Insert Url last 2 characters in database php - php

Question

I am trying to insert last 2 chararcters of Url into my database.When i insert everytime it takes some number like "2147483647".How to insert the correct last 2 chararcters of Url.
'$array = json_decode(stripslashes($_POST['data']));
for($i = 0, $l = sizeof($array); $i < $l; $i++){
$obj = $array[$i];
if($obj->{'leaf'} == true){
$leaf = 1;
} else{
$leaf = 0;
}
if($obj->{'parentId'} == null){
$parentID = 'null';
} else{
$parentID = $obj->{'parentId'};
}
if($obj->{'Duration'}==''){
$duration = 0;
} else{
$duration = $obj->{'Duration'};
}
$url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$gantt_id = substr(strrchr($url, '='), 1);
/*if($obj->{'gantt_id'}==null){
$gantt_id = 0;
} else{
$gantt_id = $obj->{'gantt_id'};
}
*/
$q = 'INSERT INTO j_gantt_tasks SET Name = "'.$obj->{'Name'}.'", StartDate = "'.$obj->{'StartDate'}.'", EndDate = "'.$obj->{'EndDate'}.'",
Duration = "'.$obj->{'Duration'}.'", DurationUnit = "'.$obj->{'DurationUnit'}.'", PercentDone = "'.$obj->{'PercentDone'}.'", Cls = "'.$obj->{'Cls'}.'", gantt_id="'.$gantt_id.'",
parentId = "'.$obj->{'parentId'}.'"';
$r = mysql_query($q);
if(!$r){
echo db_error($q);
}
$obj->{'id'} = mysql_insert_id();
}
echo json_encode($array);'

Answer 1

give a try to substring
$url = (!empty($_SERVER['HTTPS'])) ?
"https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] :
"http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$last2 = substring($url,-2);