Increment integer in set range - php

Question

If I want to loop through an array and then use them as looped increment counters, how would I do that?
E.g. I have up to 5 values stored in an array. I want to loop through them, and in the forst loop I want to use a specific value, then for the second another specific value.
Pseudo code below, but how do I bring in the second array into the picture? The first range is going to dynamic and empty or have up to 5 values. The second will be fixed.
$array = array(2,6,8); // Dynamic
$array2 = array(11,45,67,83,99); Fixed 5 values
foreach ($array as $value) {
// First loop, insert or use both 2 and 11 together
// Second loop, insert or use both 6 and 45
// Third loop, insert or use both 8 and 67
}

Answer 1

Use $index => $val:
foreach ($array2 as $index => $value) {
if ( isset($array[ $index ]) ) {
echo $array[ $index ]; // 2, then 6, then 8
}
echo $value; // 11, then 45, then 67, then 83, then 99
}
See it here in action: http://codepad.viper-7.com/gpPmUG
If you want it to stop once you're at the end of the first array, then loop through the first array:
foreach ($array as $index => $value) {
echo $value; // 2, then 6, then 8
echo $array2[ $index ]; // 11, then 45, then 67
}
See it here in action: http://codepad.viper-7.com/578zfQ

Answer 2

You can try this-
foreach ($array as $index => $value) {
echo $array[ $index ]; // 2, then 6, then 8
echo $array2[ $index ]; // 11, then 45, then 67
}

Answer 3

Here's a clean and simple solution, that does not uses useless and heavy non standard libraries:
$a = count($array);
$b = count($array2);
$x = ($a > $b) ? $b : $a;
for ($i = 0; $i < $x; $i++) {
$array[$i]; // this will be 2 the first iteration, then 6, then 8.
$array2[$i]; // this will be 11 the first iteration, then 45, then 67.
}
We just use $i to identify the same position of the two arrays inside the main for loop in order to use them together. The main for loop will iterate the correct number of times so that none of the two arrays will use undefined indexes (causing notices errors).

Answer 4

Determine the minimum length of both arrays.
Then loop your index i from 1 to the minimum length.
Now you can use the i-th element of both arrays

Answer 5

Here is what I think you want:
foreach($array as $value){
for($x = $value; $array[$value]; $x++){
//Do something here...
}
}

Answer 6

You can use a MultipleIterator:
$arrays = new MultipleIterator(
MultipleIterator::MIT_NEED_ANY|MultipleIterator::MIT_KEYS_NUMERIC
);
$arrays->attachIterator(new ArrayIterator([2,6,8]));
$arrays->attachIterator(new ArrayIterator([11,45,67,83,99]));
foreach ($arrays as $value) {
print_r($value);
}
will print:
Array ( [0] => 2 [1] => 11 )
Array ( [0] => 6 [1] => 45 )
Array ( [0] => 8 [1] => 67 )
Array ( [0] => [1] => 83 )
Array ( [0] => [1] => 99 )
If you want it to require both arrays to have a value, change the flags to
MultipleIterator::MIT_NEED_ALL|MultipleIterator::MIT_KEYS_NUMERIC
which will then give
Array ( [0] => 2 [1] => 11 )
Array ( [0] => 6 [1] => 45 )
Array ( [0] => 8 [1] => 67 )