Exactly what the title says. I want the table containing all of the search queries to be hidden, but I've tried a lot of things and none of them work. For example, if($myData!=null) {proceed with showing the table}, but that didn't work. isset() also didn't work. Any ideas?
<style>
ul
{
list-style-type: none;
}
</style>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Search Chemicals</title>
</head>
<p>
<body>
<h3>Chemical Information</h3>
<p>You may search by Catalog number, CASRN, or the chemical name.</p>
<form method="post" action="search.php?go" id="searchform">
<input type="text" name="name">
<input type="submit" name="submit" value="Search">
</form>
<?php
error_reporting(0);
if (isset($_POST['submit'])) {
if (isset($_GET['go'])) {
if (preg_match("/^[a-zA-Z0-9]+/", $_POST['name'])) {
$name = $_POST['name'];
$conn = mysql_connect("localhost", "Blimeo", "password");
$db = mysql_connect("localhost", "-", "-") or die('I cannot connect to the database because: ' . mysql_error());
//-select the database to use
$mydb = mysql_select_db("chemicals");
//-query the database table
$sql = "SELECT * FROM products WHERE Catalog LIKE '%" . $name . "%' OR CASRN LIKE '%" . $name . "%' OR Chemical_Name LIKE '%" . $name . "%'";
$myData = mysql_query($sql, $conn);
echo "<table border=1>
<tr>
<th>Catalog</th>
<th>Image</th>
<th>CASRN</th>
<th>Chemical Name</th>
<th>Quantity 1</th>
<th>Price 1</th>
<th>Quantity 2</th>
<th>Price 2</th>
<th>Quantity 3</th>
<th>Price 3</th>
<th>Quantity 4</th>
<th>Price 4</th>
</tr>";
while ($record = mysql_fetch_array($myData)) {
echo "<tr>";
echo "<td>" . $record['Catalog'] . "</td>";
echo "<td><img src=\"./img/" . $record['Image'] . "\" alt=\"Chemical\"/></td>";
echo "<td>" . $record['CASRN'] . "</td>";
echo "<td>" . $record['Chemical_Name'] . "</td>";
echo "<td>" . $record['Quantity1'] . "</td>";
echo "<td>" . $record['Price1'] . "</td>";
echo "<td>" . $record['Quantity2'] . "</td>";
echo "<td>" . $record['Price2'] . "</td>";
echo "<td>" . $record['Quantity3'] . "</td>";
echo "<td>" . $record['Price3'] . "</td>";
echo "<td>" . $record['Quantity4'] . "</td>";
echo "<td>" . $record['Price4'] . "</td>";
echo "</tr>";
echo "</form>";
echo "<ul>\n";
echo "<li>" . "" . $Catalog . " " . $CASRN . " " . $Chemical_Name . "</li>\n";
echo "</ul>";
}
}
} else {
echo "<p>Product not found! Please rephrase your search criteria.</p>";
}
}
?>
</body>
</html>
</p>
You should add mysql_num_rows();
$myData = mysql_query($sql, $conn);
$exists = mysql_num_rows($myData);
if($exists) {
echo "<table border=1>";
//..................
echo "</table>";
} else {
echo "<p>Product not found! Please rephrase your search criteria.</p>";
}
Well, it seems you are echoing out your table regardless of the results of the search query. You should probably check the number of rows returned in teh result set and only echo out the table if the count is > 0.
Use <div visibility="hidden"> to hide the table and use Javascript to change the visibility based on the search queries or some other condition.
Related
I want to display table vertically. Now, It's displaying horizontally. Each
and every field is displaying. How can I display table vertically?
And one more thing I want to add one more function to the button. Current
date added into database when button
submit is clicked. For now this code is making my status 0 and not updating
date in database.
