SQL Query not ordering results properly - php

Question

I'm querying my database to return a set of results from highest to lowest. But, it seems as if the query isn't entirely ordering the results that way. My code is as follows:
$query = mysql_query("SELECT * FROM ".$stats_table." ORDER BY ppg DESC")or die(mysql_error());
$count = mysql_num_rows($query);
$i = 0;
while($row = mysql_fetch_assoc($query))
{
$team[$i] = $row['team'];
$ppg[$i] = $row['ppg'];
$i++;
}
for($i=0;$i<$count;$i++)
{
echo "".$ppg[$i]." <br /><br />";
}
When I echo out the ppg column set I get the following:
99.7
98.2
97.8
97.4
97.1
96.9
96.8
96.3
96.2
95.5
94.6
94.5
94.3
93.9
93.2
92.8
92.2
91.5
90.8
90.3
106.0
105.9
104.5
103.6
102.6
101.9
101.5
101.3
100.7
100.1
It seems that for all of the values less than 100 and over 100 it works. But, how can I make this order work with all values instead of just within those less than and above 100?
Thanks,
Lance

Answer 1

Change the data type to numeric like double, real, float. Try it.

Answer 2

Make ppg double, real or anything numeric, not varchar.

Answer 3

Use ORDER BY ABS(ppg) if you don't want to touch your structure

Answer 4

You could let PHP sort it.
$query = mysql_query("SELECT * FROM ".$stats_table)or die(mysql_error());
$i = 0;
while($row = mysql_fetch_assoc($query)) {
$team[$i] = $row['team'];
$ppg[$i] = (int)$row['ppg'];
$i++;
}
sort($ppg, SORT_NUMERIC);
for($i=0;$i<count($ppg);$i++) {
echo $ppg[$i]." <br /><br />";
}