I'm afraid i have written a query & confused myself in the process despite it being quite simple.
I have 2 mysql tables.
Table1 has ... orderID, productID, quantity
Table2 has ... orderID, status, time
I need to do a query that will do the following...
Output (1 per line)
productID - Quantity where status = 1 & time < $lastactive.
I tried doing a query of Table 2 to fetch productID and count Quantity but then if 2 different orderID's have the same productID then it doesnt total them. Any help greatly appreciated (name of tables/rows are accurante).
Example:
orderID 123, productID 2, quantity 4
orderID 123, productID 5, quantity 6
orderID 678, productID 2, quantity 5
would output:
2 9
5 6
You should be able to use something similar to this:
select t1.productId, Sum(t1.quantity) Total
from table1 t1
inner join table2 t2
on t1.orderid = t2.orderid
where t2.status = 1
and t2.time < $lastactive
group by t1.productid
Related
I've a table syntax like this,
- table1
id foreign_table_id
-----------------------
1 2
2 2
3 2
4 1
5 1
6 1
The other table is,
- table2
id value
------------
1 20
2 10
I want to get a summation of table1.foreign_table_id where the data will retrieve from table2.
Like this example should produce the result 90
Please provide any solution.
Use below query.
Select sum(table2.value) as total FROM table1 LEFT JOIN table2 ON table1.foreign_table_id = table2.id
It will give u below result.
Output::
total
-----
90
SELECT SUM(table2.value) AS summation FROM table1 LEFT JOIN table2
ON table2.id = table1.foreign_table_id
We require to get row if product_id is in sequence.
Table (product)
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
6 Nuts
8 Britania
9 Pepsi
Require Output
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
6 Nuts
product_id - 8 and 9 not getting because it is not in sequence.
My Try
select distinct t1.*, t1.product_id, (select GROUP_CONCAT(t2.product_id) from product as t2) as p_id
from product t1
having FIND_IN_SET(t1.product_id+1, p_id)
Output
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
In this try i am not getting product_id - 6 row.
Note : I want MySql query not in PHP.
Thank You !
One way i can think of is to user user defined variable to get the rank of row and then calculate the difference of product id and rank and select only those rows where difference = 0
select *
from(
select f.*,#row:= #row + 1 rank,
product_id - #row as diff
from product f,
(select #row:= 0) t
order by product_id
) t1
where diff = 0
Demo
Or if you want to pick the least sequence no. automatically you can write it as
select *
from(
select f.*,#row:= #row + 1 rank,
product_id - #row as diff
from product f,
(select #row:= (select min(product_id) from product_sale_flag) a) t
order by product_id
) t1
where diff = -1
Demo
Explanation
First query assign's minimum value of product_id to variable #row,then it assigns a rank to each row ordered by product_id in ascending order, once rank is assigned for every row then it calculates the difference between the original value of product_id and lastly using the resultant difference it checks where difference is 0 get those rows because they follow the sequence. Hope this makes sense
Q : I am trouble to do following task in mysql query.
Task is get all products (If product is duplicate than sum of it's qty) and deduct wastage stock (If wastage product is duplicate than sum of it's qty).
I have two tables like,
1) manage_stock
2) manage_wastage
manage_stock
=> This table has p_id(Product ID) and many rows with product duplication's.
p_id p_name p_qty
1 Pro-1 10
2 Pro-2 15
3 Pro-3 8
1 Pro-1 15
manage_wastage
=> This table has p_id(Product ID) of manage_stock table. It is also many rows with product duplication's.
p_id w_qty
1 2
1 4
3 5
Desired Output
p_id p_name p_qty w_qty final_qty
1 Pro-1 20 6 14
2 Pro-2 15 0 15
3 Pro-3 8 5 3
Thank you very much.
You just have to compute the difference between the stock quantity and the wastage
SELECT s.p_id, s.p_name, SUM(p_qty), SUM(w_qty), SUM(p_qty) - SUM(w_qty) as final_qty
FROM manage_stock s
LEFT OUTER JOIN manage_wastage w
ON s.p_id = w.p_id
GROUP BY s.p_id, s.p_name
try this one
SELECT s.p_id, s.p_name, SUM(p_qty),SUM(ifnull(w_qty, 0)),SUM(p_qty - ifnull(w_qty, 0)) as total
FROM manage_stock s
left outer JOIN manage_wastage w
ON s.p_id = w.p_id
GROUP BY s.p_name
its work
SELECT ms.p_id ,GROUP_CONCAT(ms.p_name)p_name ,SUM(ms.p_qty) p_qty ,SUM(mw.w_qty) w_qty,SUM(ms.p_qty)-SUM(mw.w_qty) final_qty FROM manage_stock ms
INNER JOIN manage_wastage mw on ms.p_id =mw.p_id
GROUP BY ms.p_id
Try above code.
