I'm trying to filter some car parts depending on the categories they are related to.
A part can have many categories (in the code they are called tags), so I chose the HABTM relation with a join table.
Filtering works so far, but only with an OR condition with cake using the SQL command IN.
But I'm trying to filter only the parts that have all the selected categories, so I need to use an AND condition on the category array.
Here's the extracted code from the controller:
$this->Part->bindModel(array('hasOne' => array('PartsTagsJoin')));
$params['conditions'] = array('AND' => array('PartsTagsJoin.tag_id' => $selectedCats));
$params['group'] = array('Part.id');
$parts = $this->Part->find('all',$params);
$this->set('parts',$parts);
$selectedCats is an array like this: array(1,2,3,4,5);
The SQL output is:
'SELECT `Part`.`id`, `Part`.`name`, `Part`.`image`, `Part`.`image_dir`, `Part`.`time_created`, `Part`.`time_edited`, `Part`.`user_id`, `Part`.`editor_id`, `Part`.`notice`, `User`.`id`, `User`.`username`, `User`.`password`, `User`.`usergroup_id`, `User`.`realname`, `PartsTagsJoin`.`id`, `PartsTagsJoin`.`part_id`, `PartsTagsJoin`.`tag_id`
FROM `c33rdfloor`.`parts` AS `Part`
LEFT JOIN `c33rdfloor`.`users` AS `User` ON (`Part`.`user_id` = `User`.`id`)
LEFT JOIN `c33rdfloor`.`parts_tags_join` AS `PartsTagsJoin` ON (`PartsTagsJoin`.`part_id` = `Part`.`id`)
WHERE `PartsTagsJoin`.`tag_id` IN (1, 4, 8, 24)'
How can I filter the parts that have every id that is committed through the $selectedCats Array.
Thank you in advance for your help.
I've got it working thanks to this blog post:
http://nuts-and-bolts-of-cakephp.com/2008/08/06/habtm-and-join-trickery-with-cakephp/
It seems to be a little tricky to filter entries with all selected tags:
The key in achieving an AND relation is to get the count of the selected cats and match it with the ones of the query inside the group parameter.
This line did it:
$params['group'] = array('Part.id','Part.name HAVING COUNT(*) = '.$numCount);
In the End the code looked like this (for people interested in a solution):
// Unbinds the old hasAndBelongsToMany relation and adds a new relation for the output
$this->Part->unbindModel(array('hasAndBelongsToMany'=>array('PartsTag')));
$this->Part->bindModel(array('hasOne'=>array(
'PartsTagsJoin'=>array(
'foreignKey'=>false,
'type'=>'INNER',
'conditions'=>array('PartsTagsJoin.part_id = Part.id')
),
'PartsTag'=>array(
'foreignKey'=>false,
'type'=>'INNER',
'conditions'=>array(
'PartsTag.id = PartsTagsJoin.tag_id',
'PartsTag.id'=>$selectedCats
)))));
$numCount = count($selectedCats); // count of the selected tags
// groups the entries to the ones that got at least the count of the selected tags -> here the 'AND' magic happens
$params['group'] = array('Part.id','Part.name HAVING COUNT(*) = '.$numCount);
$parts = $this->Part->find('all', $params); // sends the query with the params
$this->set('tagCategories', $categories);
$this->set('selectedCats', $selectedCats);
$this->Part->recursive = 4;
$this->set('parts',$parts);
Related
SELECT i.itemsname
, i.itemsprice
, i.itemsdescrip
, c.catname
, c.catdes
, c.status
, c.collapse
, c.catid
FROM items i
LEFT
JOIN categories c
ON c.catid = i.catid
WHERE i.restid
AND c.restid =12
GROUP
BY c.catid
that is my query at the moment but I would like to have something like this....
but this is what I'm getting:
Ok, I lied in the comments, so With PDO (haven't tested it)
$stmt = $PDO->prepare('SELECT
categories.catname,
items.itemsname,
items.itemsprice,
items.itemsdescrip,
categories.catdes,
categories.status,
categories.collapse,
categories.catid
FROM items
LEFT JOIN categories ON items.catid=categories.catid
WHERE items.restid AND categories.restid = :restid');
$stmt->execute([':restid' => 12]);
$data = $stmt->fetchAll(\PDO::FETCH_GROUP);
foreach($data as $catname => $rows){
//echo group html stuff
//echo "<dl>";
//echo "<dt>$catname</dt>".;
foreach($rows as $row){
//echo row data stuff
// echo "<dd> {stuff} </dd>";
}
//echo "</dl>";
}
I'll leave the html up to you. But as I said you want a data structure like this
[
'BREAKFASTS' => [
0 => [ name => "wimpy hamburger", description => "bla bla", price => "$100,000"],
1 => [ ... ]
],
'SINGLE BURGERS' => [ ...]
