How do I get the first and last results from a query? - php

I am creating a pagination script and I need to get the first and last results in the database query so that I can determine what results appear when the user clicks a page to go to. This is the code that I have at the minute:
// my database connection is opened
// this gets all of the entries in the database
$q = mysql_query("SELECT * FROM my_table ORDER BY id ASC");
$count = mysql_num_rows($q);
// this is how many results I want to display
$max = 2;
// this determines how many pages there will be
$pages = round($count/$max,0);
// this is where I think my script goes wrong
// I want to get the last result of the first page
// or the first result of the previous page
// so the query can start where the last query left off
// I've tried a few different things to get this script to work
// but I think that I need to get the first or last result of the previous page
// but I don't know how to.
$get = $_GET['p'];
$pn = $_GET['pn'];
$pq = mysql_query("SELECT * FROM my_table ORDER BY id ASC LIMIT $max OFFSET $get");
// my query results appear
if(!$pn) {
$pn = 1;
}
echo "</table><br />
Page $pn of $pages<br />";
for($p = 1;$p<=$pages;$p++) {
echo "<a href='javascript:void(0);' onclick='nextPage($max, $p);' title='Page $p'>Page $p</a> ";
}

I think you have few problems there, but I try to tackle them for you. First, as comments say above, you are using code that it vulnerable to SQL injection. Take care of that - you might want to use PDO, which is as easy use as MySQL extension, and will save you from many trouble (like injection).
But to your code, lets go through it:
You should ask DB to get count of the rows, not using mysql function, it's far more effective, so use SELECT count(*) FROM mytable.
For $pages use ceil() as you want all rows to be printed, if you have $max 5 and have 11 rows, round will make $pages 2, where you actually want 3 (last page just contains that last 11th row)
in LIMIT you want to LIMIT row_count OFFSET offset. You can calculate offset from page number, so: $max = row_count but $offset = ($max * $page) - $max. In your code if $get is directly the page, it means you get $get'th row (Not sure though what happens in your JS nextpage. Bare in mind that not all use JavaScript.)
I have prepared simple example here which uses PDO, maybe that gives you idea how simple it's use PDO.
The selecting rows shows example how to put parameters in SQL, it would be perfectly safe in this case state, 'SELECT * FROM pseudorows LIMIT '.$start.','.$max by I wanted to make an example how easy it is (and then safe):
// DB config
$DB_NAME = 'test';
$DB_USER = 'test';
$DB_PASSWD = 'test';
// make connection
try {
$DB_CONN = new PDO("mysql:host=localhost;dbname=".$DB_NAME, $DB_USER, $DB_PASSWD);
$DB_CONN->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDOException $e) {
die($e);
}
// lets say user param 'p' is page, we cast it int, just to be safe
$page = (int) (isset($_GET['p'])?$_GET['p']:1);
// max rows in page
$max = 20;
// first select count of all rows in the table
$stmt = $DB_CONN->prepare('SELECT count(*) FROM pseudorows');
$stmt->execute();
if($value = $stmt->fetch()) {
// now we know how many pages we must print in pagination
// it's $value/$max = pages
$pages = ceil($value[0]/$max);
// now let's print this page results, we are on $page page
// we start from position max_rows_in_page * page_we_are_in - max_rows_in_page
// (as first page is 1 not 0, and rows in DB start from 0 when LIMITing)
$start = ($page * $max) - $max;
$stmt = $DB_CONN->prepare('SELECT * FROM pseudorows LIMIT :start,:max');
$stmt->bindParam(':start',$start,PDO::PARAM_INT);
$stmt->bindParam(':max', $max,PDO::PARAM_INT);
$stmt->execute();
// simply just print rows
echo '<table>';
while($row = $stmt->fetch()) {
echo '<tr><td>#'.$row['id'].'</td><td>'.$row['title'].'</td></tr>';
}
echo '</table>';
// let's show pagination
for($i=1;$i<=$pages;$i++) {
echo '[ '.$i.' ]';
}
}

mysql_fetch_array returns an associative array
Which means you can use reset and end to get the first and last results:
$pqa = mysql_fetch_array($pq);
$first = reset($pqa);
$last = end($pqa);
I don't see how you plan to use the actual results, just page numbers should be sufficient for pagination.
Still, hope it helps. And yes, upgrade to mysqli, so your code doesn't get obsolete.

