I have 2 arrays in PHP. One of them holds a list of dates, the other a list of numbers.
Array1
(
[0] => 2010-06-14
[1] => 2010-06-14
[2] => 2010-06-14
[3] => 2014-01-26
[4] => 2014-01-26
)
Array2
(
[0] => 120
[1] => 100
[2] => 60
[3] => 140
[4] => 30
)
The value [0] in Array2 belongs with the date [0] in Array1. What I am trying to do is add all of the values in Array2 together, based on the date. Any dates that match should have their values added together. So for example at the end I would like something like:
$date = 2010-06-14;
$value = 280;
$date = 2014-01-26;
$value = 170;
...and so on.
I've searched though the site but was unable to find exactly what I needed. Any help would be appreciated...
You can iterate $values, and get the corresponding date from $dates to use as the key in your result array.
foreach ($values as $key => $value) {
$result[$dates[$key]] = $value + ($result[$dates[$key]] ?? 0);
}
The output will be like this:
array (size=2)
'2010-06-14' => int 280
'2014-01-26' => int 170
$sum=0; // New Element
$Array3[][]=0; // New 2D array
$p=0; // Counter for 2D array
for($i=0;$i<5;$i++) // Single loop for traversing
{
$date=Array1[$i]; // Start for a date
while($date==Array1[$i]){ // For for Similar date
$sum=$sum+Array2[$i]; // Adding values of similar date
$i++; // Increment array
}
$Array3[$p]["date"]=$date; // Array3 date element
$Array3[$p]["sum"]=$sum; // Array4 date element
$i--; // Reducing a value which is incremented in while loop
}
Array3 is like
Array3
(
[0] => array( 'date' => " ",'sum' => " ")
[1] => array( 'date' => " ",'sum' => " ")
)
Are you trying to count all of the values in Array2 that have an entry in Array1 that matches some predefined target value?
If so, this for loop version should work:
private function forLoopVersion($array1, $array2, $target) {
$result = 0;
for ($i = 0; $i < count($array1); ++$i) {
if ($array1[$i] == $target) {
$result += $array2[$i];
}
}
return $result;
}
Also, this foreach loop version might work, but I do not know if the $key for $array1 can be used to index an element in $array2. You could try it:
private function foreachLoopVersion($array1, $array2, $target) {
$result = 0;
foreach ($array1 as $key => $value) {
if ($value == $target) {
$result += $array2[$key];
}
}
return $result;
}
$newArray = array();
for($i = 0; $i < count(Array1); $i++) {
$newArray[$Array1[$i]] = $Array2[$i];
}
echo $newArray[$date1] + $newArray[$date2];
Put the dates as keys to for easy math.
Related
I have an array from array_diff function and it looks like below:
Array
(
[0] => world
[1] => is
[2] => a
[3] => wonderfull
[5] => in
[6] => our
)
As you can see, we have a gap between the keys #3 and #5 (i.e. there is no key #4).
How can I split that array into 2 parts, or maybe more if there are more gaps?
The expected output would be:
Array
(
[0] => Array
(
[0] => world
[1] => is
[2] => a
[3] => wonderfull
)
[1] => Array
(
[0] => in
[1] => our
)
)
You can use old_key,new_key concept to check that there difference is 1 or not? if not then create new index inside you result array otherwise add the values on same index:-
<?php
$arr = Array(0 => 'world',1 => 'is',2 => 'a',3 => 'wonderfull',5 => 'in',6 => 'our');
$new_array = [];
$old_key = -1;
$i = 0;
foreach($arr as $key=>$val){
if(($key-$old_key) ==1){
$new_array[$i][] = $val;
$old_key = $key;
}
if(($key-$old_key) >1){
$i++;
$new_array[$i][] = $val;
$old_key = $key;
}
}
print_r($new_array);
https://3v4l.org/Yl9rp
You can make use of the array internal pointer to traverse the array.
<?php
$arr = Array(0=>"world",1=>"is",2=>"a",3=>"wonderfull",5=>"in",6=>"our");
print_r($arr);
$result = Array();
$lastkey;
while($word = current($arr))
{
$key = key($arr);
if(isset($lastkey) && $key == $lastkey + 1)
{
$result[count($result) - 1][] = $word;
}
else
{
$result[] = Array($word);
}
$lastkey = $key;
next($arr);
}
print_r($result);
?>
This task is a perfect candidate for a reference variable. You unconditionally push values into a designated "bucket" -- in this case a subarray. You only conditionally change where that bucket is in the output array.
There are two important checks to make when determining if a new incremented key should be generated:
if it is not the first iteration and
the current key minus (the previous key + 1) does not equal 0.
Code: (Demo)
$nextKey = null;
$result = [];
foreach ($array as $key => $val) {
if ($nextKey === null || $key !== $nextKey) {
unset($ref);
$result[] = &$ref;
}
$ref[] = $val;
$nextKey = $key + 1;
}
var_export($result);
This solution generates an indexed array starting from zero with my sample input and uses only one if block. In contrast, AliveToDie's solution generates a numerically keyed array starting from 1 and uses two condition blocks containing redundant lines of code.
