Option Menu with Last Record as Default - php

Question

I have an option menu as follows:
<select name="selCycle" id="selCycle" onChange="formFilter.submit()">
<option value="%">all cycles</option>
<?php
do {
?>
<option value="<?php echo $row_Recordset2['Cycle'] ?>"
<?php
if ($varCycle_DetailRS4 == $row_Recordset2['Cycle']) {
echo 'selected';
} elseif ($varCycle2_DetailRS4 == $row_Recordset2['Cycle']) {
echo 'selected';
} else {
echo '';
}
?>
>
<?php echo $row_Recordset2['Cycle'] ?>
</option>
<?php
} while ($row_Recordset2 = mysql_fetch_assoc($Recordset2));
$rows = mysql_num_rows($Recordset2);
if ($rows > 0) {
mysql_data_seek($Recordset2, 0);
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
}
?>
</select>
Currently, the default selection is showing all records. I would like for the default to be the latest set of data equal to:
<?php echo $row_RecordsetCycle['Cycle']; ?>
So option menu would list 1,2,3,4,5 with 5 being the default when the page loads. User can then pick any option available. is set to last record in table with a limit of 1 so it will always echo the last record, which composes the option menu.
Help please. What should I edit so that the one record in
<?php echo $row_RecordsetCycle['Cycle']; ?>
is the default or selected option menu when the page loads? Currently, the default just shows all records and is extremely slow to load, hence why I want the latest record to be the default.

Answer 1

I took a stab at rewriting this. (code at the end)
the first thing I did was turn your do_while loop into a while loop as I think it was adding unnecessary confusion to the code
after doing that I moved some code
$rows = mysql_num_rows($Recordset2);
if ($rows > 0) {
mysql_data_seek($Recordset2, 0);
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
}
above the while loop as I thought it was needed to "prime the pump" of the while loop
I also pulled the
if ($varCycle_DetailRS4 == $row_Recordset2['Cycle']) {
return ' selected';
} elseif ($varCycle2_DetailRS4 == $row_Recordset2['Cycle']) {
return ' selected';
} else {
return '';
}
out into a function so as to simplify the code further
now here come my assumptions I assumed that $varCycle_DetailRS4 was the last value and that $varCycle2_DetailRS4 was the currentlySelected that was set befor the code provided;
if that is the case and that $varCycle2_DetailRS4 would be unset if it was the first then all that would need to be done is to slightly modify the isSelected to only set one option as selected.
<?php
function isSelect($value)
{
$lastValue = $varCycle_DetailRS4;
$currentlySelected = $varCycle2_DetailRS4;
if(isset($currentlySelected))
{
$selectValue = $currentlySelected;
}
else
{
$selectValue = $lastValue;
}
if ($selectValue == $value) {
return ' selected';
} else {
return '';
}
}
?>
<select name="selCycle" id="selCycle" onChange="formFilter.submit()">
<option value="%">all cycles</option>
<?php
$rows = mysql_num_rows($Recordset2);
if ($rows > 0) {
mysql_data_seek($Recordset2, 0);
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
}
while ($row_Recordset2 = mysql_fetch_assoc($Recordset2))
{
$value = $row_Recordset2['Cycle']
echo " <option value=\"".$value."\"".isSelect($value).">".$value."</option>/n";
} ;
?>
</select>

Answer 2

Try using end() to get the last array:
<?php
$arr =array(1,2,3,4,5);
$last = end($arr);
?>
<select name="selCycle" id="selCycle" onChange="formFilter.submit()">
<option value="%">all cycles</option>
<?php foreach($arr as $key=>$val):
if(in_array("$last", array($val))==true){
echo '<option value="" selected="selected">'.$val.'</option>';
continue;
}
echo '<option>'.$val.'</option>';
endforeach; ?>
</select>
Stop using mysql extension, use pdo or mysqli. Using your question code, it should be:
$row_Recordset2 = mysql_fetch_assoc($Recordset2);
$last = end($row_Recordset2);
foreach($row_Recordset2 as $key=>$val){
//other code
if(in_array("$last", array($val))==true){
echo '<option value="" selected="selected">'.$val.'</option>';
continue;
}
echo '<option>'.$val.'</option>'
}
Working Demo