Related

PHP Limit rows returned by MySQL and do something if last row returned

I didn't know exactly how to word this question but by do something I mean that I would like to hide or not show my "next" button that is shown below. I have a script that pulls all the images from MySQL and prints them to my page by 30 images per page and the next 30 will create a new page that is activated by my back/next buttons. My "back" button has a if statement if $startrow isn't >= 0 than it won't show but I would like the same concept with my next button when the last row in my database is shown and it hides my next button.
I was thinking if you can detect the first empty row or the last row of the database and if so hide the next button. Otherwise it keeps adding 30 to $startrow when nothing is shown on screen.
I found a script helping me with this here but it didn't tell me how to hide the next button.
<?php
$startrow = $_GET['startrow'];
if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) {
$startrow = 0;
} else {
$startrow = (int)$_GET['startrow'];
}
?>
<?php
$db = mysqli_connect("localhost", "root", "", "media");
$uploaded = mysqli_query($db, "SELECT * FROM images LIMIT $startrow, 30");
while ($row = mysqli_fetch_array($uploaded)) {
echo "<div class='img_container'>";
echo "<li><img class='img_box' src='uploads/images/".$row['image_title']."' ></li>";
echo "</div>";
}
$prev = $startrow - 30;
if ($prev >= 0) {
echo '<div class="prevRow">Back</div>';
}
echo '<div class="nextRow">Next</div>';
?>
You could try something like
$num_rows = 30; // rows on a page
$db = mysqli_connect("localhost", "root", "", "media");
// get total possible rows
$res = mysqli_query($db, "SELECT count(id) FROM images");
$row = $res->fetch_row();
$total_rows = $row[0];
$res->close();
$uploaded = mysqli_query($db, "SELECT * FROM images LIMIT $startrow, $num_rows");
while ($row = mysqli_fetch_array($uploaded)) {
. . .
}
$prev = $startrow - $num_rows;
if ($prev >= 0) {
echo '<div class="prevRow">Back</div>';
}
if ( $startrow+$num_rows < $total_rows ) {
echo '<div class="nextRow">Next</div>';
}
Potentially a little faster than the answer from #RiggsFolly, you can modify your existing query to count the rows.
SELECT SQL_CALC_FOUND ROWS * FROM images LIMIT $startrow, 30
Then, after the query returns, you run a second query to get the answer:
SELECT FOUND_ROWS()
The FOUND_ROWS() function returns the number of rows the previous query would have returned, without LIMIT (or an offset).
This is probably not as fast as your original query would be in isolation, but should be slightly faster than SELECT COUNT(...) ... followed by your original query. With small data sets, though, any differences will likely be below measurable limits.
See also https://dev.mysql.com/doc/refman/5.7/en/information-functions.html
You can also combine these things into a stored procedure that accepts items per page and page number, and returns all of the records along with metadata items such as the total number of pages.

How to index a table with order by?

Using a while loop I'm able to return my table in the order I want, but after implementing pagination the variable I've created (counter) resets itself on each page, frustratingly. Example code:
$sql = ('SELECT id,name,logo FROM mytable ORDER BY name DESC LIMIT 25');
$query = mysqli_query($db_conx,$sql);
$counter = 0;
while ($row = $query->fetch_assoc()) {
$counter++;
echo "$counter, $row['id'], $row['name']";
echo "<br />";
}
I've tried many things and can't get this to work. Obviously my logic is flawed. The loop returns the correct results, but the $counter variable breaks on each page, resetting itself indefinitely.
What I am trying to do is get $counter to increase by 25 (representing results for each page) for each of the pages created by the pagination loop. Example code:
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='page.php?page=".$i."'>&nbsp[".$i."]</a> ";
$GLOBALS["counter"]+=25;
};
Obviously this was not working, so I am stumped at what I should try next. If anyone has any ideas I would love to hear them, I have heard great things about the SO community.
You seem to display only the first 25 results at any time.
You need to initialize $counter to zero if it's the first page, to 26 if it's the second page, and so on :
$counter = 0;
if(isset($_GET['counter'])){
$counter = intval($_GET['counter']);
}
You need to modify your query to fetch a different set of results for each page :
$sql = 'SELECT id,name,logo FROM mytable ORDER BY name DESC LIMIT ' . mysqli_real_escape_string($db_conx, $counter . ',25');
$query = mysqli_query($db_conx,$sql);
Then I assume you display a link to the other paginated pages, you need to pass it the value of $counter :
Next

Mysql Queries Error Inside a While Loop

I have a while loop from a query called $result.
Inside this while loop I have two other queries $anchors1 and $anchors2
The first one retrieves the first 2 rows;
The second one should retrieve the following ones using an offset.
For some reason the queries seem to interact one another, not displaying the 3 row and pulling a duplicate row which should not be there.
Is there any way this queries would interfere?
If I delete the first one, the second query works. Same vice versa.
The platform is Wordpress.
while($slice = mysql_fetch_assoc($result)){
$i++;
if($enable_position1 == 'y' && $i == $position[0]):
$anchors1 = mysql_query("SELECT * FROM anchors WHERE site_url = '$site_current' LIMIT 3");
while($anc = mysql_fetch_assoc($anchors)){
$site_anchor = $anc['site_anchor'];
$site_current = $anc['site_current'];
echo '<li>'.$site_anchor.'</li>';
}
elseif($enable_position2 == 'y' && $i == $position[1]):
$anchors2 = mysql_query("SELECT * FROM anchors WHERE site_url = '$site_current' LIMIT 999 OFFSET 3");
while($anc2 = mysql_fetch_assoc($anchors2)){
$site_anchor2 = $anc2['site_anchor'];
$site_current2 = $anc2['site_current'];
echo '<li>'.$site_anchor2.'</li>';
}
else:
the_post();
endif;
}
Ty very much!
In the second query, you're using the variable $site_current, which is set in the first query's block. Depending on how your application is designed, that could be causing the interference. I think you meant to put $site_current2 there.

