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Strip off specific parameter from URL's querystring
(22 answers)
Closed 8 years ago.
I have to remove the last element in a string. I used rtrim in php but it is not working.
This is the string:
/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC
I need to remove "&make_order=ASC"
Can anyone help me?
$s = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo substr($s, 0, strrpos($s, '&'));
Edit:
$url = $base_url.trim( $_SERVER['REQUEST_URI'], "&year_order=".$arr['year_order']."" );
// ^
// |_ replace , with .
trim should work:
$string = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
$string = trim($string, "&make_order=ASC");
There's no guarantee that make_order will be at the end of the query string - or exist at all. To remove the field properly, you'd have to use something like this:
$url = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
// break down the URL into a path and query string
$parsed = parse_url($url);
// turn the query string into an array that we can manipulate
$qs = array();
parse_str($parsed['query'], $qs);
// remove the unwanted field
unset($qs['make_order']);
// rebuild the URL
$rebuilt = $parsed['path'];
if(!empty($qs)) {
$rebuilt .= '?' . http_build_query($qs);
}
echo $rebuilt;
$actual_link = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
echo str_replace("&make_order=ASC","",$actual_link);
$string = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
$args = array_pop(explode($string, "&"));
$string = implode("&", $args);
There are a bunch of ways. The easiest might be:
$i=strrpos($text,'&');
$newstring=substr($text,0,$i);
$str = "/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC";
echo $str . "<br>";
echo trim($str,"&make_order=ASC");
if &make_order=ASC is always going to be at the end, you can use strstr() to do this
$str = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo strstr($str,'&make_order=ASC',true);
Remove desired key from url.
Use:
$s = '/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100&make_order=ASC';
echo remove_key_from_url($url, 'make_order');
Output :
/search/listing.html?vehicle_type=&year=&make_name=&model_name=&loc_type=3&zipcode=641004&distance=100
Code:
function remove_key_from_url($url, $key) {
if (strpos($url, '?') === false) return $url;
list($left, $right) = explode('?', $url, 2);
parse_str($right, $get);
if (isset($get[$key])) unset($get[$key]);
return $left . '?' . http_build_query($get);
}
Related
I've been working with this code
<?php
class PerchTemplateFilter_sol_en_cat_path extends PerchTemplateFilter {
public function filterAfterProcessing($value, $valueIsMarkup = false) {
// ORIGINAL STRING: solutions-en/rail-technologies/track-components/name-of-product
$mystring = $value;
$replace = ['solutions-en', '%2F'];
$str = '';
$oldstr = str_replace($replace, $str, $mystring);
$str_to_insert = 'XXX';
$findme = '/';
$pos = strpos($mystring, $findme); // I NEED THIS TO INSERT $str_to_insert AFTER THE SECOND FORWARD SLASH FOUND IN THE ORIGINAL STRING?
$value = substr_replace($oldstr, $str_to_insert, $pos, 0);
return $value;
// $value: /rail-technologies/track-components/XXX/name-of-product
// Insert string at specified position
// https://stackoverflow.com/questions/8251426/insert-string-at-specified-position
}
}
PerchSystem::register_template_filter('sol_en_cat_path', 'PerchTemplateFilter_sol_en_cat_path');
?>
My string is: solutions-en/rail-technologies/track-components/name-of-product
I want to end up with: /rail-technologies/XXX/track-components/name-of-product
XXX is only a placeholder value
I guess I need to do something with $pos to set where I want XXX to be added to the string.
I need to insert after the second forward slash, as the string may contain different text
The code above outputs this string: /rail-technoXXXlogies/track-components/ewosr-switch-lock
I can't seem to figure out how to insert XXX after the second forward slash.
Hope someone can provide some help.
How about explode to array, then implode the first two items.
Join with xxx and implode the rest?
function AddInTheMiddle($start, $where, $what){
$arr = explode("/", $what);
$str = implode("/", array_splice($arr,$start,$where)) . '/xxx/' . implode("/", $arr);;
return $str;
}
$str = 'solutions-en/rail-technologies/track-components/name-of-product';
$str = AddInTheMiddle(1, 2, $str);
https://3v4l.org/m98io
Thank you Andreas, your post gave me the nudge I needed. I did this in the end.