As p_name always unique with p_id GROUP_CONCAT() only returns single name.
I have table Orders:
O_Id OrderDate OrderPrice Customer
1 2008/11/12 1000 Hansen
2 2008/10/23 1600 Nilsen
3 2008/09/02 700 Hansen
4 2008/09/03 300 Hansen
5 2008/08/30 2000 Jensen
6 2008/10/04 100 Nilsen
and query:
SELECT COUNT(Customer) AS CustomerNilsen FROM Orders
WHERE Customer='Nilsen'
but is possible add to this results IDs results?
I would like receive
count: 2
and
ids: 2 and 6
GROUP_CONCAT may help:
SELECT
COUNT(Customer) AS CustomerNilsen,
GROUP_CONCAT(O_Id) as IDS
FROM
Orders
WHERE
Customer='Nilsen'
Better to just fetch all the IDs and then use the appropriate row count function:
SELECT `O_Id` FROM `Orders`
WHERE `Customer` = 'Nilsen'
I don't really understand your question, but from what I can tell you just want to SELECT the o_id column in your query:
SELECT COUNT(Customer) AS CustomerNilsen, O_Id AS OrderID FROM Orders WHERE Customer='Nilsen'
You might check this
SELECT Customer,
COUNT(Customer) AS CustomerNilsen
FROM Orders
WHERE Customer = 'Nilsen'
GROUP BY Customer
HAVING CustomerNilsen = 1
Try this
SELECT O1.O_Id AS OrderID,Count(O1.O_Id) AS OrderCount FROM Orders O1
INNER JOIN Orders O2 ON O1.Customer = O2.Customer
WHERE O1.Customer='Nilsen'
GROUP BY O1.Customer,O1.O_Id
I'd like to know the most efficient SQL query for achieving this problem:
Say we have a table with two columns, one storing entry ids (entry_id) and one storing category ids (cat_id):
entry_id cat_id
3 1
3 2
3 3
3 20
4 1
4 2
4 21
I'd like to count how many distinct entry_id's there are in the categories 1, 2 OR 3 but that also must be in cat_id 20.
For example, categories 1, 2 and 3 might represent music genres (Country, Pop etc.), while category 20 might be recording formats (CD, Vinyl etc.). So another way of putting it verbally could be: "How many products are there that are on Vinyl and in either the Pop or Country category?"
I could achieve this with a nested loop in code (PHP) or possibly with a nested SQL subquery, but neither feels that efficient. I feel there must be an obvious answer to this staring me in the face...
EDIT TO ADD:
I would also like to do this without modifying the database design, as it's a third party system.
FURTHER EXAMPLE TO CLARIFY:
Another real-world example of why I'd need this data:
Let's say the category ids instead represent either:
Accommodation Types (Camping = 20, Holiday Cottage = 21)
OR
Continents and their sub-regions (i.e. Europe = 1, UK = 2, England = 3)
Let's say someone has selected that they are interested in camping (cat_id = 1). Now we need to count how many camping products there are in the Europe. A product might be tagged as both Europe (parent), UK (child) AND England (grand-child), giving us an array of category ids 1, 2 or 3. So we now need to count how many distinct products there are in both those categories AND the original accommodation category of 1 (camping).
So having selected Camping, the end result might look something like:
Europe: 4 camping products
UK: 2 camping products
England : 1 camping product
Wales : 1 camping product
France: 2 camping products
etc.
Hope that helps...
I believe you want GROUP BY, COUNT() and EXISTS()
declare #t table(entry_id int, cat_id int)
insert #t select 1, 1
insert #t select 2, 1
insert #t select 1, 2
insert #t select 2, 2
insert #t select 3, 1
insert #t select 1, 20
select t1.cat_id, COUNT(*)
from #t as t1
where exists(
select * from #t
where t1.entry_id = entry_id
and cat_id = 20)
group by t1.cat_id
V2 using join instead of EXISTS()
declare #t table(entry_id int, cat_id int)
insert #t select 1, 1
insert #t select 2, 1
insert #t select 1, 2
insert #t select 2, 2
insert #t select 3, 1
insert #t select 1, 20
select t1.cat_id, COUNT(*)
from #t as t1
join #t as t2 on t1.entry_id = t2.entry_id and t2.cat_id = 20
group by t1.cat_id
select count(distinct entry_id) from myTable where cat_id=20 and entry_id in
(select distinct entry_id from myTable where cat_id in (1,2,3));
With no subqueries, using JOIN and GROUP BY:
Join the table to itself using entry_id (this gives you all possible pairs of cat_id for that entry_id). Select rows having cat_id both a member of (1,2,3) and the second cat_id = 20.
SELECT r1.entry_id
FROM records r1
JOIN records r2 USING(entry_id)
WHERE r1.cat_id IN (1,2,3)
AND r2.cat_id = 20 GROUP BY entry_id;