I have a path like:
$path='somefolder/foo/bar/lastdir';
and I want to remove the last part, so I have:
$path='somefolder/foo/bar';
Like I went one folder up.
I'm really newbie in php, maybe its just one function, although I can't find it anywhere.
You could try this (tested and works as expected):
$path = 'somefolder/foo/haha/lastone';
$parts = explode('/', $path);
array_pop($parts);
$newpath = implode('/', $parts);
$newpath would now contain somefolder/foo/haha.
use :
dirname(dirname('somefolder/foo/haha/lastone/somescript.php'));
this should return:
somefolder/foo/haha/
This is untested, but try:
$path_array = explode('/',$path);
array_pop($path_array);
$path = implode('/',$path_array);
If you are currently at:
somefolder/foo/haha/lastone/somescript.php
and you want to access:
somefolder/foo/haha/someotherscript.php
just type:
../someotherscript.php
Probably using a regex function would be appropriate if the last part is going to vary. Try
$pattern = '#/.*$#U';
$stripped_path = preg_replace($pattern, '', $original_path);
This will strip everything off the original path string starting from the last forward slash.
You could use a function that explodes() the $path variable into an array and then array_pop to get rid of the last element.
function path($path) {
$arrayPath = explode("/", $path);
$path = array_pop($arrayPath);
return $path = implode("/", $path);
}
The shortest variant in PHP is:
$path = preg_replace('|/[^/]*$|','', $path);
which uses a regular expression.
Related
Goal -
convert a path: /aaaaa/bbbbb/ccccc/dddd
to a relative path (to the root): ../../../../
So far I've come up with this regex: /\/.+?\//
but this only produces: ..bbbbb..dddd because it is only matching every other pair of slashes, and also matching the slashes. I'm looking for something like a string split, but also replace.
All of my php code:
$pattern = '/\/.+?\//';
$path = '/aaaaa/bbbbb/ccccc/dddd';
echo preg_replace($pattern, '..', $path);
preg_replace('/\/{0,1}(\w+)\/{0,1}/', '../', $path);
This is working for me.
How about:
preg_replace(':/[^/]+:', '../', $path);
what about the below ?
$pattern = '/\//';
$path = '/aaaaa/bbbbb/ccccc/dddd';
preg_replace(array($pattern), array('..'), $path
I need a regular expression that would take the string after the last forward slash.
For example, considering I have the following string:
C:/dir/file.txt
I need to take only the file.txt part (string).
Thank you :)
You don't need a regex.
$string = "C:/dir/file.txt";
$filetemp = explode("/",$string);
$file = end($filetemp);
Edited because I remember the latest PHP spitting errors out about chaining these types of functions.
If your strings are always paths you should consider the basename() function.
Example:
$string = 'C:/dir/file.txt';
$file = basename($string);
Otherwise, the other answers are great!
The strrpos() function finds the last occurrence of a string. You can use it to figure out where the file name starts.
$path = 'C:/dir/file.txt';
$pos = strrpos($path, '/');
$file = substr($path, $pos + 1);
echo $file;
I am not much used to using rtrim and Reg expressions. So I wanted to get my doubt cleared about this:
Here is a url: http://imgur.com/r/pics/paoWS
I am trying to use rtrim function on this url to pick out only the 'paoWs' from the whole url.
Here is what i tried:
$yurl = 'http://imgur.com/r/pics/paoWS';
$video_id = parse_url($yurl, PHP_URL_PATH);
$yid=rtrim( $video_id, '/' );
And i am using '$yid' to hotlink the image from imgur. But What I get after trying this function is:
$yid= '/r/pics/paoWS'
How do I solve this?
rtrim is used for trimming down a string of certain characters or whitespace on the right-hand side. It certainly shouldn't be used for your purpose.
Assuming the URL structure will always be the same, you could just do something like this:
$yurl = 'http://imgur.com/r/pics/paoWS';
$video_id = parse_url($yurl, PHP_URL_PATH);
$parts = explode('/', $video_id)
$yid = end($parts);
You sould not use regular expressions (whitch are 'expensive') for a so 'simple' problem.