]
note that the first field after "SELECT" is by default the field used by FETCH_GROUP
See in this way, the first foreach can output the title of the category, which is BREAKFASTS for example. Then the inner foreach can do the individual rows in the table.
Personally I would use a dl, dt, dd tag setup as my structure (hinted in the comments, i really am to lazy today to code all the html, <sigh>)
https://www.w3schools.com/tags/tag_dt.asp
UPDATE
You may want to check your query
...
WHERE
items.restid AND ...
Seems to be flawed, just saying. I saw this while optomizing the query for sorting.
SELECT
c.catname,
i.itemsname,
i.itemsprice,
i.itemsdescrip,
c.catdes,
c.status,
c.collapse,
c.catid
FROM
(
SELECT c0.catid FROM categories AS c0 WHERE c0.restid = :restid SORT BY c0.catname
) AS t
JOIN
categories AS c ON t.catid=c.catid
LEFT JOIN
items AS i ON items.catid=categories.catid
WHERE
items.restid = ? //< this is the error/omission/strangeness i pointed out above.
So a few things to note, first you should base the query off the categories, as an empty category should be shown, while an item without a category will blow it all to bits ( basically, ie how can you group them by the category if they have none ) You'll wind up with some hodgepoge of items with no category at the end, of course based on your example I'm assuming a Many to One relationship. For example One category can have Many items, and Many items can belong to a category. (it's probably more ideal to do a Many to Many, but that's another story for another day)
The reason the above query is more optimized is the inner query, creates only a small temp table using the catid, And sorts on just the data from the cat table and only the data that is pulled by the where.
Then as we move to the outer query, they basically inherent the sort from the join, and we can pull the rest of the data from that. It's typically about 2-10x faster this way (of course I haven't test this particular query) in theory. Of course this is a bit more complex/advanced query and is optional, but it should improve sort performance if my mind is in the right place tonight... lol
Also I abbreviated your table names (alias), as I said I am lazy like that. Sadly my answers are always so long, dont ask me how I see all these issues, it's just experience or how my dyslexic brain works?
Lastly, if you really must use mysqli, you can manually group them with something like this.
$data = [];
while(false !== ($row = $res->fetch_assoc())){
$key = $row['catname'];
if(!isset($data[$key])) $data[$key] = [];
$data[$key][] = $row;
}
It's all so prosaic (common place, non-poetic) at this point for me.
Good luck.
$cat = mysqli_query($connect, "SELECT
categories.catname,
items.itemsname,
items.itemsprice,
items.itemsdescrip,
categories.catdes,
categories.catid
FROM items
LEFT JOIN categories ON items.catid=categories.catid
WHERE items.restid AND categories.restid = 12");
if($cat === FALSE) {
die(mysqli_error());
}
$data = [];
while ($rowb = mysqli_fetch_array($cat)) {
$key = $rowb['catname'];
if(!isset($data[$key])) $data[$key] = [];
$data[$key][] = $rowb;
foreach($data as $catname => $rowbs){
echo "
<dl><button class='accordiontry'><dt>$catname</dt></button>";
<div class='panel1'>
foreach($rowbs as $rowb){
echo"<div class='rmenu'>
<dd><span class='item'>{$rowb['itemsname']}</span>
<span class='price'>£{$rowb['itemsprice']}</span><br>
<span class='des'>{$rowb['itemsdescrip']}</span> ";
}
echo"</div></dd>
</div></dl>";
}
}
}
I have two tables called mg_product and mg_product_user_property.
In mg_product there are 3 columns: id, title, price as
In mg_product_user_property table product_id corresponds with id column in mg_product table.
So my goal is to get the value of property_id of "15", which in the picture above will be "Mediatek".
This is my SQL:
$sql = "SELECT *
FROM mg_product AS products
INNER JOIN mg_product_user_property AS properties
ON products.id = properties.product_id
WHERE title LIKE '%$search%')";`
PHP:
$resultSet = DB::query($sql);
if ($resultSet->num_rows > 0) {
while ($rows = $resultSet->fetch_assoc()) {
$title = $rows['title'];
$price = $rows['price'];
}
} else {
$output = "No results";
}
Now I need to assign to a php variable the value of property_id=15 so I will be able to print "Mediatek" on my website. How can I achieve that? Sorry for my English.
You are pretty close to what you want, but a couple things are going to either be a mess, or unwanted. So, since there are different ways one can go with this, I will only present a very stripped example (and am INTENTIONALLY leaving out a bunch of code here).
You may not want to do a JOIN like that in the initial search, as for each property, it will also return another of the same product. So looping through that will result in dozens of the same product.
However, if _ALL_YOU_WANT_ is to show the Product Title, Price, and Property 15... you can reduce some headwork with a simpler query:
SELECT p.title, p.price, pr.value
FROM mg_product AS p
LEFT JOIN mg_product_user_property AS pr
ON p.id = pr.product_id AND pr.property_id = 15
WHERE p.title LIKE '%$search%'
The LEFT JOIN means if the property doesn't exist, it will still return the product. But with an empty property value. And this should not return dozens of the same product for every other property in the table.
