[$i]);
$i++;
}
}
}
}
$temp = $myArray;
for ($i = 0; $i <= count($myArray); $i++)
{
for ($j = $i + 1; $j <= count($myArray); $j++)
{
if (
// condition 1
&& // condition 2
)
{
unset($temp[$i]);
$i++;
}
}
}
print_r($temp);
Your result is in $temp. So here indexes wont get hampered, you actually are applying all operation on $temp and normally traversing $myArray.
To be honest, I do not know why nobody has yet advise to use nested foreach, since you all noticed there was a problem with array size.
foreach ($numbers as $number_horizontal_parsing) {
foreach ($numbers as $number_vertical_parsing) {
if ($number_horizontal_parsing != $number_vertical_parsing) {
//do your stuff in your case it seems you want to compare both variables
}
}
}
I'm new on PHP and I want to find the 0 and replace with the number that is missed, inside the inner array, on a multidimensional array. If the inner array has more than two 0's, it will be ignored and goes to the next.
$list = array("First"=>array(0,1,2,3,0,5,6,7,8,9),
"Second"=>array(0,1,2,3,4,5,6,7,8,9),
"Third"=>array(0,1,2,3,4,5,0,0,8,9),
"Fourth"=>array(0,1,2,3,4,5,6,7,8,0),
"Fifth"=>array(0,1,2,3,4,5,0,7,8,9),
"Sixth"=>array(0,0,0,3,4,5,6,0,0,0),
"Seventh"=>array(0,1,2,3,0,0,6,7,8,9),
"Eighth"=>array(0,1,2,3,4,5,0,7,8,9),
"Ninth"=>array(0,1,2,3,4,0,6,7,8,9),
"Tenth"=>array(0,0,2,3,4,5,6,7,8,9));
$countZero = 0;
foreach($list as $lvl) {
foreach($lvl as $ind => $val) {
if($countZero = array_count_values($lvl[$val] === 0))
$list[$ind][$val] = 45 - array_sum($ind);
echo $count;
}
}
I want all inner arrays, that have two 0's get only one, to have all numbers in sequence i.e.
"First"=>array(0,1,2,3,4,5,6,7,8,9);
Please, help me.
I tried this code below, trying to finde the 0's.
$counts = 0;
$newArr = array();
foreach($list as $lvl) {
if(is_array($lvl)) {
for($i = 0; $i < count($lvl) - 1; $i++) {
if(($lvl[$i] == 0) < 2){
$counts++;
$newArr[$i] = 45 - array_sum($lvl);
}
}
}
}
print_r($newArr);
This is a solution using array_walk:
array_walk($list,
function(&$numbers) {
$zeroIndex = 0;
foreach($numbers as $i => $number) {
if( $number === 0 ) {
if( $zeroIndex > 0 ) {
return;
}
$zeroIndex = $i;
}
}
$numbers[$zeroIndex] = $zeroIndex;
});
You don't need to count all the zeros. You just need to check if there are less than 3 zeros.
I'm saving the index (position) of zero ($zeroIndex = $i).
I'm assuming that the first number is always a zero ($zeroIndex = 0).
The index of the second zero is greater than zero. If I find a zero when the index of the last found zero is greater than zero (if( $zeroIndex > 0 )), this means that there are more than two zeros.
In fact,here is what I've done and worked.
$list = array(array(1,2,3,0,5,6,7,8,9),
array(1,2,3,4,5,6,7,8,9),
array(1,2,3,4,5,0,0,8,9),
array(1,2,3,4,5,6,7,8,0),
array(1,2,3,4,5,0,7,8,9),
array(0,0,3,4,5,6,0,0,0),
array(1,2,3,0,0,6,7,8,9),
array(1,2,3,4,5,0,7,8,9),
array(1,2,3,4,0,6,7,8,9));
for($l = 0; $l < count($list); $l++)
{
$total = 0;
$countZ = 0;
for($i=0; $i < 9; $i++)
{
if($list[$l][$i] == 0)
{
$countZ++;
$indexZero = $i;
}
$total += $list[$l][$i];
if($countZ > 1) {
break;
}
}
$list[$l][$indexZero] = 45 - $total;
}
print_r($list);
TY all.