If I have this array:
Array (
[0] => Array (
[booking_id] => 1
[booking_status] => confirmed
[client_name] => Bale
[client_firstname] => Gareth
[days] => Array (
[day_id] => 2016-11-23,2016-11-24
[room_id] => 2
)
)
)
How can I get the number of item into day_id please?
You can use array_reduce to iterate through array items and get a final result. Take a look at this:
function reduce_func($carry, $item){
if (isset($item['days']) && !empty($item['days']['day_id'])){
$carry += count(array_unique(array_filter(explode(',', $item['days']['day_id']))));
}
return $carry;
}
$result = array_reduce($arr, "reduce_func", 0);
Update
note that you can also provide a callback to the array_filter to filter out your desired entries to be counted, eg. regex checking each entry to be a valid date. Here's PHP manual for array_filter.
$sum = 0;
foreach ($data as $booking) {
$sum += sizeof(explode(",",$booking["days"]["day_id"]));
}
$sum =0;
for ($count = 0; $count < count($data); $count++) {
$booking = $data[$count];
$day_ids = explode(",", $booking['days']['day_id'];
$sum = $sum + count($day_ids);
}
Supposing I have an Array with x elements. I would like to loop through this Array in "tens" and add a run-Time variable. This means that each set of 10 Arrays will have a unique run-time. I am using the code below:
$time = '00:00:00';
$k = 0;
for ($i = 0; $i < count($agnt_arr); $i+=10) {
$temp = strtotime("+$k minutes", strtotime($time));
$runTime = date('H:i', $temp);
array_push($agnt_arr[$i], $runTime);
$k+=4;
}
Where $agnt_arr is an Array with the following structure :
Array
(
[0] => Array
(
[name] => User.One
[email] => User.One#mail.com
)
[1] => Array
(
[name] => User.Two
[email] => User.Two#mail.com
)
[2] => Array
(
[name] => User.Three
[email] => User.Three#mail.com
)
)
The problem I'm having is the run times are only added to the 10th element which is expected But I would like elements 0-9 to have the same run time and 10-20 etc. How would I achieve something like this??
Probably easier like this always adding runtime but updating it for each 10:
$time = '00:00:00';
foreach($agent_arr as $key => $value) {
if($key % 10 === 0) {
$temp = strtotime("+$k minutes", strtotime($time));
$runTime = date('H:i', $temp);
}
$agent_arr[$key]['runtime'] = $runTime;
}
Here's my overcomplicated solution(and probably unnecessary):
$new_array = array();
foreach(array_chunk($array, 10 /* Your leap number would go here */) as $k => $v)
{
array_walk($v, function($value, $key) use (&$new_array){
$value['time'] = $time;
$new_array[] = $value;
});
}
I've a $_POST that sends an array. And i've a prevoious array with contains a key that could contain or not one of the values from teh $_POST.
For Example:
$_post: Array ( [0] => 13 [1] => 10 [2] => 52)
Previous: Array ( [0] => Array ( [collection_id] => 13 [artwork_id] => 21 )
[1] => Array ( [collection_id] => 11 [artwork_id] => 21 ) )
So i need to check if the $_POST itms already exists on the previuos array ([collection_id] key) and extract the new ones (in this case [1] => 10 [2] => 52) to ve added to the database and also get those which has changed that need to be removed from the database (replaced) by the new values.
This my current code but not working well...
$new_nodes = array();
$i = 0;
foreach($old_nodes as $node){
foreach ($collections as $collection) {
$new = array('collection_id' => $collection, 'artwork_id' => $artwork['id']);
if(array_diff($node, $new)){
if($collection > 0){
array_push($new_nodes, $new);
}
}
else{
unset($old_nodes[$i]);
}
}
$i++;
}
foreach($new_nodes as $node){
for ($i = 0; $i <= count($new_nodes); $i++) {
if(isset($new_nodes[$i])){
if(!array_diff($node, $new_nodes[$i])){
unset($new_nodes[$i]);
}
}
}
}
NOTE: old_nodes is "Previous" and $collections is "$_POST"
Try something like this:
$old_nodes = array();
$new_nodes = array();
$del_nodes = array();
foreach ($collections as $collection) {
array_push($old_nodes, $collection['collection_id']);
}
$new_nodes = array_diff($collections, $old_nodes);
$del_nodes = array_diff($old_nodes, $collections);
$cnt[0]=>Array( [0] => 0 [1] => 0 [2] => 0 ),
$cnt[1] => Array ( [0] => 1 [1] => 0 [2] => 0 )
i want convert this array to below result,
$cnt[0]=(0,0);
$cnt[1]=(0,0);
$cnt[2]=(0,1);
any php function there to convert like this format,
Thanks,
Nithish.
function flip($arr)
{
$out = array();
foreach ($arr as $key => $subarr)
{
foreach ($subarr as $subkey => $subvalue)
{
$out[$subkey][$key] = $subvalue;
}
}
return $out;
}
see more example in
PHP - how to flip the rows and columns of a 2D array
I'm interpreting your expected output to be something like a list of pairs:
$pairs = array(
array(1,0),
array(0,0),
array(0,0)
);
You'd simply check that the sub-arrays are the same length, and then use a for loop:
assert('count($cnt[0]) == count($cnt[1])');
$pairs = array();
for ($i = 0; $i < count($cnt[0]); ++$i)
$pairs[] = array($cnt[0][$i], $cnt[1][$i]);