--
The OTHER way you could go about doing it, using the SQL query you already have (and the dozens of results of the same product it will return), you can alter your php loop like so:
$found_products = array();
while ($row = $resultSet->fetch_assoc()) {
if ($row['property_id'] == 15) {
$found_products[$row['product_id']] = array(
'title' => $row['title'],
'price' => $row['price'],
'prop' => $row['value']
);
}
}
// now you have a clean array of found products that have the property
--
Also I am forced to point out that you should use a prepared statement here, replacing inserting $search directly into the code. But showing you all of how to do that is beyond the scope of this question/answer.
In my events calendar module for Silverstripe 3.1, i have added some additional fields to CalendarEvent. I want to make use of these in my template, but from my researches i have seen that events are exported as being CalendarDateTime so i can't use my additional fields.
I have found that in getStandardEvents function, there is a inner join which i think is causing the problem, but i can't figure it out to join the columns from CalendarEvent
$list = DataList::create('CalendarDateTime')
->filter(array(
'EventID' => [139, 140, 141, 143]
))
->innerJoin('CalendarEvent', "EventID = \"{CalendarEvent}\".\"ID\"")
->innerJoin("SiteTree", "\"SiteTree\".\"ID\" = \"{CalendarEvent}\".\"ID\"")
->where("Recursion != 1");
Note: In my code, i have some of the columns as variables, so i have written them as the values that are reffering to.
Here is the original code:
$list = DataList::create($datetimeClass)
->filter(array(
$relation => $ids
))
->innerJoin($eventClass, "$relation = \"{$eventClass}\".\"ID\"")
->innerJoin("SiteTree", "\"SiteTree\".\"ID\" = \"{$eventClass}\".\"ID\"")
->where("Recursion != 1");
I have tried to add the 'CalendarEvent' as a second parameter inside DataList::create(), but no result. I have the same output.
So how can i select columns from CalendarDateTime and CalendarEvent tables ?
Any help would be appreciated.Thanks
I have found a manual way:
$list = DB::query('SELECT * FROM "CalendarDateTime" INNER JOIN "CalendarEvent" ON "EventID" = "CalendarEvent"."ID" INNER JOIN "SiteTree" ON "SiteTree"."ID" = "CalendarEvent"."ID" WHERE "Recursion" != 1');
Any other solutions are welcome.
I'm new at Laravel and have a question about combining 2 JOIN results.
At first, I have the following tables:
videos: id, approved
videos_languages: video_id, language_id, name
Now I do the following:
$arr = Video::join("videos_languages","video_id","=","videos.id")->whereRaw("approved = 0")->get();
Then I pass the array to my view.
I get the values, but now have double results, if one video has more than 1 language. Is it possible, to combine the results of that join with Laravel into one result?
Example:
$arr[0]['id'] = 5;
$arr[0]['approved'] = 0;
$arr[0]['videos_langauges][0] =
{
'name' = ...
}
$arr[0]['videos_langauges][1] =
{
'name' = ...
}
Thank you :)
$arr = Video::distinct()->join("videos_languages","video_id","=","videos.id")->where("approved", 0)->get();
That should clean up duplicates from your results. Also note where() instead of whereRaw().
My Models are related as follows:
Post BELONGS_TO Parent
Parent HAS_MANY ParentAdmin
Now I wish to find all Parent admins of all post if a post's attribute's value is met. The equivalent sql query is :
SELECT parent_admins.* FROM posts
LEFT JOIN parents AS Parent ON Parent.id = posts.target_id
LEFT JOIN parent_admins ON parent_admins.parent_id = Parent.id
WHERE posts.admin_notification = 0 AND Parent.maxtime > posts.created
Assuming Models are linked in cakephp accordingly and recursive = 2, what will be the condition array in find query?
You can both use the bindModel & unbindModel methods to get the exact query you want or you can use the Containable behavior.
More information about how to create and destroy associations on the fly with CakePHP: http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#creating-and-destroying-associations-on-the-fly
And you'll need this array of conditions:
$conditions = array(
'Post.admin_notification' => 0,
'Parent.maxtime >' => 'Post.created'
);
according to your query :-
$conditions=array(
'posts.admin_notification'=>0,
'Parent.maxtime >'=>'posts.created'
);
If your query do the job:
Inside PostsController:
$query = "SELECT parent_admins.* FROM posts
LEFT JOIN parents AS Parent ON Parent.id = posts.target_id
LEFT JOIN parent_admins ON parent_admins.parent_id = Parent.id
WHERE posts.admin_notification = 0 AND Parent.maxtime > posts.created"
$result = $this->Posts->query($query);
$debug($result);