"Unexpected end of input" using Ajax - php

Question

I am building a thread-messaging system. I used AJAX to send the parent_id to the php file which retrieved the thread (many messages with the same parent_id)
in the ajax, I send the parent_id
data:{
parent_id: $(this).data('id'),
ajax: 'true'
},
I use this parent_id in the php file using a query which retrieves some rows and I pass them back using this :
$ret_msg_query_result=mysql_query($retrive_query);
while ($retrieved_msg_fetched=mysql_fetch_assoc($ret_msg_query_result))
{
echo json_encode($retrieved_msg_fetched) . "\n";
}
and then back to Ajax:
$(document).ready(function() {
$(".msgsRow li.msg_subject,.msgsRow li.msg_content").click(function() {
$.ajax({
type: 'POST',
url: AJAX_URL+"front/RetrieveMsg.php",
data:{ parent_id: $(this).data('id'), ajax: 'true' },
success: function(data) {
var strLines = data.split("\n");
for (var i in strLines) {
var obj = JSON.parse(strLines[i]);
console.log(obj.id);
}
}
});
});
});
I got this way (of splitting) to convert each row into an object from a post here on Stackoverflow Sending/Parsing multiple JSON objects
The function works right retrieving the ids of messages and even retrieving the full row. But I get
"Uncaught SyntaxError: Unexpected end of input "
and it points to the line before console.log(obj.id);
I searched StackOverflow for this error and it usually appears for missing a closing parenthesis but I can'd find any.
Thanks,

Answer 1

You are missing a } on in this function
success: function(data){
var strLines = data.split("\n");
for (var i in strLines) {
var obj = JSON.parse(strLines[i]);
console.log(obj.id);
**}**
}
NOTE: remove the 4x*, those should not be there :)
That should fix it!

Answer 2

I figured out the problem ... It's because I am splitting using "/n" which makes the strLines be something like {row},{row},{row},
The comma in the end causes the unexpected end. So, I used a counter to check the number of row, if it's the last, then don't insert "/n"
$counter=1;
while ($retrieved_msg_fetched=mysql_fetch_assoc($ret_msg_query_result))
{
if ($counter==mysql_num_rows($ret_msg_query_result))
{
echo json_encode($retrieved_msg_fetched);
}
else{
echo json_encode($retrieved_msg_fetched) . "\n";
$counter++;
}
}
Thanks Limelights for your help too :)

Answer 3

I got this when I forgot to return something from my php-script when it worked fine. I just added something like this:
die (json_encode (array ('reponse'=>'Your script worked fine')));
at the end of my php-script, and that solved it. You can also use 'response' to check it it worked fine.