$query2 = "SELECT * FROM `Listing` WHERE listingid = '{$myID}'";
if(!($result2 = # mysql_query($query2,$connection)))
echo "query failed<br>";
$result_array = array();
while($row2 = mysql_fetch_assoc($result2))
{
$result_array[] = $row2;
}
foreach ($result_array as $key => $val) {
echo "$key = $val\n";
}
Listing (Table) has 7 fields.
I get a bunch of "0 = Array"
How do I store mysql query results into php array and display them?
I want to have it as array first so i can sort them.
You are actually storing them. The code you have listed is storing them in array of arrays to see them you can modify the for with:
foreach ($result_array as $key => $val) {
echo "$key = " . print_r($val, true) . "\n";
}
$val is actually an array containing all the fields of a row.
Related
I managed to add multiple data in one column in the database, but now I need to display it with a new line in the browser so they don't stick with each other as I display them as an array in one column.
Here is my code:
if (isset($_GET['id']) && $_GET['id'] == 5) {
$subArray = array("StudentAnswer");
$subId6 = $db->get("answertable", null, $subArray);
foreach ($subId6 as $sub) {
$answers[] = $sub['StudentAnswer'] . "\n";
}
foreach ($answers as $row) {
$answers2 = explode("||", $row[0]);
foreach($answers2 as $row2){
$answers3 = $row2 . '\n';
}
}
$db->where('AccessId', $_GET['token']);
$db->where('StudentAnswer', $answers3);
$subId8 = $db->get("answertable");
if ($subId8) {
echo json_encode($subId8);
}
}
You are overriding $subId6 after getting its content. Try to fetch the table $rows in a new variable and the extract the content from it, like the code below.
<?php
// Example of $subId6 content
$subId6 = array(["StudentAnswer" => ["Answer 1\nAnswer 2\nAnswer 3"]], ["StudentAnswer" => ["Answer 1\nAnswer 2\nAnswer 3"]]);
// Fetch rows
foreach ($subId6 as $sub) {
$rows[] = $sub['StudentAnswer'];
}
// Decode rows
foreach($rows as $row) {
$answers = explode("\n", $row[0]);
echo "New answers: \n";
// Split answers in single answer
foreach ($answers as $answer)
echo "$answer \n";
echo "\n";
}
You will have a list of all the answers split for table rows
If you want a string of answers seperated by a space then simply do
if (isset($_GET['id']) && $_GET['id'] == 5) {
$subId6 = $db->get("answertable");
foreach ($subId6 as $sub) {
$answers .= $sub['StudentAnswer'] . ' ';
}
$answers= rtrim($answers, ' '); //remove last space in case thats an issue later
$db->where('AccessId', $_GET['token']);
$db->where('StudentAnswer', $answers);
$subId8 = $db->get("answertable");
if ($subId8) {
echo json_encode($subId8);
}
}
The following code returns the field names of a result set. I also want it to return the values. How can I do this?
while ($row = mysqli_fetch_assoc($result)) {
foreach( $row as $field => $name) {
echo $field."<br>";
}
}
If we assume that your array looks like this:
$row["first_name"] = "John";
$row["last_name"] = "Doe";
$row["username"] = "john.doe";
Using this code:
while ($row = mysqli_fetch_assoc($result)) {
foreach( $row as $field => $value) {
echo "{$field} - {$value}<br>";
}
}
You will get an output like this:
first_name - John
last_name - Doe
username - john.doe
When you iterate through an array, using => operator, you are iterating in a "key-value" pair style. Every iteration holds the key and value as you can see.
Take a look at foreach for more information.
you are getting the value in $name variable
foreach( $row as $field => $name) {
echo $field . " = " . $name . "<br>";
}
I'm pulling 3 colummns from one table and storing them in an array as such to populate a dropdown menu. The ref_code is used to decide which dropdown it will go to ('Module','Customer','Application') while id is the select value and ref_desc is the display text.
foreach ($test as $t) {
$aa[] = array($t->ref_code => array('id'=>$t->id, 'ref_desc'=>$t->ref_desc));
};
I've been trying to retrieve them using $aa['ref_code'] but have not been getting any success. Help please.
This question is similar, but I am unable to retrieve the values I want.
I found a solution on another forum but I will also give your solutions a try later. Thank you very much!
foreach ($aa as $a => $d) {
foreach ($d as $ref_code => $dd) {
echo "<p>". $ref_code ."</p>";
echo "<p>". $dd['ref_desc'] ."</p>";
echo "<p>". $dd['id'] ."</p>";
};
};
Why don't you write it like this? The ref_code (if it's unique) is the key of the array.
foreach ($test as $t) {
$aa[$t->ref_code] = array('id'=>$t->id, 'ref_desc'=>$t->ref_desc);
};
you need a three dimensional array:
dropdown => ids => displaytext
here we go:
// fill in:
$aa = array();
foreach ($test as $t) {
if ( !isset($aa[$t->ref_code]) )
$aa[$t->ref_code] = array();
$aa[$t->ref_code][$t->id] = $t->ref_desc;
};
// have a drop down:
$myDropDown = 'Customer';
foreach ( $aa[$myDropDown] as $id => $displaytext )
{
echo "<option value=\"" . $id . "\">" . $displaytext . "</option>";
}
.... etc.
below is a php object which is retrieving some values from mysql db through a php method
$query = "SELECT imgpath from images";
$oMySQL->ExecuteSQL($query);
Now when i use this
$result=$oMySQL->ExecuteSQL($query);
it prints "Array"
How to iterate through the array
Regards Jane
A simple foreach loop.
foreach ($result as $key => $val) {
foreach ($val as $label => $item) {
echo $label . " - " . $item;
}
}
$key will hold the associative name the array element, and $val will hold the value of the element.
You mean it print array when you do echo $result?
Then:
foreach($result as $index => $value) {
echo $index . '=' $value;
}
I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}