How to save query in multidimesional array? - php

Question

I have this script executing as a cron job everyday to update days remaining to pay invoices. I first query every row of my table and attempt to store the data in a multidimensional array but this seems to be storing everything I query in the first element of my array.
Here's my script:
<?php
include '../inc/dbinfo.inc';
ini_set("log_errors", 1);
ini_set("error_log", "/tmp/php-error.log");
error_log( "################################################# UpdateVendorInvoiceDays.php #################################################" );
$three = 3;
$fetchAllInvoices = "SELECT VENDORINVOICEID, VdrInvoiceReceived, PaymentDue, COUNT(*), DATEDIFF(PaymentDue, NOW()) FROM tblVendorInvoices WHERE VdrInvoiceStatusID != ?";
$getInvoices = $conn->prepare($fetchAllInvoices);
$getInvoices->bind_param("i", $three);
$getInvoices->execute();
$result = $getInvoices->get_result();
$rows = array();
$j = 0;
while($row = $result->fetch_assoc())
{
$rows[$j][] = $row;
$j++;
}
echo json_encode($rows[0][0]); //Only outputs one row
//UPDATE DAYS REMAINING IN EACH ENTRY THAT ISNT PAID
$updateDaysRemaining = "UPDATE tblVendorInvoices SET DaysRemaining = ? WHERE VENDORINVOICEID = ? AND VdrInvoiceStatusID ! = ?";
$setDays = $conn->prepare($updateDaysRemaining);
$k = 0; //incrementor
$numberOfEntries = $rows['COUNT(*)'];
for($k;$k<$numberOfEntries;$k++){
$setDays->bind_param("iii", $rows[$k]["DATEDIFF(PaymentDue, NOW())"],
$rows[$k]['VENDORINVOICEID'], $three);
if($setDays->execute()){
error_log('Cron success');
}else{
error_log('Cron fail');
}
}
?>
Currently the output from my first query is:
[[{"VENDORINVOICEID":88,"VdrInvoiceReceived":"2018-08-21","PaymentDue":"2018-07-27","COUNT(*)":2,"DATEDIFF(PaymentDue, NOW())":-25}]]
and my error log only gives me a notice for $rows['COUNT(*)'] being undefined (which makes sense)
I've looked at other answers here but they don't seem to have the same structure as I do.
EDIT: I also have 2 rows in my database but this only puts out one. I forgot to mention this.

Answer 1

There are a couple of simplifications to get all of the rows. Instead of...
while($row = $result->fetch_assoc())
{
$rows[$j][] = $row;
$j++;
}
echo json_encode($rows[0][0]);
You can just return all rows using fetch_all()...
$rows = $result->fetch_all (MYSQLI_ASSOC);
echo json_encode($rows);
Then encode the whole array and not just the one element - which is what $rows[0][0] was showing you.
As for you other problem - change in your select statement to
COUNT(*) as rowCount
and then you can use this alias for the field reference...
$rows['COUNT(*)']
becomes
$rows['rowCount']