I have an URL say: www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go. I want to extract the string register-car from it using php code. Please help.
try this:
<?php
$url = "www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go";
$register_car = basename(parse_url($url, PHP_URL_PATH));
echo $register_car; // will echo "register-car"
?>
You can use a combination of parse_url and basename, or even pathinfo to help you with this.
In PHP < 5.4.7
$url = "www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go";
$result = basename(parse_url("http://" . $url, PHP_URL_PATH));
echo $result; // register-car
In PHP >= 5.4.7
$url = "www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go";
$result = basename(parse_url("//" . $url, PHP_URL_PATH));
echo $result; // register-car
You are looking for the parse_url function, followed by basename to return the last /item/. The following prints register-car.
$parsed = parse_url("http://www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go", PHP_URL_HOST);
echo basename($parsed['path']);
$parts = parse_url("www.abc.com/blog/2012/12/register-car?w=Search&searchDmv=Go", PHP_URL_PATH);
$pieces = explode($parts, "/");
$action = $pieces[count($pieces)-1];
Related
I have a string $current_url that can contain 2 different values:
http://url.com/index.php&lang=en
or
http://url.com/index.php&lang=jp
in both cases I need to strip the query part so I get: http://url.com/index.php
How can I do this in php?
Thank you.
Simplest Solution
$url = 'http://url.com/index.php&lang=en';
$array = explode('&', $url);
echo $new_url =$array[0];
To only remove the lang query do this
$url = 'http://url.com/index.php&lang=en&id=1';
$array = explode('&lang=en', $url);
echo $new_url = $array[0] .''.$array[1];
//output http://url.com/index.php&id=1
So this way it only removes the lang query and keep other queries
If the value of your lang parameter is always of length 2, which should be the case for languages, you could use:
if(strpos($current_url, '&lang=') !== false){
$current_url = str_replace(substr($current_url, strpos($current_url, '&lang='), 8), '', $current_url);
}
If the substring "&lang=" is present in $current_url, it removes a substring of length 8, starting at the "&lang=" position. So it basically removes "&lang=" plus the 2 following chars.
You can Use strtok to remove the query string from url.
<?php
echo $url=strtok('http://url.com/index.php&lang=jp','&');
?>
DEMO
Answer based on comment.
You can use preg_replace
https://www.codexworld.com/how-to/remove-specific-parameter-from-url-query-string-php/
<?php
$url = 'http://url.com/index.php?page=site&lang=jp';
function remove_query_string($url_name, $key) {
$url = preg_replace('/(?:&|(\?))' . $key . '=[^&]*(?(1)&|)?/i', "$1", $url_name);
$url = rtrim($url, '?');
$url = rtrim($url, '&');
return $url;
}
echo remove_query_string($url, 'lang');
?>
DEMO
I have a link like below:
$link = http://mytour.com:8080/en/admin/dashboard//tmp/Rc4Lw3
How can i get it to be like the one below in PHP:
$link = http://mytour.com:8080
Sorry if this is a newbie question. Thanks.
parse_url($link)
$link = 'http://mytour.com:8080/en/admin/dashboard//tmp/Rc4Lw3';
$parsed_link = parse_url($link);
echo $parsed_link['scheme']."//".$parsed_link['host'].":".$parsed_link['port'];
preg_match() - worse
preg_match("/^http[s]*:\/\/.*:\d+/", $link, $match);
echo $match[0];
You can use parse_url() to get url you want
$url = 'http://mytour.com:8080/en/admin/dashboard//tmp/Rc4Lw3';
$parse_url = parse_url($url);
echo $link = $parse_url['scheme']."://".$parse_url['host'].":".$parse_url['port'];
echo "<br>";
//You can also use default method and params
echo $link = parse_url($url, PHP_URL_SCHEME)."//".parse_url($url, PHP_URL_HOST).":".parse_url($url, PHP_URL_PORT);
As suggested by #vladkras use parse_url($link)
$url = 'http://mytour.com:8080/en/admin/dashboard//tmp/Rc4Lw3';
$parse = parse_url($url);
echo $parse['scheme'].'://'.$parse['host'].':'.$parse['port'];
Output:
http://mytour.com:8080
$link = 'http://mytour.com:8080/en/admin/dashboard//tmp/Rc4Lw3';
$url = parse_url($link);
echo $url['scheme'].'://'.$url['host'].':'.$url['port'];
I have the following url : http:example.com/country/France/45.
With the pattern http:example.com/country/name/**NUMBER**(?$_GET possibly).
How can I extract the number with a regex (or something else then regex) ?
