I need a regular expression that would take the string after the last forward slash.
For example, considering I have the following string:
C:/dir/file.txt
I need to take only the file.txt part (string).
Thank you :)
You don't need a regex.
$string = "C:/dir/file.txt";
$filetemp = explode("/",$string);
$file = end($filetemp);
Edited because I remember the latest PHP spitting errors out about chaining these types of functions.
If your strings are always paths you should consider the basename() function.
Example:
$string = 'C:/dir/file.txt';
$file = basename($string);
Otherwise, the other answers are great!
The strrpos() function finds the last occurrence of a string. You can use it to figure out where the file name starts.
$path = 'C:/dir/file.txt';
$pos = strrpos($path, '/');
$file = substr($path, $pos + 1);
echo $file;
Related
i have a path like this:
/dude/stuff/lol/bruh.jpg
i want to echo it like this:
/stuff/lol/bruh.jpg
how to do this? and if you could please explain it. i found one good answer
Removing part of path in php but i cannot work my way around with explode and implode.
please give me the link to the duplicate answer if my question is a duplicate
You could use strpos with substr:
$string = '/dude/stuff/lol/bruh.jpg';
$string = substr($string, strpos($string, '/', 1));
The strpos to look for the position of the / after the first one, then use substr to get the string starting from that position till the end.
$path = '/dude/stuff/lol/bruh.jpg';
$path = explode('/', $path);
unset($path[1]);
$path = implode('/', $path);
Will separate the string into an array, then unset the first item (technically the second in the array, since the first element will be empty due to the string starting with /). Finally the path is imploded, and you get:
/stuff/lol/bruh.jpg
Try this :
$string = "/dude/stuff/lol/bruh.jpg";
$firstslash = strpos($string,"/",1);
$secondstring = substr($string, $firstslash+1);
echo "String : " . $string;
echo " <br> Result : " . $secondstring;
You can use a regular expression to extract resource name you need.
preg_match('/(?P<name>[^\/]+)$/', $path, $match);
Then you have to use $match as array, and you can see the name inside of it.
$match['name];
Hi i want to know how can i get substring from string after last slash?
In short i want to get the file name from path.
for example i got string like this:
test-e2e4/test-e2e4/test-e2e4/6.png
and i want to get 6.png how can i do that ?
I got dir only and the file name can be all format, it can be also something else then file
Or test-e2e4/test-e2e4/test-e2e4/aaaaa and want to get aaaaa
Regex maybe? Or maybe you know some nice functions which will do it for me ?
In addition to other replies, there's actually a function in PHP to do this: basename. Example:
$string = 'test-e2e4/test-e2e4/test-e2e4/6.png';
$base = basename($string); // $base == '6.png';
$string = 'test-e2e4/test-e2e4/test-e2e4/aaaaa';
$base = basename($string); // $base == 'aaaaa'
$string = '6.png';
$base = basename($string); // $base == '6.png'
Full details here: http://php.net/basename
Do like this..
$yourstring = 'test-e2e4/test-e2e4/test-e2e4/6.png';
$val = array_pop(explode('/',$yourstring)); // 6.png
You can try explode and array_pop functions to work this out:
$str = 'test-e2e4/test-e2e4/test-e2e4/aaaaa.png';
$str = explode('/', $str);
$filename = array_pop($str);
echo $filename; //Output will be aaaaa.png
...Or you can use the following regex:
[^\/]*$
You don't need to use regex for this, you can use substr() to get a portion of the string, and strrpos() to specify which portion:
$full_path = "test-e2e4/test-e2e4/test-e2e4/6.png"
$file = substr( $full_path, strrpos( $full_path, "/" ) + 1 );
substr() returns a portion of the string, strrpos() tells it to start from the position of the last slash in the string, and the +1 excludes the slash from the return value.
How can I add divider ; in the following variable which contains string
I have string like this:
$filename = "a.jpg3c.pngyes.jpg";
I would like to have something like
a.jpg;3c.png;yes.jpg
This string is created when I select multiple files to upload.
Is regex only solution in here?
Regex is not the only solution! Perhaps you can use str_replace() instead of regex.
$filenames = "a.jpg3c.pngyes.jpg";
$img_extensions = array(".png", ".jpg", ".gif");
$semicolon_additions = array(".png;", ".jpg;", ".gif;");
$newfilenames = str_replace($img_extensions, $semicolon_additions, $filenames);
http://php.net/manual/en/function.str-replace.php
Edit: In your particular case, I would add in the semicolon at the end of the filename inside of your loop.
Here is one option using regular expressions:
$filename = "a.jpg3c.pngyes.jpg";
$regex = '/\.(jpg|png|gif)(?!$)/';
$filename = preg_replace($regex, ".$1;", $filename);
i want to give regex a pattern and force it to read it all ..
http://example.com/w/2/1/x/some-12345_x.png
i want to target "some-12345_x"
i used this /\/(.*).png/, it doesnt work for some reason
how do i force it to remember it must start with / and end with .png?
If you always want to get the final file-name, minus the extension, you could use PHP's substr() instead of trying to come up with a regex:
$lastSlash = strrpos($url, '/') + 1;
$name = substr($url, $lastSlash, strrpos($url, '.') - $lastSlash);
Also, a more readable method would be to use PHP's basename():
$filename = basename($url);
$name = substr($filename, 0, strpos($filename, '.'));
To actually use a regex, you could use the following pattern:
.*/([^.]+).png$
To use this with PHP's preg_match():
preg_match('|.*/([^.]+).png$|', $url, $matches);
$name = $matches[1];
You can do:
^.*/(.*)\.png$
which captures what occurres after the last / till .png at the end.
You might need to use reg-ex in this situation for a particular reason, but here's an alternative where you don't:
$url = "http://example.com/w/2/1/x/some-12345_x.png";
$value = pathinfo($url);
echo $value['filename'];
output:
some-12345_x
pathinfo() from the manual
How about:
~([^/]+)\.png$~
this will match anything but / until .png at the end of the string.
I am trying to sanitize a filename.
I would like to know of a way to remove all decimals from a files name except the last one. I need to keep the last one because the extension follows that.
EXAMPLE:
abc.def.ghij-klmnop.q234.mp3
This file should look like
abcdefghij-klmnopq234.mp3
Some extensions are longer than 3 characters.
You can use a regex with a positive lookahead. Like this:
$withdots = 'abc.def.ghij-klmnop.q234.mp3';
$nodots = preg_replace('/\.(?=.*\.)/', '', $withdots);
After executing the above, $nodots will contain abcdefghij-klmnopq234.mp3. The regular expression is basically saying match all periods that are followed by another period. So the last period won't match. We replace all matches with an empty string, and we're left with the desired result.
That should do it:
$file = 'abc.def.ghij-klmnop.q234.mp3';
$parts = pathinfo($file);
$filename = str_replace('.', '', $parts['filename']).'.'.$parts['extension'];
You could also do this, it should be faster then using pathinfo & str_replace.
$parts = explode('.', 'abc.def.ghij-klmnop.q234.mp3');
$ext = array_pop($parts);
$nodots = implode('', $parts) . '.' . $ext;
Assuming $s is the name of the file.
$s = (($i = strrpos($s, '.')) === false) ? $s :
str_replace('.','',substr($s,0,$i)).substr($s,$i);