<html>
<head>
<meta name="description" content="website description" />
<meta name="keywords" content="website keywords, website keywords" />
<meta http-equiv="content-type" content="text/html; charset=windows-
1252" />
<link rel="stylesheet" type="text/css" href="style/style.css" />
<style>
<table>
{
border-style:solid;
border-width:2px;
border-color:pink;
}
</style>
</head>
<?php
include 'inc/head.php';
include 'connection.php';
$id = $_GET['id'];
$sql = "SELECT * FROM user WHERE id='$id'";
$query = mysqli_query($conn, $sql);
echo "<table border='6'>
<tr>
<th>Application Type</th> <br>
<th>First name</th><br>
<th>Sur name</th><br>
<th>title</th>
<th>Date of Birth</th>
<th>Gender</th>
<th>Nationality</th>
<th>Country of Birth</th>
<th>Applicant's Location</th>
<th>alias</th>
<th>Criminal </th>
<th>Country of passport</th>
<th>Passport number</th>
<th>Passport issue date </th>
<th>Passport expiry date</th>
<th>Address </th>
<th>City</th>
<th>State</th>
<th>Postal Code</th>
<th>Country</th>
<th>Email Address</th>
<th>Home Number</th>
<th>Business Number</th>
<th>mobile</th>
</tr>";
while($row = mysqli_fetch_assoc($query)) {
echo "<tr>";
echo " <td>" . $row['applicationtype'] . "</td>";
echo " <td>" . $row['firstname'] . "</td>";
echo " <td>" . $row['lastname'] . "</td>";
echo " <td>" . $row['title1'] . "</td>";
echo " <td>" . $row['dob'] . "</td>";
echo " <td>" . $row['gender'] . "</td>";
echo " <td>" . $row['nationality'] . "</td>";
echo " <td>" . $row['countryofbirth'] . "</td>";
echo " <td>" . $row['applicantlocation'] . "</td>";
echo " <td>" . $row['alias'] . "</td>";
echo " <td>" . $row['criminal'] . "</td>";
echo " <td>" . $row['countryofpassport'] . "</td>";
echo " <td>" . $row['passportnumber'] . "</td>";
echo " <td>" . $row['pid'] . "</td>";
echo " <td>" . $row['ped'] . "</td>";
echo " <td>" . $row['address'] . "</td>";
echo " <td>" . $row['city'] . "</td>";
echo " <td>" . $row['state'] . "</td>";
echo " <td>" . $row['postalcode'] . "</td>";
echo " <td>" . $row['country'] . "</td>";
echo " <td>" . $row['email'] . "</td>";
echo " <td>" . $row['homephone'] . "</td>";
echo " <td>" . $row['businessphone'] . "</td>";
echo " <td>" . $row['mobile'] . "</td>";
echo "</tr>";
}
echo "</table><br><br>";
if(isset($_POST['submit'])) {
echo $radio = $_POST['radio'];
$date_clicked = date('Y-m-d H:i:s');
$sql = "UPDATE user SET visastatus='$radio' AND currentdate='$date_clicked' WHERE id='$id'";
$query = mysqli_query($conn, $sql);
if($query) {
echo "<h4 style='color:green'>Action Performed Successfully....</h4>";
} else {
echo "<h4 style='color:red'>Failed.</h4>";
}
}
?>
<form method="POST" action="" enctype="multipart/form-data">
<div class="col-xs-12 col-sm-6 col-md-6 col-lg-6" style="margin-top:
8px;">
<label class="checkbox-inline tourist-rad">
<input type="radio" name="radio" id="success"
value="Successfull">Successfull
</label>
<label class="checkbox-inline tourist-rad">
<input type="radio" name="radio" id="decline" value="Declined">Declined
</label>
</div>
<div class="form-group">
<button type="submit" name="submit" value="submit" class="btn btn-
primary" style="float: right;">Update Menu Item</button>
</div>
</body>
</html>
How can I display the table vertically?
Put each heading in a new <tr>. Remember, <tr> stands for table row, while <td> is for each of the elements in that row. This will require some modification of your php code so that you can essentially print a new row, and each td within it.
