Passing json to php and updating mysql - php

Question

I'm trying to pass image coordinates via json to a php file that should update the database.
I have this in jquery:
var coords=[];
var coord = $(this).position();
var item = { coordTop: coord.top, coordLeft: coord.left };
coords.push(item);
var order = { coords: coords };
$.ajax({
type: "POST",
data : +$.toJSON(order),
url: "updatecoords.php",
success: function(response){
$("#respond").html('<div class="success">X and Y Coordinates
Saved</div>').hide().fadeIn(1000);
setTimeout(function(){
$('#respond').fadeOut(1000);
}, 2000);
}
});
This is what updatecoords.php looks like:
<?php
$db = Loader::db();
$data = json_decode($_POST['data']);
foreach($data->coords as $item) {
$coord_X = preg_replace('/[^\d\s]/', '', $item->coordTop);
$coord_Y = preg_replace('/[^\d\s]/', '', $item->coordLeft);
$x_coord = mysql_real_escape_string($coord_X);
$y_coord = mysql_real_escape_string($coord_Y);
$db->Execute("UPDATE coords SET x_pos = '$x_coord', y_pos = '$y_coord'");
}
?>
The success message shows from the javascript however nothing gets updated in the database?
Any thoughts?

Answer 1

You have a + before $.toJSON. Meaning that the json string it returns will be converted to an integer - probably 0 or NaN.

Answer 2

Alex is right, but you can also take the quotes out from the preg_replace pattern. PHP naturally uses /.../ slashes to "quote" a regular expression.

Answer 3

try this
UPDATE coords SET x_pos = '".$x_coord."', y_pos = '".$y_coord."'
and look here how to use toJSON
EDIT :
try this
$.ajax({
type: "POST",
data : { coordTop: coord.top, coordLeft: coord.left ,coords: coords },
and in second code do this
$data = json_decode($_POST['data']);
$coordTop = mysql_real_escape_string($_POST['coordTop']);
$coordLeft = mysql_real_escape_string($_POST['coordLeft']);
$coords = mysql_real_escape_string($_POST['coords']);
foreach(.........
.....
.....
and then use those variables $coordTop , $coordLeft , $coords

Answer 4

Thanks for the help but this seemed to do the trick....
In javascript:
$.post('updatecoords.php', 'data='+$.toJSON(order), function(response){ alert (response + mydata);
In Updatecoords.php:
$data = json_decode(stripcslashes($_POST['data']));