coding to check the data with array Intersect - php

Question

I wanted to check to enter data into the database.Checks are as follows
$implode1 = "cat, dog, chicken";
$implode2 = "cow, goat, cat";
If the cat in the variable $implode1 is also contained in the variable $implode2, it should display a warning message. How to code for the above problem?
Help me please :(

Answer 1

You could explode your strings to arrays, then use array_intersect to return the values which are present in both, eg:
$string1 = 'cat, dog, chicken';
$string2 = 'cow, goat, cat';
$compare = explode(', ', $string1);
$against = explode(', ', $string2);
$matches = array_intersect($compare, $against);

Answer 2

$implode1 = "cat, dog, chicken";
$implode2 = "cow, goat, cat";
$imp1 = explode(', ',$implode1);
$imp2 = explode(', ',$implode2);
foreach($imp1 as $val){
if(in_array($val,$imp2)) {
echo "$val is present in $implode2";
}
}

Answer 3

loop the first array and check if any element is present in the second - something like this:
foreach($implode1 as $val){
if(in_array($val,$implode2)) {
echo "$val is exists in the implode2 array";
}
}
ohh, sorry, those are just strings. First explode them:
arr_implode1 = explode(", ",$implode1)
arr_implode1 = explode(", ",$implode2)

Answer 4

You could just check before inserting the values into a database if they already exist:
if not exists (select * from TestTable where column NOT IN {$implode})
begin
...Do something here!!
end

Answer 5

Create yourself a function that is able to extract the values out of each string in form of an array, then get the intersection. If it is not FALSE, there is an intersection, so do the warning:
$values = function($string) {
return explode(', ', $string);
};
if (array_intersect($values($implode1), $values($implode2))) {
trigger_error('Values intersect', E_USER_WARNING);
}
See it in action.