Edit: To display it vertically as you like, you'd need to modify your existing while loop.
//Print the row
echo "<tr>";
//Print the row heading
<th>Application Type</th>
while($row = mysqli_fetch_assoc($query)) {
//Print each matching data type inside
echo " <td>" . $row['applicationtype'] . "</td>";
}
//Close the row
echo "</tr>";
You'll need to do this functionality for each of the headings you have. You could also use arrays along with nested loops to print all the data cleanly and easily without excess code.
If by "vertically" you mean you want to have 2 columns and 24 rows instead of 24 columns and 2 rows, this will do it for you:
echo "<table border='6'>";
while($row = mysqli_fetch_assoc($query)) {
echo "<tr><th>Application Type</th><td>{$row['applicationtype']}</td></tr>";
echo "<tr><th>First Name</th><td>{$row['firstname']}</td></tr>";
echo "<tr><th>Surname</th><td>{$row['lastname']}</td></tr>";
echo "<tr><th>Title</th><td>{$row['title1']}</td></tr>";
echo "<tr><th>Date of Birth</th><td>{$row['dob']}</td></tr>";
echo "<tr><th>Gender</th><td>{$row['gender']}</td></tr>";
echo "<tr><th>Nationality</th><td>{$row['nationality']}</td></tr>";
echo "<tr><th>Country of Birth</th><td>{$row['countryofbirth']}</td></tr>";
echo "<tr><th>Applicant's Location</th><td>{$row['applicantlocation']}</td></tr>";
echo "<tr><th>Alias</th><td>{$row['alias']}</td></tr>";
echo "<tr><th>Criminal</th><td>{$row['criminal']}</td></tr>";
echo "<tr><th>Country of Passport</th><td>{$row['countryofpassport']}</td></tr>";
echo "<tr><th>Passport Number</th><td>{$row['passportnumber']}</td></tr>";
echo "<tr><th>Passport Issue Date</th><td>{$row['pid']}</td></tr>";
echo "<tr><th>Passport Expiry Date</th><td>{$row['ped']}</td></tr>";
echo "<tr><th>Address</th><td>{$row['address']}</td></tr>";
echo "<tr><th>City</th><td>{$row['city']}</td></tr>";
echo "<tr><th>State</th><td>{$row['state']}</td></tr>";
echo "<tr><th>Postal Code</th><td>{$row['postalcode']}</td></tr>";
echo "<tr><th>Country</th><td>{$row['country']}</td></tr>";
echo "<tr><th>Email Address</th><td>{$row['email']}</td></tr>";
echo "<tr><th>Home Number</th><td>{$row['homephone']}</td></tr>";
echo "<tr><th>Business Number</th><td>{$row['businessphone']}</td></tr>";
echo "<tr><th>Mobile</th><td>{$row['mobile']}</td></tr>";
}
echo "</table>";
Additionally, if you are going to be handling such sensitive personal data, you MUST improve your query security starting with mysqli prepared statements using placeholders.
I'm retrieving a table from database as result of a search action, but when I try to display the result I see the table and the data, but the image returned in each row is not render, I think my problem is in the $('#search').html(data), I'm not sure please someone knows what is the problem?