// ORIGINAL $value: solutions-en/rail-technologies/track-components/name-of-product
$str = explode("/", $value);
$value = $str[1] . '/' . 'solutions' . '/' . $str[2] . '/';
return $value;
// Removed: solutions-en
// Added: solutions
// $value: rail-technologies/solutions/track-components/name-of-product
I was able to add the name-of-product to the end of the new string elsewhere in my template.
I have a string $current_url that can contain 2 different values:
http://url.com/index.php&lang=en
or
http://url.com/index.php&lang=jp
in both cases I need to strip the query part so I get: http://url.com/index.php
How can I do this in php?
Thank you.
Simplest Solution
$url = 'http://url.com/index.php&lang=en';
$array = explode('&', $url);
echo $new_url =$array[0];
To only remove the lang query do this
$url = 'http://url.com/index.php&lang=en&id=1';
$array = explode('&lang=en', $url);
echo $new_url = $array[0] .''.$array[1];
//output http://url.com/index.php&id=1
So this way it only removes the lang query and keep other queries
If the value of your lang parameter is always of length 2, which should be the case for languages, you could use:
if(strpos($current_url, '&lang=') !== false){
$current_url = str_replace(substr($current_url, strpos($current_url, '&lang='), 8), '', $current_url);
}
If the substring "&lang=" is present in $current_url, it removes a substring of length 8, starting at the "&lang=" position. So it basically removes "&lang=" plus the 2 following chars.
You can Use strtok to remove the query string from url.
<?php
echo $url=strtok('http://url.com/index.php&lang=jp','&');
?>
DEMO
Answer based on comment.
You can use preg_replace
https://www.codexworld.com/how-to/remove-specific-parameter-from-url-query-string-php/
<?php
$url = 'http://url.com/index.php?page=site&lang=jp';
function remove_query_string($url_name, $key) {
$url = preg_replace('/(?:&|(\?))' . $key . '=[^&]*(?(1)&|)?/i', "$1", $url_name);
$url = rtrim($url, '?');
$url = rtrim($url, '&');
return $url;
}
echo remove_query_string($url, 'lang');
?>
DEMO
It might seem easy to do but I have trouble extracting this string. I have a string that has # tags in it and I'm trying to pull the tags maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa
And here is what I want to extract 33.536759,-7.613825,17z :
$var = preg_match_all("/#(\w*)/",$path,$query);
Any way I can do this? Much appreciated.
Change your regex to this one: /#([\w\d\.\,-]*)/.
This will return the string beginning with #.
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
$string = explode('/',$string);
//$coordinates = substr($string[3], 1);
//print_r($coordinates);
foreach ($string as $substring) {
if (substr( $substring, 0, 1 ) === "#") {
$coordinates = $substring;
}
}
echo $coordinates;
This is working for me:
$path = "maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa";
$var = preg_match_all("/#([^\/]+)/",$path,$query);
print $query[1][0];
A regex would do.
/#(-*\d+\.\d+),(-*\d\.\d+,\d+z*)/
If there is only one # and the string ends with / you can use the following code:
//String
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
//Save string after the first #
$coordinates = strstr($string, '#');
//Remove #
$coordinates = str_replace('#', '', $coordinates);
//Separate string on every /
$coordinates = explode('/', $coordinates );
//Save first part
$coordinates = $coordinates[0];
//Do what you want
echo $coordinates;
do like this
$re = '/#((.*?),-(.*?),)/mi';
$str = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
preg_match_all($re, $str, $matches);
echo $matches[2][0].'<br>';
echo $matches[3][0];
output
33.536759
7.613825
This is probably simple however I am not the best with expressions..
I am trying to get the following string from..
http://www.yoursite.com/offers/838?&SITEID=2172
to this.. using an expression that will remove the ?&SITEID and the dynamic id which will vary
http://www.yoursite.com/offers/838
Can anyone suggest the best/simplest method to do this?
