PHP JSON and Twitter - php

<?
$Tweet = file_get_contents("http://api.twitter.com/1/statuses/user_timeline.json?screen_name=EdVizenor&count=1");
//$Tweet = explode(",",$Tweet);
/// If I explode and echo the $Tweet(3); i get .... "text":"mY LATEST TWEET"
var_dump(json_decode($Tweet,true));
?>
What I want to do is parse out the array via key. Something like:
echo $Tweet(text); /// but this does not work.


It would be helpful to know what the error is. The problem is that $Tweet(text) would be calling a function contained in $Tweet, since that variable is not a function, but an actual array, you actually just have to
<?php
// your code
$tweets = json_decode($Tweet,true);
echo $tweets[0]['text'];
Next time, be sure to include the error being thrown, it is very helpful for you to read and understand those!

Related

Get specific string out of array (Gravatar)

I was wondering on how to get a specific string out of an array within this document:
https://gravatar.com/205e460b479e2e5b48aec07710c08d50.php
I was working with the example given on the Gravatar page and started to get used to the following line:
$profile['entry'][0]['preferredUsername'];
The complete document (of mine) now looks like this so far:
<?php
error_reporting(error_reporting() & ~E_NOTICE);
$str = file_get_contents('https://www.gravatar.com/'.$_GET['hash'].'.php');
$profile = unserialize($str);
if (is_array($profile) && isset($profile['entry']))
echo $profile['entry'][0]['name'];
echo $profile['entry'][0]['preferredUsername'];
?>
My problem is how to figure out how to get the name and last name using this line:
echo $profile['entry'][0]['name'];
All I get by typing this single line is "Array".

$profile['entry'][0]['name'] is indeed an array. If you want the formatted name you should access $profile['entry'][0]['name']['formatted']

How can I sanitise the explode() function to extract only the marker I require?

I have some php code that extracts a web address. The object I have extracted is of the form:
WEBSITE?flage=2&fgast=48&frat=1&sort=D&fsrc=2&wid=bf&page=1&id=16123012&source=searchresults
Now in PHP I have called this object $linkHREF
I want to extract the id element only and put it into an array (I'm bootstrapping this process to get multiple id's)
So the command is:
$detailPagePathArray = explode("id=",$linkHREF); #Array
Now the problem is the output of this includes what comes after the id tag, so the output looks like:
echo $detailPagePathArray[0] = WEBSITE?flage=2&fgast=48&frat=1&sort=D&fsrc=2&w
echo $detailPagePathArray[1] = bf&page=1&
echo $detailPagePathArray[2] = 16123012&source=searchresults
Now the problem is obvious, where it'd firstly picking up the "id" in the "wid" marker and cutting it there, however the secondary problem is it's also picking up all the material after the actual "id". I'm just interested in picking up "16123012".
Can you please explain how I can modify my explode command to point it to the particular marker I'm interested in?
Thanks.

Use the built-in functions provided for the purpose.
For example:
<?php
$url = 'http://www.example.com?flage=2&fgast=48&frat=1&sort=D&fsrc=2&wid=bf&page=1&id=16123012&source=searchresults';
$qs = parse_url($url);
parse_str($qs['query'], $vars);
$id = $vars['id'];
echo $id; // 16123012
?>
References:
parse_url()
parse_str()

if you are sure that you are getting &id=123456 only once in your object, then below
$linkHREF = "WEBSITE?flage=2&fgast=48&frat=1&sort=D&fsrc=2&wid=bf&page=1&id=16123012&source=searchresults";
$str = current(explode('&',end(explode('&id', $linkHREF,2))));
echo "id" .$str; //output id = 16123012

json encode using php not able to get [] brackets

here is my code
<?
include '../dbConnect.php';
$amp=trim($_POST['amp']);
//$amp='AMP8';
//$sql=mysql_query("select tblRepairQueue.ackNo,tblRepairQueue.repairStatus,tblRepairQueue.savedAt from tblRepairQueue,AMPcustomers where AMPcustomers.phone1=tblRepairQueue.phoneNo and AMPcustomers.id='".$amp."'");
$sql=mysql_query("select phone1 from AMPcustomers where id='".$amp."'");
$response = array();
while($row=mysql_fetch_array($sql))
{
$sql_query=mysql_query("select ackNo,repairStatus,savedAt from tblRepairQueue where phoneNo='".$row['phone1']."'");
while($row1=mysql_fetch_array($sql_query)){
$ackNo=$row1['ackNo'];
$repairStatus=$row1['repairStatus'];
$savedAt=$row1['savedAt'];
$response[]=array('ackNo'=>$ackNo,'repairStatus'=>$repairStatus,'savedAt'=>$savedAt);
}}
print json_encode($response);
?>
output m getting as
{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
but i want the output to look like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]
Can anyone plz help in finding the mistake or what has to be done to get square brackets at the end

