PHP Array Zeros except for one, extract that value - php

Question

I have an array with values that change from time to time. It will usually look like this:
Array ( [0] => 0 [1] => 0 [2] => 9876 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 )
All of the Values will be 0 except for one (index location will change).
If more than one value is greater than 0, I need to execute a specific command.
Else, if only one value is greater than 0, I need to take that value and pass it to a specific command.

Answer 1

Create a new array containing only the non-null values. array_filter without callback will return all elements which do not evaluate to FALSE.:
$a = array(...);
$values = array_filter($a);
switch(count($values)) {
case 0: echo 'All 0!'; break;
case 1: specificCommandWithValue($values[0]); break;
default: executeSpecificCommand(); break;
}
If you have false-y values, you want to keep (FALSE, NULL, '0', ''), pass a callback which does strict value comparison: function($el) { return $el !== 0; }

Answer 2

try
$count =0;
foreach($array as $item){
if($item !=0){
$count = $count+1;
}
}
if($count > 1){
//execute a specific command
}elseif($count == 1){
// take that value and pass it to a specific command
}else{
//all value are zero
}

Answer 3

Try this code.
<?PHP
$array = array(
"1" => "0",
"2" => "0",
"3" => "0",
"4" => "24",
"5" => "0");
$zero_plus_keys = 0;
$zero_plus_val = array();
foreach($array as $key => $val)
{
if($val > 0)
{
$zero_plus_keys++;
$zero_plus_val = array($key,$val);
}
}
if($zero_plus_keys == 1)
{
echo "In array '".$zero_plus_val[0]."' key contains Greater than zero value. the value is = '".$zero_plus_val[1]."'";
}
elseif($zero_plus_keys > 1)
{
echo "More keys Greater than zero(0)";
}
else
{
echo "All keys contains zero(0)s only...";
}
?>

Answer 4

This is #NullPointer's answer, but I added in a variable to hold "that value".
$count =0;
$nonzero = null;
foreach($array as $item){
if($item !=0){
$count = $count+1;
$nonzero = $item;
}
}
if($count > 1){
//execute a specific command
}elseif($count == 1){
specific_command($nonzero);
}else{
//all value are zero
}

Answer 5

$array = 'your array';
function Find($array){
$count = 0;
$needle = -1;
foreach($array as $item){
if($item > 0){
$count++;
$needle = $item;
}
if($count > 1)
return -1; //error as number of non-zeroes greater than 1
}
if($count > 0)
return $needle; //returns the required single non-zero item
return 0; // returns zero if nothing is found
}
$return = Find($array);

Answer 6

Just for fun :P
$array = array_flip(array_flip($array));
sort($array);
if (count($array) > 2) moreThanOne();
else onlyOne($array[1]);

Answer 7

Filter the array and if there is only one use current() to get it:
if(count($n = array_filter($array)) == 1) {
execute_command(current($n));
} else {
execute_command();
}