Following is my code in which i am facing only one difficulty that when i run the following script then due to comparison failure the $flag doesnot echo kindly let me know how to fix this?
$s = "iph4on comes";
$se = "4gb comes in iphone";
$f = 0;
$tf = explode(" ",$searching);
$ms= explode(" ",$search_in);
foreach($tf as $word)
{
if (!preg_match("/$word/i", $search_in))
//if (!strpos($search_in, $word));
return false;
}
{
$f = 1;
}
echo $f;
//Due to return flase above i am not echoing
echo "Comparison Failed";
return terminates the currently executing code block and "returns" to whatever called that code. if you execute a return in the top level of the code, it's essentially an exit() call and your echo will never be reached.
Why not just put an echo $flag before the return statement?
if (!preg_match("/$word/i", $search_in)){
echo $flag
return false;
}
You need to put the echo before the return. return gets the execution back to the calling function, hence any code after that won't be executed.
if (!preg_match("/$word/i", $search_in)) {
$flag = 1;
echo $flag;
echo "Comparison Failed";
return false;
}
Related
Is there a way to use return in a function with an if statement?
I would like to see either the function was executed until the if statement or not.
This would help me to check if the sql query would be executed as well.
I know to 100% I only could check it on the sql response, but I am looking for the shortest way to figure out if the content of a function was executed or not.
Here is an example:
<?php
function hi($i)
{
return (1==$i){echo "Hello"; };
}
$i = '1';
echo hi($i);
?>
I try to avoid to use it like this, since I always require to add an return before the end of the if statement:
<?php
function hi($i)
{
if(1==$i){
echo "Hello";
};
return true;
}
$i = '1';
echo hi($i);
?>
<?php
function ifReturn($input){
$message="";
if ($input == 3){
$message ="input is 3";
} else {
$message = "input is everything BUT 3";
}
return $message;
}
echo '<p>'.ifReturn(3).'</p>';
echo '<p>'.ifReturn(2).'</p>';
Im writing a page in HTML/PHP that connects to a Marina Database(boats,owners etc...) that takes a boat name chosen from a drop down list and then displays all the service that boat has had done on it.
here is my relevant code...
if(isset($_POST['form1'])){//if there was input data submitted
$form1 = $_POST['form1'];
$sql1 = 'select Status from ServiceRequest,MarinaSlip where MarinaSlip.SlipID = ServiceRequest.SlipID and BoatName = "'.$form1.'"';
$form1 = null;
$result1 = $conn->query($sql1);
$test = 0;
while ($row = mysqli_fetch_array($result1, MYSQLI_ASSOC)) {
$values1[] = array(
'Status' => $row['Status']
);
$test = 1;
}
echo '<p>Service Done:</p><ol>';
if($test = 1){
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
echo '</ol>';
}else{
echo 'No service Done';
}
the issue im having is that some of the descriptions of sevice are simply Open which i do not want displayed as service done, or there is no service completed at all, which throws undefined variable: values1
how would I stop my script from adding Open to the values1 array and display a message that no work has been completed if values1 is empty?
Try this
$arr = array();
if (empty($arr))
{
echo'empty array';
}
We often use empty($array_name) to check whether it is empty or not
<?php
if(!empty($array_name))
{
//not empty
}
else
{
//empty
}
there is also another way we can double sure about is using count() function
if(count($array_name) > 0)
{
//not empty
}
else
{
//empty
}
?>
To make sure an array is empty you can use count() and empty() both. but count() is slightly slower than empty().count() returns the number of element present in an array.
$arr=array();
if(count($arr)==0){
//your code here
}
try this
if(isset($array_name) && !empty($array_name))
{
//not empty
}
You can try this-
if (empty($somelist)) {
// list is empty.
}
I often use empty（$arr) to do it.
Try this instead:
if (!$values1) {
echo "No work has been completed";
} else {
//Do staffs here
}
I think what you need is to check if $values1 exists so try using isset() to do that and there is no need to use the $test var:
if(isset($values1))
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
Or try to define $values1 before the while:
$values1 = array();
then check if it's not empty:
if($values1 != '')
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
All you have to do is get the boolean value of
empty($array). It will return false if the array is empty.
You could use empty($varName) for multiple uses.
For more reference : http://php.net/manual/en/function.empty.php
Let's say I have a simple code:
while(1) {
myend();
}
function myend() {
echo rand(0,10);
echo "<br>";
if(rand(0,10) < 3) break;
}
This will not work with error code 'Fatal error: Cannot break/continue 1 level on line'.
So is there any possibility to terminate the loop during a subfunctin execution?
