Q : I am trouble to do following task in mysql query.
Task is get all products (If product is duplicate than sum of it's qty) and deduct wastage stock (If wastage product is duplicate than sum of it's qty).
I have two tables like,
1) manage_stock
2) manage_wastage
manage_stock
=> This table has p_id(Product ID) and many rows with product duplication's.
p_id p_name p_qty
1 Pro-1 10
2 Pro-2 15
3 Pro-3 8
1 Pro-1 15
manage_wastage
=> This table has p_id(Product ID) of manage_stock table. It is also many rows with product duplication's.
p_id w_qty
1 2
1 4
3 5
Desired Output
p_id p_name p_qty w_qty final_qty
1 Pro-1 20 6 14
2 Pro-2 15 0 15
3 Pro-3 8 5 3
Thank you very much.
You just have to compute the difference between the stock quantity and the wastage
SELECT s.p_id, s.p_name, SUM(p_qty), SUM(w_qty), SUM(p_qty) - SUM(w_qty) as final_qty
FROM manage_stock s
LEFT OUTER JOIN manage_wastage w
ON s.p_id = w.p_id
GROUP BY s.p_id, s.p_name
try this one
SELECT s.p_id, s.p_name, SUM(p_qty),SUM(ifnull(w_qty, 0)),SUM(p_qty - ifnull(w_qty, 0)) as total
FROM manage_stock s
left outer JOIN manage_wastage w
ON s.p_id = w.p_id
GROUP BY s.p_name
its work
SELECT ms.p_id ,GROUP_CONCAT(ms.p_name)p_name ,SUM(ms.p_qty) p_qty ,SUM(mw.w_qty) w_qty,SUM(ms.p_qty)-SUM(mw.w_qty) final_qty FROM manage_stock ms
INNER JOIN manage_wastage mw on ms.p_id =mw.p_id
GROUP BY ms.p_id
Try above code.
As p_name always unique with p_id GROUP_CONCAT() only returns single name.
Related
We require to get row if product_id is in sequence.
Table (product)
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
6 Nuts
8 Britania
9 Pepsi
Require Output
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
6 Nuts
product_id - 8 and 9 not getting because it is not in sequence.
My Try
select distinct t1.*, t1.product_id, (select GROUP_CONCAT(t2.product_id) from product as t2) as p_id
from product t1
having FIND_IN_SET(t1.product_id+1, p_id)
Output
product_id name
1 Parle
2 Coconut
3 Pizza
4 Colgate
5 Ice Cream
In this try i am not getting product_id - 6 row.
Note : I want MySql query not in PHP.
Thank You !
One way i can think of is to user user defined variable to get the rank of row and then calculate the difference of product id and rank and select only those rows where difference = 0
select *
from(
select f.*,#row:= #row + 1 rank,
product_id - #row as diff
from product f,
(select #row:= 0) t
order by product_id
) t1
where diff = 0
Demo
Or if you want to pick the least sequence no. automatically you can write it as
select *
from(
select f.*,#row:= #row + 1 rank,
product_id - #row as diff
from product f,
(select #row:= (select min(product_id) from product_sale_flag) a) t
order by product_id
) t1
where diff = -1
Demo
Explanation
First query assign's minimum value of product_id to variable #row,then it assigns a rank to each row ordered by product_id in ascending order, once rank is assigned for every row then it calculates the difference between the original value of product_id and lastly using the resultant difference it checks where difference is 0 get those rows because they follow the sequence. Hope this makes sense
I am trying to retrieve the minimum price of some models.
Each model belongs to a certain group which belongs to a product.
I have the following tables:
Product
model_id product_id price
1 1 100
2 1 120
3 1 100
4 1 200
5 1 250
10 1 20
11 1 50
12 1 50
Product Overview
model_id product_id group_id
1 1 A
2 1 A
3 1 A
4 1 A
5 1 A
10 1 B
11 1 B
12 1 B
Product Group Optional
group_id product_id
B 1
Some groups could be optional, which means price will be zero unless the member wants to choose otherwise.
So in the example above, I want to get the sum of minimum price from each group.
We have two groups, group A and group B.
Group A minimum price value is 100 (model_id 1 and 3)
Group B minimum price value is 20 (model_id 10) but because Group B is optional then that means minimum price value is 0.
