I am doing something like this, I am passing a variable to a php script via post with AJAX. It is actually getting inside my php and running my echo, however it is not printing anything out when I print the $_POST array.
function ajaxFunction(data){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
ajaxRequest.open("POST", "process.php", true);
ajaxRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajaxRequest.setRequestHeader("Content-length", data.length);
ajaxRequest.setRequestHeader("Connection", "close");
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
//var data = array();
//data = document.forms["order_form3"].getElementsByTagName("input");
}
}
ajaxRequest.send(data);
}
I recommend to use a plugin like firebug or even the built in functionalities of Chrome or Firefox to see what has been sent and what has been received in your post request.
The ajax response is not printed somewhere on your screen as you might know it from "normal" http POST requests to a php page. It will be returned as part of your ajaxRequest object and you can fetch it from there to use Javascript to "print" it.
Seems you need to encode your parameters, calling your function does submit your data, however they are unbound to a variable on the other end. I'm not surprised PHP throws your data away.
See here: AJAX XMLHttpRequest POST
Related
I am working in a chat system that relies on a mysql database.
At the beginning of the first loading of the page sending the following query:
SELECT * FROM `Shoutbox` ORDER BY `Shoutbox`.`ID` ASC LIMIT 0 , 30
and then using a while loop mold all messages (with user names and date) in a div.
while($array=mysql_fetch_array($dati)) {
echo "<div class='tag_li $array[ID]'><span class='when'>$array[DateTime]</span><span class='linea mess'><span id='author'><a onclick='ajaxLoadContent(this)' link='profile.php?name=$array[User]'>$array[User]</a></span>: $array[Message]</span></div>";
}
Now I would like to be sent every second query, and then updates the contents of the div with new messages if any.
How can I send a SQL query in a range?
I will assume you are using javascript and want to make an ajax call.
Start with the timer on the client side
window.setInterval("ajaxFunction()",milliseconds);
And the ajax function
function ajaxFunction(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById('ajaxDiv');
ajaxDisplay.innerHTML = ajaxDisplay.innerHTML + ajaxRequest.responseText;
}
}
ajaxRequest.open("GET", "ajax-example.php" , true);
ajaxRequest.send(null);
}
the php part
while($array=mysql_fetch_array($dati)) {
echo "<div class='tag_li $array[ID]'><span class='when'>$array[DateTime]</span><span class='linea mess'><span id='author'><a onclick='ajaxLoadContent(this)' link='profile.php?name=$array[User]'>$array[User]</a></span>: $array[Message]</span></div>";
}
And the html part
<div id="ajaxDiv"></div>
That should give you an idea how it is done.
I am trying to write the code to let users upload their profile picture using php. I want the image to be updated without reloading the page. I have tried using ajax to do this.
My ajax code is:
function f()
{
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
x=document.getElementById("img"); //Find the element
x.innerHTML=ajaxRequest.responseText; //Change the content
}
}
ajaxRequest.open("POST", "Uploadimage.php", true);
ajaxRequest.send();
}
Uploadimage.php is the file in which uploads the image and moves it into a folder.The $_FILES has the details of the file(filename,type etc...).
The above code is not working i.e., the image is not getting updated.Please help me how to correct this.
Thank you.
Personally I would only return the new url name of the profile pic and change the src of the profile pic upon success. Such as:
x = document.getElementById('img'); // If this is the <img> tag
x.src = ajaxRequest.responseText;
Note that the url name of the new pic will need a new url, or else I don't think any browser will try to reload the pic, regardless of caching rules set by the server.
First off - NO JQUERY. I hate that thing with a passion and I can't possibly imagine how a native code implementation would be less efficient.
What I am after is a way to call any PHP function from Javascript and pass parameters to the function using call_user_func_array. I have written this exact code before but can't think of how I did it.
In the end, I want to be able to (in JS) be able to do something like:
var responseString = callPhpFunction(func, param1, param2, etc);
`
Which is an ideal and will probably involve a few nested functions. At the moment I have the basic Ajax request. Needs to be POST, and doesn't have to handle multiple requests simultaneously.
var lastResponse = '';
function phpFunction(funcName){
var ajaxRequest;
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject('Msxml2.XMLHTTP');
} catch (e) {
try{
ajaxRequest = new ActiveXObject('Microsoft.XMLHTTP');
} catch (e){
// Something went wrong
alert('Ajax/Browser problem!');
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
//Seems to work.
window.lastResponse = ajaxRequest.responseText;
}
}
ajaxRequest.open('POST', 'ajaxCall.php', true);
ajaxRequest.send('func='+funcName); //Need to generate parameters dynamically, not sure how to do that
}
This shouldn't be really complex, but I've never seen a good implementation of it.
Any ideas?
been working on a new site, and run into a problem.
I have an ajax loader on my main page, which loads a script every second to check if a background process is completed (usually 20 seconds-ish)
But, once the ajax script has executed (20 seconds later) it still refreshes every second.
I need to redirect the parent page to a new url, once the ajax script has finished its job.
My ajax code:
<script type="text/javascript">
function myFunction()
{
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
document.getElementById("txtHint").innerHTML=ajaxRequest.responseText;
}
}
ajaxRequest.open("GET", "code/timer.php?file='.$file.'", true);
ajaxRequest.send(null);
}
</script>
<script type="text/javascript">
function forward(){
location.href=\'http://domain/newpage.html\';
}
function setTimer(){
set = setInterval( "myFunction()", 1000 );
}
</script>
the backslashes in forward(); are because my code is echoed from php.
i have tried a few codes, but the main one that should work (in child ajax element) is:
window.opener.forward();
would be greatful of any help you guys can provide... thanks
opener is only available in windows opened with javascript, call simply
forward();
but you should use another name for the function, there is a predefined method window.forward()
I am using AJAX function. I am passing 3 variables to the next page using AJAX. When I add the 4th variable the function doesn't get called.
Code:
<script language="javascript" type="text/javascript">
//Browser Support Code
function ajaxFunction(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById('ajaxDiv');
ajaxDisplay.innerHTML = ajaxRequest.responseText;
}
}
var count = document.getElementById('count').value;
var type = document.getElementById('type').value;
var sem = document.getElementById('sem').value;
var rid = document.getElementById('room').value;
ajaxRequest.open("GET", "add_requi_ajax.php?count=" + count+"&type="+ type+"&sem="+sem+"&rid="+rid, true);
ajaxRequest.send(null);
};
</script>
Your code is syntactically and logically correct, which means that the problem is likely one of your input IDs is wrong (typo? Should room be rid?), or you call the function before the inputs are rendered on the page (use window.onload).
Verify each of your input IDs. If they all look correct, then comment them out and hard code the values to rule out your inputs as a problem. Watch the error console for any error messages. If an uncaught error is encountered, it can appear that the function isn't being called.
You probably need to urlencode your values.