This is a bit strange because I have this code:
<?php
$array = array();
$array[] = array("ackNo"=>"26101211236759","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 00:55:25");
$array[] = array("ackNo"=>"26101211236780","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 10:55:25");
echo json_encode($array);
?>
And I get this correct form:
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"26101211236780","repairStatus":"Closed and Complete","savedAt":"2012-10-26 10:55:25"}]

This code should indeed output [{...},...]. So we can't really tell you what went wrong on your side. check the structure of the $response variable before the conversion to Json to see what went wrong.
Note that the code allows SQL injection. You must change it so that the parameters $amp and $row['phone1'] are escaped in the SQL queries. Even if you're relying on magic qoutes now, this solution is not future-proof (now-proof really) as support for this is was removed in PHP 5.4.

What you have written should work:
http://ideone.com/ErV9fr
// How many to add
$response_count=3;
// Your response, just templated
$response_template=array(
'response_number'=>0,
'ackNo'=>'dffdgd',
'repairStatus'=>'$repairStatus',
'savedAt'=>'$savedAt'
);
// Your empty response array
$response = array();
for($i=0;$i<$response_count;$i++) {
$response_template['response_number'] = $i; // Set the 'response number' to the itteration.
$response[]= $response_template; // Add the template to the collection
}
print json_encode($response);
Result:
[{"response_number":0,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":1,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":2,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"}]
In addition to this, you should sanitize your $amp variable. In it's current form it would be trivial for a user to escape your query and execute an arbitrary query against your DB.
http://www.php.net/manual/en/mysqli.real-escape-string.php

Please recheck it can not give you the output like that {"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
as it is creating an array of array so it can not print like that.
It will always print like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]

PHP Undefined Offset unless printed out

While trying to read data from a socket ran the following code through the interpreter:
function get_song_title($stream){
$song;
$sc_return = array();
$sc_return = explode("\r\n",$stream);
$song = $sc_return[4];
return $song;
}
This will succeed in getting the information I need 20% of the time maybe.
However when I do:
function get_song_title($stream){
$song;
$sc_return = array();
$sc_return = explode("\r\n",$stream);
echo $sc_return[4];
$song = $sc_return[4];
return $song;
}
it will succeed 100% of the time. Any method to print the array(or its elements) out will make it to work without a problem. If I simply to try return it or assign it the undefined offset 4 message comes up.
this also includes using print_r($sc_return); which will always succeed.
Any ideas why I would need to print the array element out for it to succeed all the time?

not sure about why you need echo / print out to work, but...
try to do
var_dump($sc_rturn);
to see what you are getting.
also to check for undefined index, you should do
isset($sc_return[4]);
also you can count your results using
count($sc_return);

Using Simple HTML DOM to extract an 'a' URL

I have this code for scraping team names from a table
$url = 'http://fantasy.premierleague.com/my-leagues/303/standings/';
$html = #file_get_html($url);
//Cut out the table
$FullTable = $html->find('table[class=ismStandingsTable]',0);
//get the text from the 3rd cell in the row
$teamname = $FullTable->find('td',2)->innertext;
echo $teamname;
This much works.. and gives this output....
Why Always Me?
But when I add these lines..
$teamdetails = $teamname->find('a')->href;
echo $teamdetails;
I get completely blank output.
Any idea why? I am trying to get the /entry/110291/event-history/33/ as one variable, and the Why Always Me? as another.

Instead do this:
$tdhtml = DOMDocument::loadHTML($teamdetails);
$link = $tdhtml->getElementsByTagName('a');
$url = $link->item(0)->attributes->getNamedItem('href')->nodeValue;

$teamdetails = $teamname->find('a')->href;
^^^^^^^^^---- never defined in your code
I also fail to see how your "works" code could possibly work. You don't define $teamname in there either, so all you'd never get is the output of a null/undefined variable, which is...no output all.

Marc B is right, I get that you don't have to initialize a variable, but he is saying you are trying to access a property of said variable:
$teamdetails = $teamname->find('a')->href;
^^^^^^^^^---- never defined in your code
This is essentially:
$teamname = null;
$teamname->find('a')->href;

The problem in your example is that $teamname is a string and you're treating it like a simple_html_dom_node

Categories