this is the result
http://s9.postimg.org/mro5qn46n/search_result.jpg
****This is the search page, where result table is displayed****
<table align="center">
<tr>
<td>
<label for="criteria">Select Criteria</label>
</td>
<td>
<select name="select" id="criteria">
<option selected="true" style="display:none;"></option>
<option value="value1">name</option>
<option value="value2">apartment</option>
</select>
</td>
<td>
<input type="text" name="value" size="40" maxlength="60" id="value"\>
</td>
</tr>
<tr>
<td>
<input name="name-submit" type="button" id="submit" value="Search"\>
</td>
</tr>
<tr>
<td >
<div id="search"></div>
</td>
</tr>
</table>
<script type="text/javascript" src="../js/jquery-1.11.1.min.js"></script>
<script type="text/javascript">
$('#submit').click(function(){
var criteria = $("#criteria option:selected").text();
var value = $("#value").val();
$.post("search_r.php",{criteria:criteria,value:value},function(data){
$('#search').html(data);
});
});
</script>
****This is the Page that calls $.post() in the main seach page ****
<?php
$criteria = $_POST['criteria'];
$value = $_POST['value'];
$con = mysqli_connect("localhost","root","");
mysqli_select_db($con,"gables");
$query = "SELECT * FROM residents WHERE $criteria = '$value'";
$result = mysqli_query($con,$query);
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Last Name</th>
<th>Apartment</th>
<th>Parking</th>
<th>Phone1</th>
<th>Phone2</th>
<th>image</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['0'] . "</td>";
echo "<td>" . $row['1'] . "</td>";
echo "<td>" . $row['2'] . "</td>";
echo "<td>" . $row['3'] . "</td>";
echo "<td>" . $row['4'] . "</td>";
echo "<td>" . $row['5'] . "</td>";
echo "<td>" . $row['6'] . "</td>";
echo "<td><img src=get_image.php?id=".$row['0']." width=160 height=120/></td>";
echo "</tr>";
}
echo "</table>";
?>
***Here the get_image.php****
<?php
$con = mysqli_connect("localhost","root","");
mysqli_select_db($con,"gables");
$id = $_GET['id'];
$query = "SELECT * FROM residents WHERE id='$id'";
$result = mysqli_query($con,$query);
if($result)
$picture = mysqli_fetch_array($result);
header('Content-Type: image/jpg');
echo $picture['11'];
?>
You can chage the get_image.php file as this. Then this work will work.
<?php
function get_image($id){
$con = mysqli_connect("localhost","root","");
mysqli_select_db($con,"gables");
$query = "SELECT * FROM residents WHERE id='$id'";
$result = mysqli_query($con,$query);
if($result)
$picture = mysqli_fetch_array($result);
return $picture['11'];
}
?>
Then use require_once(); function and in image src like this.echo "<td><img src='".get_image($row['0'])."' width=160 height=120/></td>";. In your code check how the src path will print and it will be print like as echo string, not as a execute the file.
echo
"<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Last Name</th>
<th>Apartment</th>
<th>Parking</th>
<th>Phone1</th>
<th>Phone2</th>
<th>image</th>
</tr>";
require_once('search_r.php');
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['0'] . "</td>";
echo "<td>" . $row['1'] . "</td>";
echo "<td>" . $row['2'] . "</td>";
echo "<td>" . $row['3'] . "</td>";
echo "<td>" . $row['4'] . "</td>";
echo "<td>" . $row['5'] . "</td>";
echo "<td>" . $row['6'] . "</td>";
echo "<td><img src='".get_image($row['0'])."' width=160 height=120/></td>";
echo "</tr>";
}
echo "</table>";
I am stuck in one of my application module. I have to set multiple delete options in my application.
I have used the below code. The designing is perfectly fine. All what I want to add multiple delete options in it.
