How to index a table with order by? - php

Question

Using a while loop I'm able to return my table in the order I want, but after implementing pagination the variable I've created (counter) resets itself on each page, frustratingly. Example code:
$sql = ('SELECT id,name,logo FROM mytable ORDER BY name DESC LIMIT 25');
$query = mysqli_query($db_conx,$sql);
$counter = 0;
while ($row = $query->fetch_assoc()) {
$counter++;
echo "$counter, $row['id'], $row['name']";
echo "<br />";
}
I've tried many things and can't get this to work. Obviously my logic is flawed. The loop returns the correct results, but the $counter variable breaks on each page, resetting itself indefinitely.
What I am trying to do is get $counter to increase by 25 (representing results for each page) for each of the pages created by the pagination loop. Example code:
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='page.php?page=".$i."'>&nbsp[".$i."]</a> ";
$GLOBALS["counter"]+=25;
};
Obviously this was not working, so I am stumped at what I should try next. If anyone has any ideas I would love to hear them, I have heard great things about the SO community.

Answer 1

You seem to display only the first 25 results at any time.
You need to initialize $counter to zero if it's the first page, to 26 if it's the second page, and so on :
$counter = 0;
if(isset($_GET['counter'])){
$counter = intval($_GET['counter']);
}
You need to modify your query to fetch a different set of results for each page :
$sql = 'SELECT id,name,logo FROM mytable ORDER BY name DESC LIMIT ' . mysqli_real_escape_string($db_conx, $counter . ',25');
$query = mysqli_query($db_conx,$sql);
Then I assume you display a link to the other paginated pages, you need to pass it the value of $counter :
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