How to pass variables to an AJAX call without a form - php

I am building an application in Code Igniter and am currently building some functionality where a user can approve or deny a request on the page by clicking either a tick or a cross icon on the page. These icons are anchor tags.
The trouble I am having is passing an ID for that individual request to the AJAX form.
I would have no issue implementing this functionality in a form as I would simply use a hidden input field which would have it's value saved in it set from the controller. There can be many of these requests but they would always have their own individual ID as it is looped through in the view.
As I am using anchor tags instead of a form I am not sure where I could store the id for that request in the markup.
Here is the code:
<p><span class="bold">Authorise This Request?: </span></p>
<p>
<img src="/igniter/images/tick.png" />
<img src="/igniter/images/cross.png" />
</p>
</div>
<?php $i++; ?>
<?php } ?>
</div>
<script type="text/javascript">
$(document).ready(function() {
$('.authorise').click(function() {
$.ajax({
type: "POST",
url: 'holiday_request/authoriseRequest',
data: 'check=' + $(this).attr('id'),
success: function(data) {
}
});
return false;
});
});
</script>
As you can see I use the ID of the input field to determine later on whether to allow or deny it. All I want to do is to be able to pass the ID for that request through which is currently in the controller, so adding '&id= blahblahblah' onto the end of the URL variable in the AJAX call.
Is there a way I can do this without having to use a form instead of anchor tags?

You can use HTML5 data-* Attributes
<img src="/igniter/images/tick.png" />
...
Then get the value and add it to ajax data parameter
data: 'check=' + $(this).data('check') + '&id=' + $(this).data('id'),

You can store the ID in Data attribute of the anchor tag.
<img src="/igniter/images/tick.png" />
To get the stored value for allow anchor tag using jquery.
$val_allow = $('#allow').data('val'); // value 10

You can try using $.post and can have custom parameters as you like!
$.post({ 'holiday_request/authoriseRequest' , { check: someId , anotherParam: 1 } ,
function(response)
{
console.log(response);
}
});

Related

How to pass ajax sucess result to another php page

In my code below I want display $("#searchresults").html(data) this result to other page.
$.ajax({
type: "POST",
url: base_url + 'front/searchresult',
data: data,
success: function(data) {
alert("test");
var val = $("#searchresults").html(data);
window.location.assign("<?php echo base_url()?>front/search/" + val);
}
});
what exactly is in the data variable you receive from your post? is it a json object? is it plain text?
if it is html, I think you should consider placing the result in a div on the current page, and hide items you don't want to see after searching
relocating after ajax requests is not the way to go. Is it an option in your case, to use a form and change the action attribute of the form to your new location?
<form action="front/search/">
<input type="text" name="data">
</form>

Grab the name of an element with jquery

I have a series of Form Elements each with different names, I'll post one as an example. I cannot hard code the name into Jquery because unless I inspect the element, I won't know the name.
With that aside heres the element:
<label class="checkbox">
<input type="checkbox"
name="aisis_options[package_Aisis-Related-Posts-Package-master]"
value="package_Aisis-Related-Posts-Package-master" checked="" />
Aisis-Related-Posts-Package-master
(Disable)
</label>
The catch is to do this:
Grab the name of this element - upon clicking disable - and do two things, one - if the element is checked, which in this case it's not, unchecked it, two pass the name to a php variable, which then can do processing.
How would I do this? Jquery is not my strong area.
Here is a example without knowing more of your code:
$(function () {
$('input:checkbox').click(function () {
$(this).prop('disabled', true);
var iName = this.name;
$.ajax({
url: "file.php",
data: {
'inputname': iName
},
success: function (data) {
alert(data.returned_val);
}
})
})
})
Demo here
If you want to reach the input via name directly you need to use double backslasshes to escape the square brackets and reach that input via name. Use:
$('input[name=aisis_options\\[package_Aisis-Related-Posts-Package-master\\]]')
You can add an onchange with checkbox
onchange="f(this);"
in js f() function you can use this.name to get the name, this.value to get value etc and do whatever you want.
To check/unckeck, you can use $element.prop('checked', true/false); like this (fiddle):
HTML
<input
type="checkbox"
name="aisis_options[package_Aisis-Related-Posts-Package-master]"
value="...."
checked="checked"
/> Aisis-Related-Posts-Package-master
(Disable)
JS
$('.trigger').click (function () {
closest_checkbox = $(this).siblings('input[type=checkbox]');
closest_checkbox.prop('checked', !closest_checkbox.prop('checked'));
});
JS part 2: AJAX
You can build an object with all your name:value combinations using the jQuery plugin serializeObject, your form submission event handler would be something like:
$('form').submit( function (e) {
// Prevent the form from being sent normally since we want it ajaxified
e.preventDefault();
// Send request to php page
$.ajax({
type: "POST",
url: "some.php",
data: $('form').serializeObject() // <== Magic happens here
});
});
PS. Don't forget to include the serializeObject plugin and give a unique id to the form, $('#unique_id') is way better than $('form') which will match all the forms in the page.
To grab the value of name attribute, you can use:
$(this).attr('name');

