Scandir Array display without file extensions - php

Question

I'm using the following to create a list of my files in the 'html/' and link path.
When I view the array it shows, for example, my_file_name.php
How do I make it so the array only shows the filename and not the extension?
$path = array("./html/","./link/");
$path2= array("http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["PHP_SELF"])."/html/","http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["PHP_SELF"])."/link/");
$start="";
$Fnm = "./html.php";
$inF = fopen($Fnm,"w");
fwrite($inF,$start."\n");
$folder = opendir($path[0]);
while( $file = readdir($folder) ) {
if (($file != '.')&&($file != '..')&&($file != 'index.htm')) {
$folder2 = opendir($path[1]);
$imagename ='';
while( $file2 = readdir($folder2) ) {
if (substr($file2,0,strpos($file2,'.')) == substr($file,0,strpos($file,'.'))){
$imagename = $file2;
}
}
closedir($folder2);
$result="<li class=\"ui-state-default ui-corner-top ui-tabs-selected ui-state-active\">\n\n$file2\n<span class=\"glow\"><br></span>
</li>\n";
fwrite($inF,$result);
}
}
fwrite($inF,"");
closedir($folder);
fclose($inF);

Answer 1

pathinfo() is good, but I think in this case you can get away with strrpos(). I'm not sure what you're trying to do with $imagename, but I'll leave that to you. Here is what you can do with your code to compare just the base filenames:
// ...
$folder = opendir($path[0]);
while( $file = readdir($folder) ) {
if (($file != '.')&&($file != '..')&&($file != 'index.htm')) {
$folder2 = opendir($path[1]);
$imagename ='';
$fileBaseName = substr($file,0,strrpos($file,'.'));
while( $file2 = readdir($folder2) ) {
$file2BaseName = substr($file2,0,strrpos($file2,'.'));
if ($file2BaseName == $fileBaseName){
$imagename = $file2;
}
}
closedir($folder2);
$result="<li class=\"ui-state-default ui-corner-top ui-tabs-selected ui-state-active\">\n\n$file2\n<span class=\"glow\"><br></span>
</li>\n";
fwrite($inF,$result);
}
}
I hope that helps!