Below is the code which I have tried out:
<html>
<head>
<title>Strad Hosting Limited -Web Hosting</title>
<script language="javascript">
function validate()
{
var chks = document.getElementsByName('checkbox[]');
var hasChecked = false;
for (var i = 0; i < chks.length; i++)
{
if (chks[i].checked)
{
hasChecked = true;
break;
}
}
if (hasChecked == false)
{
alert("Please select at least one.");
return false;
}
return true;
}
</script>
</head>
<body >
<?php
$con=mysqli_connect("localhost","stradsol","D#v,b5TnQ!D!","stradsol_sales");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<form name='form1' method='post' action='' onSubmit='return validate();'>";
echo "<table border='1' style='
background-color: white;'>
<tr>
<th></th>
<th>id</th>
<th style='padding-left: 11px;'>Lead Generated Date </th>
<th>name</th>
<th>email</th>
<th>contacts</th>
<th>requirement</th>
<th style='display:none;'>Company name</th>
<th style='display:none;'>Address</th>
<th>Next Follow-Up date</th>
<th>Final_Details</th>
<th style='display:none;'>Status</th>
<th style='padding-left: 12px; display:none;'>Lead Closed Date</th>
<th>EDIT</th>
<th>Follow-up History</th>
<th>Add Follow-up</th>
<th>Delete Record</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input name='checkbox[]' type='checkbox' id='checkbox[]' value='".$rows['id']."'></td>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td><a href='config_info.php?id=" . $row['id'] . "'>".$row['name']."</a></td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['contacts'] . "</td>";
echo "<td>" . $row['requirement'] . "</td>";
echo "<td style='display:none;'>" . $row['company_name'] . "</td>";
echo "<td style='display:none;'>" . $row['address'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['final_details'] . "</td>";
echo "<td style='display:none;'>" . $row['status'] . "</td>";
echo "<td style='display:none;'>" . $row['lead_close'] . "</td>";
echo "<td><a href='edit_eg1.php?id=" . $row['id'] . "'>Edit</a></td>";
echo "<td><a href='Follow_history.php?id=" . $row['id'] . "'>Follow_history</a></td>";
echo "<td><a href='add_follow.php?id=" . $row['id'] . "'>Followup</a></td>";
echo "<td><a href='delete.php?id=" . $row['id'] . "'>Delete</a></td>";
echo "</tr>";
}
echo "<tr><td><input name='delete' type='submit' id='delete' value='Delete'></td></tr>";
$count=mysqli_num_rows($result);
if(isset($_POST['delete'])){
for($i=0;$i<count($_POST['checkbox']);$i++){
$del_id=$_POST['checkbox'][$i];
$sql = "DELETE FROM Persons WHERE id='$del_id'";
echo $sql;
$result2 = mysqli_query($con,$sql);
}
// if successful redirect to delete_multiple.php
if($result2)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=edit_table_del.php\">";
}
}
mysqli_close($con);
echo "</table>";
echo "</form>";
?>
<br><br>
[ Back To Home ]
</body>
</html>
I am stuck, the query is not working I think. I don't know what I am missing.
Try replacing
$sql = "DELETE FROM Persons WHERE id='$del_id'";
With
$sql = "DELETE FROM Persons WHERE id=$del_id";
I'm assuming the ID is a number so the single quotes aren't needed.
I'm trying to display members from my database using PHP, however the last name goes in with the first name and I'm not quite sure why... Could anyone point me in the right direction?
<?php
$mysql_db_hostname = "localhost";
$mysql_db_user = "alex";
$mysql_db_password="";
$mysql_db_database="gym";
$con = mysql_connect($mysql_db_hostname, $mysql_db_user, $mysql_db_password) or die("Could not connect database");
mysql_select_db($mysql_db_database, $con) or die("Could not select database");
$query = mysql_query("select * from users WHERE Category='Member'");
echo "<table border=1>
<tr>
<th>Users ID</th>
<th>First Name</th>
<th>Last Name</th>
</tr>";
while($row =mysql_fetch_assoc($query))
{
echo "<tr>";
echo "<td>" . $row['user_id']."<br>" . "</td>";
echo "<td>" . $row['First_Name']."<br>" . "</td";
echo "<td>" . $row['Last_Name']."<br>" . "</td";
echo "</tr>";
}
echo "</table";
?>
You aren't closing the tags. Syntax highlighter would show the error.
while($row =mysql_fetch_assoc($query))
{
echo "<tr>";
echo "<td>" . $row['user_id']."<br>" . "</td>";
echo "<td>" . $row['First_Name']."<br>" . "</td"; <-----------
echo "<td>" . $row['Last_Name']."<br>" . "</td"; <------------
echo "</tr>";
}
You are not closing your <td> tags properly
echo "<td>" . $row['First_Name']."<br>" . "</td>";
//^here
echo "<td>" . $row['Last_Name']."<br>" . "</td>";
//^and here
So the output is all one cell with both variables printed inside
You forgot to close the td on your first name field.