ajax $_POST data then redirect to new page

I have been going crazy for the last 2 weeks trying to get this to work. I am calling a MySQL Db, and displaying the data in a table. Along the way I am creating href links that DELETE and EDIT the records. The delete pulls an alert and stays on the same page. The EDIT link will POST data then redirect to editDocument.php
Here is my PHP:
<?php
foreach ($query as $row){
$id = $row['document_id'];
echo ('<tr>');
echo ('<td>' . $row [clientName] . '</td>');
echo ('<td>' . $row [documentNum] . '</td>');
echo "<td><a href='**** I NEED CODE HERE ****'>Edit</a>";
echo " / ";
echo "<a href='#' onclick='deleteDocument( {$id} );'>Delete</a></td>";
// this calls Javascript function deleteDocument(id) stays on same page
echo ('</tr>');
} //end foreach
?>
I tried (without success) the AJAX method:
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: 'edit_id='edit_id,
success: function(response){
$('#result').html(response);
}
});
}
</script>
I have been using <? print_r($_POST); ?> on editDocument.php to see if the id has POSTed.
I realize that jQuery/AJAX is what I need to use. I am not sure if I need to use onclick, .bind, .submit, etc.
Here are the parameters for the code I need:
POSTs the $id value: $_POST[id] = $id
Redirects to editDocument.php (where I will use $_POST[id]).
Does not affect other <a> OR any other tags on the page.
I want AJAX to "virtually" create any <form> if needed. I do not
want to put them in my PHP code.
I do not want to use a button.
I do not want to use $_GET.
I don't know what I am missing. I have been searching stackoverflow.com and other sites. I have been trying sample code. I think that I "can't see the forest through the trees." Maybe a different set of eyes. Please help.
Thank you in advance.
UPDATE:
According to Dany Caissy, I don't need to use AJAX. I just need to $_POST[id] = $id; and redirect to editDocument.php. I will then use a query on editDocument.php to create a sticky form.
AJAX is used when you need to communicate with the database without reloading the page because of a certain user action on your site.
In your case, you want to redirect your page, after you modify the database using AJAX, it makes little sense.
What you should do is put your data in a form, your form's action should lead to your EditDocument, and this page will handle your POST/GET parameters and do whatever database interaction that you need to get done.
In short : If ever you think you need to redirect the user after an AJAX call, you don't need AJAX.
You have a SyntaxError: Unexpected identifier in your $.ajax(); request here
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: 'edit_id='edit_id,
success: function(response){
$('#result').html(response);
}
});
}
</script>
it should be like this
<script>
function editDocument(id){
var edit_id = id;
$.ajax({
type: 'POST',
url: 'editDocument.php',
data: {edit_id: edit_id},
success: function(response){
$('#result').html(response);
}
});
}
</script>
note the 'edit_id='edit_id, i changed, well for a start if you wanted it to be a string it would be like this 'edit_id = ' + edit_id but its common to use a object like this {edit_id: edit_id} or {'edit_id': edit_id}
and you could also use a form for the edit button like this
<form action="editDocument.php" method="POST">
<input type="hidden" name="edit_id" value="272727-example" />
<!-- for each data you need use a <input type="hidden" /> -->
<input type="submit" value="Edit" />
</form>
or in Javascript you could do this
document.location = 'editDocument.php?edit_id=' + edit_id;
That will automatically redirect the user
Given your comment, I think you might be looking for something like this:
Edit
$(document).ready(function() {
$('.editLink').click(function(e) {
e.preventDefault();
var $link = $(this);
$('<form/>', { action: 'editdocument.php', method: 'POST' })
.append('<input/>', {type:hidden, value: $link.data('id') })
.appendTo('body')
.submit();
});
});
Now, I don't necessarily agree with this approach. If your user has permission to edit the item with the given id, it shouldn't matter whether they access it directly (like via a bookmark) or by clicking the link on the list. Your desired approach also prevents the user from opening links in new tabs, which I personally find extremely annoying.
Edit - Another idea:
Maybe when the user clicks an edit link, it pops up an edit form with the details of the item to be edited (details retrieved as JSON via ajax if necessary). Not a new page, just something like a jQuery modal over the top of the list page. When the user hits submit, post all of the edited data via ajax, and update the sql database. I think that would be a little more user-friendly method that meets your requirements.
I was facing the same issue with you. I also wanted to redirect to a new page after ajax post.
So what is did was just changed the success: callback to this
success: function(resp) {
document.location.href = newURL; //redirect to the url you want
}
I'm aware that it defies the whole purpose of ajax. But i had to get the value from a couple of select boxes, and instead of a traditional submit button i had a custom anchore link with custom styling in it. So in a hurry i found this to be a viable solution.