Overall sum of min values: 100 (Group A) + 0 (Group B) = 100
My code so far:
SELECT po.group_id,
CASE WHEN
((SELECT COUNT(*) FROM product_group_optional pgo
WHERE po.group_id = group_id AND po.product_id = 1 AND po.product_id = product_id) >= 1)
THEN SUM(0)
ELSE SUM(p.price)
END AS sum_price
FROM product_overview po, product p
WHERE po.product_id = 1
AND po.model_id = p.model_id
AND p.price = (
SELECT MIN(p2.price)
FROM product p2, product_overview po2
WHERE po2.product_id = 1 AND po2.group_id = po.group_id
AND po2.model_id = p2.model_id
)
GROUP BY po.group_id
The output:
group_id sum_price
A 200
B 0
The problem is that I get 200 for Group A but it should be 100.
There are 2 models with min value 100, model 1 and 3. And I assume these are sum together = 100 + 100 = 200.
Issue a) But I want to just take the min value, no matter how many times this value exists.
Issue b) Also, I am trying to get the SUM of those two output SUM of Group A and Group B.
But I am not sure how to do it.
I want it to be done in this query.
Desired output
Sum of all groups
100
Can anyone lead me to the right direction please?
You can use the following query:
SELECT SUM(min_price)
FROM (
SELECT po.group_id,
MIN(CASE WHEN pgo.group_id IS NULL THEN price ELSE 0 END) AS min_price
FROM Product AS p
INNER JOIN Product_overview AS po
ON p.product_id = po.product_id AND p.model_id = po.model_id
LEFT JOIN Product_group_optional AS pgo ON po.group_id = pgo.group_id
GROUP BY po.group_id) AS t
I'm not sure that I understand the keys of your tables, and the problem as well.
There is few questions.
a) The answer should be 120?
b) If the Product has no price, the is price null?
c) If there is a Product in a group with null price and others with price, should it be counted as 0?
Here is how you could get the sum of the lower prices of each group, ignoring the product_group_optional for while:
SELECT t2.group_id, sum(t2.new_price)
FROM
(
SELECT t.group_id, t.new_price
FROM
(
SELECT po.group_id, if(ifnull(pgo.product_id, true), p.price, 0) as new_price
FROM product p, product_overview po
LEFT JOIN product_group_optional pgo ON po.group_id = pgo.group_id
WHERE p.model_id = po.model_id
ORDER by po.group_id, new_price
) t
GROUP BY t.group_id
) t2
I have multiple tables with orders and deliveries and I want to get only open orders (only those orders that do not have records in delivery table).
So, my tables look like:
Orders table (sh_comenzi):
id partner
1 Partner X
2 Partner Y
3 Partner Z
4 Partner Q
Order lines table (sh_comenzi_pos) where idc is the id of sh_comenzi table
id idc cPos quantity
1 1 1 5
2 1 2 10
3 1 3 20
4 2 1 10
5 2 2 15
6 3 1 10
7 3 2 5
8 3 3 8
9 4 1 15
The deliveries items table is (sh_delivery_items)
id idc cPos
1 1 1
2 1 3
3 2 2
4 3 1
5 3 2
6 3 3
The desired result should give me an output of open orders just like this:
id partner
1 Partner X
2 Partner Y
4 Partner Q
The result doesn't have to keep track o quantities, just on lines level. If one line from orders exists in sh_delivery_items then that line is closed.
I tried something like this:
SELECT DISTINCT sh_comenzi.id, partner FROM sh_comenzi
LEFT JOIN sh_comenzi_pos ON sh_comenzi.id = sh_comenzi_pos.idc
LEFT JOIN sh_delivery_items ON (sh_comenzi_pos.idc = sh_delivery_items.idc AND sh_comenzi_pos.cPos = sh_delivery_items.cPos)
WHERE sh_comenzi.id IS NOT NULL
ORDER BY sh_comenzi.id DESC
Could someone help me?
This is the query you need:
SELECT DISTINCT c.*
FROM sh_comenzi c
INNER JOIN sh_comenzi_pos p
ON c.id = p.idc
LEFT JOIN sh_delivery_items di # 'di' from 'delivery items'
ON p.idc = di.idc AND p.cPos = di.cPos
WHERE di.id IS NULL # keep only not-delivered items
How it works
It combines all the orders (table sh_comenzi) with their line items (table sh_comenzi_pos). The INNER JOIN will leave out the empty orders (if any); if you need them then use LEFT JOIN instead.