Just change
</td
to
</td>
I have trouble with creating an approval form as am still php beginner,
the idea is
user submit a form am setting a default value"0" in the approved row at the table..
so behind the scenes the admin shows all members from this table where approved="0"
and this is the code
<code>
<?php
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</code>
I just want to add checkbox for every table user and when checked thier status changed to 1 in approved column
thanks all
$con = mysql_connect("localhost","ebarea_epic","...");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ebarea_epic", $con);
$query = "select * from medicalrep where approved='0'";
$result=mysql_query($query);
$i = 1; //counter for the checkboxes so that each has a unique name
echo "<form action='process.php' method='post'>"; //form started here
echo "<table border='1'>
<tr>
<th>User Name</th>
<th>Password</th>
<th>Mobile </th>
<th>Address</th>
<th>Faculty</th>
<th>Graduation Year</th>
<th>Region</th>
<th>Area</th>
<th>Line</th>
<th>Appointment Date</th>
<th>Resign Data</th>
<th>Job Title</th>
<th>Update</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['username'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['Mobile'] . "</td>";
echo "<td>" . $row['Address'] . "</td>";
echo "<td>" . $row['Faculty'] . "</td>";
echo "<td>" . $row['Graduation Year'] . "</td>";
echo "<td>" . $row['Region'] . "</td>";
echo "<td>" . $row['Line'] . "</td>";
echo "<td>" . $row['Area'] . "</td>";
echo "<td>" . $row['Appointment'] . "</td>";
echo "<td>" . $row['Resign'] . "</td>";
echo "<td>" . $row['job_title'] . "</td>";
echo "<td><input type='checkbox' name='check[$i]' value='".$row['ID']."'/>";
echo "</tr>";
$i++;
}
echo "</table>";
echo "<input type='submit' name='approve' value='approve'/>";
echo "</form>";
mysql_close($con);
Now comes process.php
if(isset($_POST['approve'])){
if(isset($_POST['check'])){
foreach ($_POST['check'] as $value){
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die (mysql_error());
}
}
}
though you are using mysql_* functions here, i recommend you to use PDO
EDIT:
As per your request, this is the update.
Change this code in your admin panel script:
echo "<input type='submit' name='approve' value='approve'/>";
Delete the above line and add this instead:
echo "<input class='action' type='button' name='approve' value='approve' />";
echo "<input class='action' type='button' name='edit' value='edit' />";
echo "<input class='action' type='button' name='delete' value='delete' />";
echo "<input type='hidden' name='action' value='' id='action' />"; //Action (edit, approve or delete) will be set here which will be passed as POST variable on form submission
Now you will need some javascript to do some tricks.
Add the following code preferably head section in your admin panel script
<script type="text/javascript" src="jquery-1.7.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('.action').click(function(){
var action = $(this).attr('name');
$('#action').val(action);
$(this).closest('form').submit();
})
})
</script>
Now comes the modification in process.php file
if (isset($_POST['approve'])) {
if (isset($_POST['check'])) {
foreach ($_POST['check'] as $value) {
$sql = "UPDATE post SET post_approved = 1 WHERE ID = $value"; //write this query according to your table schema
mysql_query($sql) or die(mysql_error());
}
}
} elseif(isset($_POST['edit'])){
//do the edit things here
} elseif(isset($_POST['delete'])){
foreach ($_POST['check'] as $value){
$sql = "DELETE FROM post WHERE ID=$value";//modify it
mysql_query($sql) or die(mysql_error());
}
}
NOTE
You may not want to mutiple checkbox for edit. You just need to tweak the javascript code above a little and it'l send the ID as a post variable on form submission from which you can retreive the details for one entry and then edit functions will come. I'l leave it to you. try it, post your trial code here and i'l give you a solution if it doesn't work.