How to pass multiple parameters by jQuery.ajax() to PHP?

I have a simple load more style script that works fine on the index page, where only one parameter is sent via ajax
$(function() {//When the Dom is ready
$('.load_more').live("click",function() {//If user clicks on hyperlink with class name = load_more
var last_msg_id = $(this).attr("id");//Get the id of this hyperlink this id indicate the row id in the database
if(last_msg_id!='end'){//if the hyperlink id is not equal to "end"
$.ajax({//Make the Ajax Request
type: "POST",
url: "index_more.php",
data: "lastmsg="+ last_msg_id,
beforeSend: function() {
$('a.load_more').html('<img src="loading.gif" />');//Loading image during the Ajax Request
},
success: function(html){//html = the server response html code
$("#more").remove();//Remove the div with id=more
$("ul#updates").append(html);//Append the html returned by the server .
}
});
}
return false;
});
});
With this HTML/PHP
<div id="more">
<a id="<?php echo $msg_id; ?>" class="load_more" href="#">more</a>
</div>
However, I want to add another php variable so that it can also work with particular categories, I have no problems writing the HTML and PHP but I am new to Jquery and struggling to edit the script to include the additional parameter if it is set. This is the HTML that I am thinking of using, just struggling with editing the JQuery
<div id="more"class="<?php echo $cat_id;?>">
<a id="<?php echo $msg_id;?>" class="load_more2" href="#">more</a>
</div>
As always any help is much appreciated!
You can set
data = {onevar:'oneval', twovar:'twoval'}
And both key/value pairs will be sent.
See Jquery ajax docs
If you look under the data section, you can see that you can pass a query string like you are, an array, or an object. If you were to use the same method you already are using then your data value would be like "lastmsg="+ last_msg_id + "&otherthing=" + otherthing,
You can pass multiple URL params in the data portion of your ajax call.
data: "lastmsg="+ last_msg_id +"&otherparam="+ other_param
On the PHP side, you'd just process these as you already are.
You can use this code:
$.ajax({//Make the Ajax Request
type: "POST",
url: "index_more.php",
data: {var1: "value1", var2: "value2"},
beforeSend: function() {
$('a.load_more').html('<img src="loading.gif" />');//Loading image during the Ajax Request
},
success: function(html){//html = the server response html code
$("#more").remove();//Remove the div with id=more
$("ul#updates").append(html);//Append the html returned by the server .
}
});
Try It:
data: JSON.stringify({ lastmsg: last_msg_id, secondparam: second_param_value});
You can add more parameters separating them by comma (,).

