PHP: Displaying a value dependent on input - php

Question

In my view I have the following select menu that states what type of form types are available:
<label for="add_fields_type">Type: </label>
<select name="add_fields_type" id="add_fields_type">
<option value="input">Input</option>
<option value="textarea">Text Area</option>
<option value="radiobutton">Radio Button</option>
<option value="checkbox">Check Box</option>
</select>
In my controller I currently have the following but I am unsure how to make is so that if $_REQUEST['add_fields_type'] is = to lets say radiobutton then it will display that respective code.
Controller:
if (isset($_REQUEST['add_fields_type']))
{
echo $_REQUEST['add_fields_type'];
}

Answer 1

if (isset($_REQUEST['add_fields_type'])) {
if ($_REQUEST['add_fields_type'] == 'input') {
// echo stuff for input
}
else if ($_REQUEST['add_fields_type'] == 'textarea') {
// echo stuff for textarea
}
else if ($_REQUEST['add_fields_type'] == 'radiobutton') {
// echo stuff for radiobutton
}
else if ($_REQUEST['add_fields_type'] == 'checkbox') {
// echo stuff for checkbox
}
}

Answer 2

Another way, using the switch code that swapnesh mentioned (slightly more concise than having multiple if statements and will stop when it hits the right case):
if (isset($_REQUEST['add_fields_type']))
{
switch($_REQUEST['add_fields_type'])
{
case('input'):
// echo stuff for input
break;
case('textarea'):
// echo stuff for textarea
break;
case('radiobutton'):
// echo stuff for radiobutton
break;
case('checkbox'):
// echo stuff for checkbox
break;
default:
// echo stuff if the other cases fall through
break;
}
}