Input checkbox value that is created dynamically into MySQL if checked - php

Question

I am pulling in questions from a questions table in MySQL and populating them in a form. This works fine and I am populating checkboxes as well that the value is populated with the QuestionID. The array is properly populating but I want to take the value of the checked checkboxes (which is my question ID) and insert that ID into a table, so that I have the questions that are selceted for use by their ID. Here is what I have so far:
//Declare the QuestionID as a array
$QuestionID = array();
while($row = mysqli_fetch_array($run,MYSQLI_ASSOC)){
echo '<div id="QuestionSelection"><input id="chkQuestion" type="checkbox" value=" '.$row['QuestionID'].'" name=chkQuestion align="left"/><p>' . $row['Question'] .'</p></div><br/><br/>';
//Assign the QuestionID from the table to the var
$QuestionID[] = $row['QuestionID'];
}
if($_POST['submitted']) {
if (isset($_POST['chkQuestion']))
{
//create the query for the score
$sql2 = "INSERT INTO tbl_QuestionSelected (`QuestionID`) VALUES ($QuestionID)";
//Run the query
$run2 = #mysqli_query ($conn,$sql2);
//Confirm message data was entered with a correct response and a graphic
echo '<h1>Submitted!!</h1>';
}
}//End of IF 'submitted

Answer 1

You want to insert multiple records in one statement is what I'm understanding.
$sql2 = "INSERT INTO `tbl_QuestionSelected` (`QuestionID`) VALUES(". implode('),(', $QuestionID) . ")";
This will join each index inside $QuestionID with ),(
If you were to echo $sql2 you would get
INSERT INTO `tbl_QuestionSelected` (`QuestionID`) VALUES(1),(2),(3)

Answer 2

You can use a loop to get the questions that are checked.
for($i=0;$i<count($_POST["chkQuestion"]);$i++) {
"INSERT INTO tbl_QuestionSelected (QuestionID) VALUES('".$_POST["chkQuestion"][$i]."');
}
This way the MySQL statement has the actual values to insert into your table.

Answer 3

try to loop your ids and escape it!!
$ids_list = '';
foreach($_POST["chkQuestion"] as $id)
{
$ids_list .= (strlen($ids_list) > 0 ? ',' : '').mysql_real_escape_string($id);
}
$sql2 = "INSERT INTO tbl_QuestionSelected (`QuestionID`) VALUES (".$ids_list.")";

Answer 4

This will assign the value based on the array for the value and insert it into MySQL:
//Declare the QuestionID as a array
$QuestionID = array();
while($row = mysqli_fetch_array($run,MYSQLI_ASSOC)){
echo '<div id="QuestionSelection"><input id="chkQuestion" type="checkbox" value=" '.$row['QuestionID'].'" name="QuestionID[' . $row['QuestionID'] . ']">' .$row['Question']. '</p></div><br/><br/>';
//Assign the QuestionID from the table to the var
$QuestionID[] = $row['QuestionID'];
}
if($_POST['submitted']) {
$ids_list = '';
foreach($_POST["QuestionID"] as $key=>$value) {
{
$ids_list .= (strlen($ids_list) > 0 ? ',' : '').mysql_real_escape_string($value);
}
$sql2 = "INSERT INTO tbl_QuestionSelected (`QuestionID`) VALUES (".$ids_list.")";
//Run the query
$run2 = #mysqli_query ($conn,$sql2);
}//End of IF 'submitted
}