jQuery, Ajax & PHP submit multiple forms dilemma

This is a very simple form that I have found on the web (as I am a jQuery beginner).
<!-- this is my jquery -->
<script>
$(document).ready(function(){
$("form#submit_wall").submit(function() {
var message_wall = $('#message_wall').attr('value');
var id = $('#id').attr('value');
$.ajax({
type: "POST",
url: "index.php?leht=pildid",
data:"message_wall="+ message_wall + "&id="+ id,
cache: false,
success: function(){
$("ul#wall").prepend(""+message_wall+"", ""+id+"");
$("ul#wall li:first").fadeIn();
alert("Thank you for your comment!");
}
});
return false;
});
});
</script>
<!-- this is my HTML+PHP -->
some PHP ...
while($row_pilt = mysql_fetch_assoc($select_pilt)){
print
<form id="submit_wall">
<label for="message_wall">Share your message on the Wall</label>
<input type="text" id="message_wall" />
<input type="hidden" id="id" value="'.(int)$row_pilt['id'].'">
<button type="submit">Post to wall</button>
</form>
and down below is my PHP script that
writes to mySQL.
It is a pretty straight forward script. However, it is getting little complicated when I submit it. Since I have more than one form on my page (per WHILE PHP LOOP), thus when I submit - only the FIRST form gets submitted. Furthermore, any other subsequent forms that I submit - data is being copied from the first form.
Is there any jQuery functions that clear the data? - or is there a better solution.
Thanks,
Nick
It's because you're giving each form the same id, and thus it is submitting the first element it finds with that id, i.e. the first form. What you should do is assign a unique id to each form, and then give each form an AJAX submit function that submits the form-specific data. You can use jQuery's $.each() function to loop through all the forms and $(this).attr('id') within the submit function to retrieve the form-specific id.
UPDATE: As revealed by the comment on this answer, you actually don't need the each() function because jQuery applies it to every form element anyway.
Here would be an example script:
$(document).ready(function(){
$("form").submit(function() {
var message_wall = $(this).children('input[type="text"]').attr('value');
var id = $(this).children('input[type="hidden"]').attr('value');
$.ajax({
type: "POST",
url: "index.php?leht=pildid",
data:"message_wall="+ message_wall + "&id="+ id,
cache: false,
success: function(){
$("ul#wall").prepend(""+message_wall+"", ""+id+"");
$("ul#wall li:first").fadeIn();
alert("Thank you for your comment!");
}
});
return false;
});
});
Because we can't see all of your forms, I'm not entirely sure, but given your question I'm going to assume that the other forms all share the same id (form#submit_wall), which is invalid an id must be unique within the document.
Given that you're going to change the id of the other forms (I'd suggest using a class name of, probably, 'submit_wall', but the specifics are up to you), the jQuery needs to be changed, too. From:
$("form#submit_wall").submit(function() {
To:
$("form.submit_wall").submit(function() { // using the class-name instead of the id.
Now, of course, you run into the same problems of duplicate ids.
So I'd suggest, again, changing the id to a class and changing:
var message_wall = $('#message_wall').attr('value');
var id = $('#id').attr('value');
to:
var message_wall = $(this).find('.#message_wall').attr('value');
var id = $(this).find('.id').attr('value');
Given the mess that you've posted, above, I find it hard to believe that this is all you need. It would definitely be worth posting the full page (or a demo at JS Fiddle or JS Bin) that fully reproduces your code.

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