I have an array that can have any number of items inside it, and I need to grab the values from them at a certain pattern.
It's quite hard to explain my exact problem, but here is the kind of pattern I need to grab the values:
No
Yes
No
No
No
Yes
No
No
No
Yes
No
No
I have the following foreach() loop which is similar to what I need:
$count = 1;
foreach($_POST['input_7'] as $val) {
if ($count % 2 == 0) {
echo $val;
echo '<br>';
}
$count ++;
}
However, this will only pick up on the array items that are 'even', not in the kind of pattern that I need exactly.
Is it possible for me to amend my loop to match that what I need?
You can do this much simpler with a for loop where you set the start to 1 (the second value) and add 4 after each iteration:
for ($i = 1; $i < count($_POST['input_7']); $i += 4) {
echo $_POST['input_7'][$i] . '<br />';
}
Example:
<?php
$array = array(
'foo1', 'foo2', 'foo3', 'foo4', 'foo5',
'foo6', 'foo7', 'foo8', 'foo9', 'foo10',
'foo11', 'foo12', 'foo13', 'foo14', 'foo15'
);
for ($i = 1; $i < count($array); $i += 4) {
echo $array[$i] . '<br />';
}
?>
Output:
foo2foo6foo10foo14
DEMO
Try this:
$count = 3;
foreach($_POST['input_7'] as $val) {
if ($count % 4 == 0) {
echo $val;
echo '<br>';
}
$count ++;
}
I have an array in php, and I want to print the elements of the array, 15 at a time, from (n-15). Like, if I have 100 elements in an array, I want to print it 85-100,70-84,55-70,, etc.,
I've tried the loop
for( $j = sizeof($fields)-16; $j < sizeof($fields); ) {
for ( $i = $j ; $i < $i+16 ; $i++ ) {
echo $fields[$i];
echo "<br>";
}
$j=$j-16;
}
but, this prints only the first iternation, i.e 85-100, and goes into an infinite loop.
Where am i going wrong?
Help!
foreach (array_reverse(array_chunk($fields, 15)) as $chunk) {
foreach ($chunk as $field) {
echo $field . '<br />';
}
}
In PHP 5.3, you can do this:
<?php
$fields = range(1, 100);
foreach (array_chunk(array_reverse($fields, true), 15, true) as $i => $chunk) {
echo 'Group ' . $i . ":<br/>\n";
$chunk_rev = array_reverse($chunk, true);
array_walk($chunk_rev, function($value) {
echo "$value<br/>\n";
});
}
See the demo.
Think about the loop termination condition.
If $j is being decremented and $j starts off lower than the comparison value, $j will never be greater than the comparison value, so the loop will never terminate.
Here's the issue:
I retrieve the following data string from my database:
$row->exceptions = '1,2,3';
After explode I need the below code to check each one of the exploded pieces
$exceptions = explode(",", $row->exceptions);
//result is
//[0] => 1
//[1] => 2
//[2] => 3
for ($i = 0; $i <= $row->frequency; $i++) {
if ($exceptions[] == $i) {
continue;
} else {
//do something else
}
}
How can I make $exceptions[] loop through all keys from the exploded array so it evaluates if ==$i?
Thanks for helping.
It should suffice to substitute:
if($exceptions[] == $i)
with:
if(in_array($i,$exceptions))
By the way, it eliminates the need for a nested loop.
Ah, should be straightforward, no?
$exceptions = explode(",", $row->exceptions);
for ($i = 0; $i <= $row->frequency; $i++) {
foreach($exceptions as $j){
if($j == $i){
// do something
break;
}
}
}
I think I understand what you are asking. Here's how you would test within that loop whether the key equals $i.
for ($i = 0; $i <= $row->frequency; $i++)
{
foreach ($exceptions as $key => $value)
{
if ($key == $i)
{
continue;
}
}
}