Create php fom select multiple taking values from a table bd - php

Question

The table deportes has 2 columns with 4 rows:
<?php
$sql = 'SELECT * FROM deportes';
$resul = mysqli_query($conexion, $sql);
$deportes = array();
while ($fila = mysqli_fetch_array($resul))
{
$deportes[] = $fila;
}
?>
The form with the select multiple options:
<select name="fan[]" multiple="multiple">
<?php
foreach ($deportes as $aficion)
{
echo "<option value='".$aficion['idD']."'";
echo " >{$aficion['nombreDep']} </option>\n";
}
?>
</select>
Get the values from the form
<?php
if (isset($_POST['fan']))
{
$sport = $_POST['fan'];
}
?>
Now this
<?php $sport = mysqli_real_escape_string($conexion, $sport); ?>
This way insert the values in another table
$idPersona = mysqli_insert_id($conexion);
$sql = "INSERT INTO mec(id,idD) VALUES ('$idPersona','$sport') ";
And the result is i get the value "0" in the field idD from table mec

Answer 1

If you print_r your $_POST['fan'], you will see that this is array. To get every value of array you should iterate over it, with for or foreach:
$idPersona = mysqli_insert_id($conexion);
foreach ($_POST['fan'] as $sport) {
echo $sport; // you will see that now it is string
$sql = "INSERT INTO mec(id,idD) VALUES ('$idPersona','$sport') ";
// execute your query
}
And of course you must move to prepared statements to protect your code from sql-injection. This question will give you a start.