If you want to catch the last part of the URL, after the last slash, you can do :
$urlParts = explode('/', 'http://imgur.com/r/pics/paoWS');
$lastPart = end($urlParts);
rtim( strrchr('http://imgur.com/r/pics/paoWS' , '/') ); rtrim + strrchr
substr(strrchr('http://imgur.com/r/pics/paoWS', "/"), 1); substr + strrchr
rtrim() returns the filtered value, not the stripped characters. And your usage of it isn't proper too - it strips the passed characters from the right side. And you don't need parse_url() either.
Proper answers have been given already, but here's a faster alternative:
$yid = substr($yurl, strrpos($yurl, '/')+1);
Edit: And another one:
$yid = ltrim(strrchr($yurl, '/'), '/');
I have a path that looks like:
/home/duke/aa/servers/**servername**/var/...morefiles...
With php, I want to extract the "servername" from the path
Unfortunately I'm not that well versed with php but I came up with something that used strstr() but I am only using PHP version 5.2 where as one of the parameter functions require 5.3
What could be some code that would return "servername"?
you can use explode('/', $path) to break it down into the individual directories. After that, it's up to you to figure out which array element is the server name (with your sample path, it'd be #4):
$parts = explode('/', $path);
echo $parts[4]; // **servername**
function getServerName($data) {
preg_match('#/servers/(.+)/var/#', $data, $result);
if (isset($result[1]) {
return $result[1];
}
}
$data = '/home/duke/aa/servers/**servername**/var/...morefiles...';
echo getServerName($data);
$str = '/home/duke/aa/servers/**servername**/var/...morefiles...';
echo preg_replace('$(.+)/servers/(.+)/var/(.+)$', '\2', $str);
string '/home/adam/Projects/red/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg' (length=85)
what i need is just
http://localhost/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg
what is the best way doing it ? i mean useing strlen ? substr_replace ? substr ? im a bit confused what is the best way doing this? becouse there is many ways to do this.
edit* there is no newbie tag :|
// get from database red/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg
$image_path = $this->data['products'][0]['image_small'];
$exploded = end(explode('/', $image_path));
$myurl = DOMAIN;
$myfullurl = $myurl."/storage/".$exploded;
// it works!, but let see the comments maybe there is a better way :)
Here is how you can get the image part:
$str = '/home/adam/Projects/red/storag/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg';
$exploded = end(explode('/', $str));
echo $exploded;
Result:
22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg
Now you can concatenate it with whatever eg:
$new_str = 'http://localhost/storage/' . $exploded;
echo $new_str;
Result:
http://localhost/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg
And It is most likely you want to concatenate the image path with your document root which you do like this:
$img_path = $_SERVER['DOCUMENT_ROOT'] . $exploded;
The idea is that you explode the string with explode function by specifying / as delimiter. This gives you array, now you use the end function to get the ending part of the array which is your image actually.
If the path prefix represents your document root path, then you can do this to strip it:
$path = '/home/adam/Projects/red/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg';
$_SERVER['DOCUMENT_ROOT'] = '/home/adam/Projects/red/';
if (substr($path, 0, strlen($_SERVER['DOCUMENT_ROOT'])) === $_SERVER['DOCUMENT_ROOT']) {
$uriPath = substr($path, strlen(rtrim($_SERVER['DOCUMENT_ROOT'], '/')));
echo $uriPath;
}
I suggest you check if the string contains /home/adam/Projects/red, and if it does, you use substr to get the part after it, and you glue it with http://localost.
$path = '/home/adam/Projects/red/storage/*snip*.jpg';
$basePath = "/home/adam/Projects/red";
if (strpos($path, $path) !== false)
$url = 'http://localhost' . substr($path, strlen($basePath));
This one's pretty much the easiest
str_replace(
"/home/adam/Projects/red",
"http://localhost",
"/home/adam/Projects/red/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg"
);
$string = '/home/adam/Projects/red/storage/22ff0bc0662bd323891844f6ed342cce2603490ec0_tumb_2.jpg';
str_replace('/home/adam/Projects/red', 'http://localost', $string)