PHP/MySQL Count() Issue

I am trying to create a class registration system for a client that utilizes PHP and MySQL. I have the database and table all set up and that part works just fine, however, the client has requested that upon registration, if there are 3 or fewer students enrolled to warn that the class may not run.
I'm trying to use the count() function as well as passing a dynamic variable from a cookie, set from the registration PHP script. However, I've hit a roadblock. I can't seem to get the count() function to actually count the rows. My select statement is below. Any help would be greatly appreciated.
$class = $_COOKIE["class"];
$min_check = "SELECT class_list, COUNT(class_list) as count
FROM T_Student WHERE class_list = '$class'
GROUP BY class_list
HAVING count < 20";
$result = mysql_query($min_check);
$count = mysql_num_rows($result);
if ($count < 4)
{
echo "IF THERE ARE 3 OR FEWER PEOPLE SIGNED UP FOR THIS CLASS, IT MAY NOT RUN.\n";
echo "THERE ARE CURRENTLY " . $count . " PEOPLE SIGNED UP.\n";
}
else if ($count > 4)
{
echo "There are currently " . $count . " people signed up for this class.";
}
?>
Your SQL query is returning a list of the class_list values, along with a count of each specific instance, where there are less than 20 people registered.
$count = mysql_num_rows($result);
...is getting the number of records returned in the resultset, not the alias count value, which is why you aren't seeing the output you expect. You need to read into your resultset to get the value:
while ($row = mysql_fetch_assoc($result)) {
$count = $row['count'];
if($count < 4) { ... }
}
The count that you want is returned in the row of the query. the mysql_num_rows will count the rows returned, which is not what you want. Use this instead.
$result = mysql_query($min_check);
$count = mysql_fetch_row($result);
$count = $count[0];
On a first glance, the HAVING count < 20 is unnecessary.
You use the MySQL-count-function, but never retrieve it's value!? Use:
$firstRow = mysql_fetch_row($result);
$count = $firstRow[1]; // 1 indicates the second column (0 being the first)
I don't recommend using known MySQL identifiers like count. It's confusing.
$class = mysql_real_escape_string($_COOKIE["class"]);
$min_check = "SELECT class_list, COUNT(class_list) as mycount
FROM T_Student WHERE class_list = '$class'
GROUP BY class_list
HAVING mycount < 20";
Don't forget to escape the contents of that cookie!
The error is that count is a reserved word. You need to either surround it in backticks `count` or even better, use a different moniker. It's not an error per se, but it's just too confusing.
Next up, you are not actually retrieving the mycount result from the database. I suggest using code something like this:
$result = mysql_query($min_check);
while( $row = mysql_fetch_assoc($result) ) {
$people_count = $row['mycount'];
if ($people_count < 4) { echo "this" }
else { echo "that" }
}

MySQL PHP Pagination

Is it possible to create pagination without getting all elements of table?
But with pages in GET like /1 /666…
It usually involves issuing two queries: one to get your "slice" of the result set, and one to get the total number of records. From there, you can work out how many pages you have and build pagination accordingly.
A simply example:
<?php
$where = ""; // your WHERE clause would go in here
$batch = 10; // how many results to show at any one time
$page = (intval($_GET['page']) > 0) ? intval($_GET['page']) : 1;
$start = $page-1/$batch;
$pages = ceil($total/$batch);
$sql = "SELECT COUNT(*) AS total FROM tbl $where";
$res = mysql_query($sql);
$row = mysql_fetch_assoc($res);
$total = $row['total'];
// start pagination
$paging = '<p class="paging">Pages:';
for ($i=1; $i <= $pages; $i++) {
if ($i==$page) {
$paging.= sprintf(' <span class="current">%d</a>', $i);
} else {
$paging.= sprintf(' %1$d', $i);
}
}
$paging.= sprintf' (%d total; showing %d to %d)', $total, $start+1, min($total, $start+$batch));
And then to see your pagination links:
...
// loop over result set here
// render pagination links
echo $paging;
I hope this helps.
Yes, using mySQL's LIMIT clause. Most pagination tutorials make good examples of how to use it.
See these questions for further links and information:
How do you implement pagination in PHP?
Searching for advanced php/mysql pagination script
more results
You can use LIMIT to paginate over your result set.
SELECT * FROM comments WHERE post_id = 1 LIMIT 5, 10
where LIMIT 5 means 5 comments and 10 is the offset. You can also use the longer syntax:
... LIMIT 5 OFFSET 10

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