With regexp:
$str = 'http:example.com/country/France/45';
preg_match('/http:example\.com\/country\/(?P<name>\w+)\/(?P<id>\d+)/', $str, $matches);
print_r($matches); // return array("name"=>"France", "id" => 45);
$url = 'http:example.com/country/France/45';
$id = end(explode('/',trim($url,'/')));
Simple isn't ?
The usage of trim () is to remove trailing \
echo $last = substr(strrchr($url, "/"), 1 );
strrchr() will give last occurence of the / character and then substr() gives string after it.
use something like this
$url = "http://example.com/country/France/45";
$parts = explode('/', $url);
$number = $parts[count($parts) - 1];
and if you have GET variable at the end, you can explode further like this
$number = explode('?', $number);
$number = $number[0];
hope this helps :)
the get command for php is $_GET so to show to number do
<html>
<body>
<?php
echo $_GET["eg"];
?>
</body>
</html>
with a URL of http:example.com/country/name/?eg=**NUMBER**
Use explode():
$parts = explode('/', $url);
$number = $parts[count($parts)-1];
This question already has answers here:
Strip off specific parameter from URL's querystring
(22 answers)
Closed 8 years ago.
I have to remove the last element in a string. I used rtrim in php but it is not working.
This is the string:
/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC
I need to remove "&make_order=ASC"
Can anyone help me?
$s = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo substr($s, 0, strrpos($s, '&'));
Edit:
$url = $base_url.trim( $_SERVER['REQUEST_URI'], "&year_order=".$arr['year_order']."" );
// ^
// |_ replace , with .
trim should work:
$string = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
$string = trim($string, "&make_order=ASC");
There's no guarantee that make_order will be at the end of the query string - or exist at all. To remove the field properly, you'd have to use something like this:
$url = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
// break down the URL into a path and query string
$parsed = parse_url($url);
// turn the query string into an array that we can manipulate
$qs = array();
parse_str($parsed['query'], $qs);
// remove the unwanted field
unset($qs['make_order']);
// rebuild the URL
$rebuilt = $parsed['path'];
if(!empty($qs)) {
$rebuilt .= '?' . http_build_query($qs);
}
echo $rebuilt;
$actual_link = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
echo str_replace("&make_order=ASC","",$actual_link);
$string = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
$args = array_pop(explode($string, "&"));
$string = implode("&", $args);
There are a bunch of ways. The easiest might be:
$i=strrpos($text,'&');
$newstring=substr($text,0,$i);
$str = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
echo $str . "<br>";
echo trim($str,"&make_order=ASC");
if &make_order=ASC is always going to be at the end, you can use strstr() to do this
$str = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo strstr($str,'&make_order=ASC',true);
Remove desired key from url.
Use:
$s = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo remove_key_from_url($url, 'make_order');
Output :
/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100
Code:
function remove_key_from_url($url, $key) {
if (strpos($url, '?') === false) return $url;
list($left, $right) = explode('?', $url, 2);
parse_str($right, $get);
if (isset($get[$key])) unset($get[$key]);
return $left . '?' . http_build_query($get);
}
Can someone help me with replacing this url
http://www.izlesene.com/video/arabic-shkira-belly-dance/200012
to: 200012
$url = 'http://www.izlesene.com/video/arabic-shkira-belly-dance/200012';
$out = preg_replace("/[^0-9]/i","",$url);
or
preg_match("/\/([0-9]+)/i",$url,$m);
$out = $m[1];
use the basename
$video_id = basename($url);
var_dump($video_id);
or
try to explode and get the last item.
$url = "http://www.izlesene.com/video/arabic-shkira-belly-dance/200012";
$segments = explode("/",$url);
$video_id = end($segments);
var_dump($video_id);
If things works like in JS you can do it like so:
$url = "http://www.izlesene.com/video/arabic-shkira-belly-dance/200012";
$a = explode("/", $url);
$number = array_pop($a);
And maybe like this:
$url = "http://www.izlesene.com/video/arabic-shkira-belly-dance/200012";
$number = array_pop( explode("/", $url) );
Or you can do it faster without arrays and regex:
$url = "http://www.izlesene.com/video/arabic-shkira-belly-dance/200012";
$url = substr($url, strrpos($url, "/") + 1);
strrpos searches the position of the last occurrence of / in a string and substr returns the portion of a string specified by this position.
Try:
$number = basename($url);
Hint: Regular expressions are not always the best solution (even if quite powerful but also complicated). See basenameDocs.
If you really need a regex, start at the end:
$url = "http://www.izlesene.com/video/arabic-shkira-belly-dance/200012";
$number = preg_replace('~.*/([^/]+)$~', '$1', $url);
^