Next, each row (order, line item) is combined with the delivery information (table sh_delivery_items) using the pair of columns (idc, cPos). The LEFT JOIN ensures all the rows from the left side table (or result set) appear in the final result set; if a row from the right side table cannot be found to match the row from the left, a row full of NULLs is used instead. This happens for the line items that were not delivered yet (there is no record for them in sh_delivery_items).
Then, the WHERE clause keeps only the rows having NULLs in the di table (sh_delivery_items), i.e. the line items that were not delivered, together with the orders that own them.
Finally, SELECT DISTINCT c.* selects only the columns from the orders table (sh_comenzi) and DISTINCT ensures each order appear only once. Otherwise, each order appears once for each of its line items that was not delivered.
Complete the query yourself with the desired ORDER BY clause.
Can someone help me how to make an efficient mysql query for this?
I need to make a query to get the sum quantity of all ordered items.
combined with.
I need to make a query to get the sum quantity of all received items.
Please note that some products have serial numbers when received and some don't in my 'received_po_details' table. That's where I'm having problem with since the sum of received gets doubled because of the serial numbers.
Table: received_po_details
i_rpoh_id i_p_id i_quantity_received s_product_serial
1 1 100
1 2 100
1 3 50
1 4 25
1 7 100
1 8 50
1 6 1 XYZ1
1 6 1 XYZ2
1 5 1 ABC1
1 5 1 ABC2
Right now I have these 2 separate sql that I need to combine.
I don't want to use Union statement for this if possible...
-- to get the Total Quantity Ordered
SELECT
products.i_id AS 'ID',
products.s_name AS 'Name',
COALESCE(SUM(purchase_order_details.i_quantity_ordered),0) AS 'Total Quantity Ordered'
FROM
products
LEFT JOIN
purchase_order_details
ON
products.i_id = purchase_order_details.i_p_id
GROUP BY
products.i_id
-- to get the Total Quantity Received
SELECT
products.i_id AS 'ID',
products.s_name AS 'Name',
COALESCE(SUM(received_po_details.i_quantity_received),0) AS 'Total Quantity Received'
FROM
products
LEFT JOIN
received_po_details
ON
products.i_id = received_po_details.i_p_id
GROUP BY
products.i_id
You can combine these queries by creating a derived table or each type of sum (in the query below they're named t1 and t2) and left joining the derived tables to the main product table.
SELECT
p.i_id AS 'ID',
p.s_name AS 'Name',
COALESCE(t1.total,0) 'Total Quantity Ordered',
COALESCE(t2.total,0) 'Total Quantity Received'
FROM products p
LEFT JOIN (
SELECT
pod.i_p_id,
SUM(pod.i_quantity_ordered) total
FROM purchase_order_details pod
GROUP BY pod.i_p_id
) t1 ON t1.i_p_id = p.i_id
LEFT JOIN (
SELECT
rpd.i_p_id,
SUM(rpd.i_quantity_received) total
FROM received_po_details rpd
GROUP BY rpd.i_p_id
) t2 ON p.i_id = t2.i_p_id
Im having some trouble with this.
Here's an example of my tables.
Booking
id zone_id name excursion_id
1 2 1
2 1 1
3 2 1
The table where I have the quantities
booking_price
id_booking id_price quantity
1 1 2
1 2 3
2 1 1
2 2 0
3 1 2
3 2 3
Here the zone table
Zone
id Name
1 a
2 b
3 c
So I want to have a table like that
Zone_id Quantity
1 1
2 10
3 0
The problem is when im joining tables and filtering by excursion_id im not getting ALL the zones.
I want to know how many people goes in each zone.
I think better way of doing it is
select z.id, coalesce(sum(bp.quantity),0) as quantity
from Booking b
right join Zone z on z.id = b.zone_id AND b.excursion_id = 1
left join booking_price bp on bp.id_booking = b.id
group by z.id
demo http://sqlfiddle.com/#!2/771f5/13
You could use a query like:
SELECT zone.id as zone_id,
sum(quantity) as Quantity
FROM zone
LEFT JOIN Booking on Booking.zone_id = zone.id
LEFT JOIN Excursion on Excursion.id_booking = Booking.id
GROUP BY zone.id