Make the loop condition depend upon the return value of the function:
$continue = true;
while( $continue) {
$continue = myend();
}
Then, change your function to be something like:
function myend() {
echo rand(0,10);
echo "<br>";
return (rand(0,10) < 3) ? false : true;
}
There isn't. Not should there be; if your function is called somewhere where you're not in a loop, your code will stop dead. In the example above, your calling code should check the return of the function and then decide whether to stop looping itself. For example:
while(1) {
if (myend())
break;
}
function myend() {
echo rand(0,10);
echo "<br>";
return rand(0,10) < 3;
}
Use:
$cond = true;
while($cond) {
$cond = myend();
}
function myend() {
echo rand(0,10);
echo "<br>";
if(rand(0,10) < 3) return false;
}
So I've been trying to devise a function that will echo a session variable only if it is set, so that it wont create the 'Notice' about an undefined variable. I am aware that one could use:
if(isset($_SESSION['i'])){ echo $_SESSION['i'];}
But it starts to get a bit messy when there are loads (As you may have guessed, it's for bringing data back into a form ... For whatever reason). Some of my values are also only required to be echoed back if it equals something, echo something else which makes it even more messy:
if(isset($_SESSION['i'])){if($_SESSION['i']=='value'){ echo 'Something';}}
So to try and be lazy, and tidy things up, I have tried making these functions:
function ifsetecho($variable) {
if(!empty($variable)) {
echo $variable;
}
}
function ifseteqecho($variable,$eq,$output) {
if(isset($variable)) {
if($variable==$eq) {
echo $output;
}
}
}
Which wont work, because for it to go through the function, the variable has to be declared ...
Has anyone found a way to make something similar to this work?
maybe you can achieve this with a foreach?
foreach ($_SESSION as $variable)
{function ifseteqecho($variable,$eq,$output) {
if($variable==$eq) {
echo $output;
}
else echo $variable;
}
}
now this will all check for the same $eq, but with an array of corresponding $eq to $variables:
$equiv = array
('1'=>'foo',
'blue'=>'bar',);
you can check them all:
foreach ($_SESSION as $variable)
{function ifseteqecho($variable,$equiv) {
if(isset($equiv[$variable])) {
echo $equiv[$variable];
}
else {
echo $variable;
}
}
}
Something like this?, you could extend it to fit your precise needs...
function echoIfSet($varName, array $fromArray=null){
if(isset($fromArray)){
if(isset($fromArray[$varName])&&!empty($fromArray[$varName])){
echo $fromArray[$varName];
}
}elseif(isset($$varName)&&!empty($$varName)){
echo $$varName;
}
}
You may use variable variables:
$cat = "beautiful";
$dog = "lovely";
function ifsetecho($variable) {
global $$variable;
if(!empty($$variable)){
echo $$variable;
}
}
ifsetecho("cat");
echo "<br/>";
ifsetecho("dog");
echo "<br/>";
ifsetecho("elephant");
UPDATE: With a rather complex code I’ve managed to meet your requirements:
session_start();
$cat = "beautiful";
$dog = "lovely";
$_SESSION['person']['fname'] = "Irene";
function ifsetecho($variable){
$pattern = "/([_a-zA-Z][_a-zA-Z0-9]+)".str_repeat("(?:\\['([_a-zA-Z0-9]+)'\\])?", 6)."/";
if(preg_match($pattern, $variable, $matches)){
global ${$matches[1]};
if(empty(${$matches[1]})){
return false;
}
$plush = ${$matches[1]};
for($i = 2; $i < sizeof($matches); $i++){
if(empty($plush[$matches[$i]])){
return false;
}
$plush = $plush[$matches[$i]];
}
echo $plush;
return true;
}
return false;
}
ifsetecho("cat");
echo "<br/>";
ifsetecho("dog");
echo "<br/>";
ifsetecho("elephant");
echo "<br/>";
ifsetecho("_SESSION['person']['fname']");
echo "<br/>";
ifsetecho("_SESSION['person']['uname']");
echo "<br/>";
I have a function that returns either a value into a variable if it is successful or it returns an errors array. see part of it below.
function uploadEmploymentDoc($var, $var2){
$ERROR = array();
if(empty($_FILES['file']['tmp_name'])){
$ERROR[] = "You must upload a file!";
}
//find the extensions
$doctypeq = mysql_query("SELECT * FROM `DocType` WHERE `DocMimeType` = '$fileType'");
$doctype = mysql_fetch_array($doctypeq);
$docnum = mysql_num_rows($doctypeq);
if($docnum == 0){
$ERROR[] = "Unsupported file type";
}
if(empty($ERROR)){
// run my code
return $var;
} else{
return $ERROR;
}
then when I run my code
$result = uploadEmploymentDoc(1, 2);
if($result !=array()){
// run code
} else {
foreach($result as $er){
echo $er."<br>";
}
}
Now my question is this. Why is my function running my code and not showing me an error when I upload an unsupported document type. Am I defining my foreach loop correctly? For some reason I cant get my errors back.
you should write like this-
if(is_array($result)){
foreach($result as $er){
echo $er."<br>";
}
} else {
//your code for handling error
}
You can get more info :http://us2.php.net/is_array
Try use
$result = uploadEmploymentDoc(1, 2);
if(!is_array($result)){
// run code
} else {
foreach($result as $er){
echo $er."<br>";
}
}
Probably will be better add parameter by reference to function for the errors array. From function return "false" if error and value if no error occurred.