Check this function:
$str = 'http://www.yoursite.com/offers/838?&SITEID=2172';
function remove_query_arg($var, $url = NULL){
if(!$url){
$url = $_SERVER['REQUEST_URI'];
}
$parsed_url = parse_url($url);
$query_vars = explode('&', $parsed_url['query']);
foreach($query_vars as $key => $value){
$query_vars[$key] = explode('=', $query_vars[$key]);
$query_variables[$query_vars[$key][0]] = $query_vars[$key][1];
}
if(is_array($var)){
foreach($var as $value){
unset($query_variables[$value]);
}
}
elseif(is_string($var)){
unset($query_variables[$var]);
}
$query_vars = array();
foreach($query_variables as $key => $value){
$query_vars[] = $key.($value !== NULL || !empty($value) ? '='.$value : '');
}
$query_str = '';
$query_str = implode('&',$query_vars);
return (isset($parsed_url['scheme']) && !empty($parsed_url['scheme']) ? $parsed_url['scheme'].'://' : '').$parsed_url['host'].(isset($parsed_url['path']) && !empty($parsed_url['path']) ? $parsed_url['path'] : '').(!empty($query_str) ? '?'.$query_str : '');
}
echo remove_query_arg('SITEID', $str);
This is a URL, so parse it as one, with parse_url().
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
$parts = parse_url($url);
$url = $parts["scheme"] . "://" . $parts["host"] . $parts["path"];
Using explode function returns an array
$url=http://www.yoursite.com/offers/838?&SITEID=2172
$result=explode('?',$url)
print_r($result);
output
array
{
[0]=>http://www.yoursite.com/offers/838
[1]=>?&SITEID=2172
}
A valid URL only has one ? so you can just use explode to break it into 2 parts
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
list($path, $query) = explode("?", $url, "2");
var_dump($path);
Output
string 'http://www.yoursite.com/offers/838' (length=34)
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
$str = substr($url, strpos($url, 0, "?&SITEID"));
// $str results in "http://www.yoursite.com/offers/838"
If you want to keep the part before the ? you can search
^(.+?)(\?&SITEID|$)
and replace with
$1
You search non greedily from the beginning of the line ^ to the first ?&SITEID and leave out the rest. If no ?&SITEID is found you get the entire line by arriving at the end of the string with $
| is the OR operator that tells the regex "Stop at the first ?&SITEID or at the end of the string"
EDIT:
After the comment where you explain your need to keep the rest of the querystring I suggest you a different approach: find
&?SITEID=[^&\s]+
being
&? an optional & at the beginning of the string
SITEID= the string you are looking for followed by
[^&\s]+ any number of non&, nonspace character
and remove it from the string. However, being this the case, I'd go with a non-regex, url-specific approach like suggested in the other answers.
I am new in PHP and can't figure out how to do this:
$link = 'http://www.domainname.com/folder1/folder2/folder3/folder4';
$domain_and_slash = http://www.domainname.com . '/';
$address_without_site_url = str_replace($domain_and_slash, '', $link);
foreach ($folder_adress) {
// function here for example
echo $folder_adress;
}
I can't figure out how to get the $folder_adress.
In the case above I want the function to echo these four:
folder1
folder1/folder2
folder1/folder2/folder3
folder1/folder2/folder3/folder4
The $link will have different amount of subfolders...
This gets you there. Some things you might explore more: explode, parse_url, trim. Taking a look at the docs of there functions gets you a better understanding how to handle url's and how the code below works.
$link = 'http://www.domainname.com/folder1/folder2/folder3/folder4';
$parts = parse_url($link);
$pathParts = explode('/', trim($parts['path'], '/'));
$buffer = "";
foreach ($pathParts as $part) {
$buffer .= $part.'/';
echo $buffer . PHP_EOL;
}
/*
Output:
folder1/
folder1/folder2/
folder1/folder2/folder3/
folder1/folder2/folder3/folder4/
*/
You should have a look on explode() function
array explode ( string $delimiter , string $string [, int $limit ] )
Returns an array of strings, each of
which is a substring of string formed
by splitting it on boundaries formed
by the string delimiter.
Use / as the delimiter.
This is what you are looking for:
$link = 'http://www.domainname.com/folder1/folder2/folder3/folder4';
$domain_and_slash = 'http://www.domainname.com' . '/';
$address_without_site_url = str_replace($domain_and_slash, '', $link);
// this splits the string into an array
$address_without_site_url_array = explode('/', $address_without_site_url);
$folder_adress = '';
// now we loop through the array we have and append each item to the string $folder_adress
foreach ($address_without_site_url_array as $item) {
// function here for example
$folder_adress .= $item.'/';
echo $folder_adress;
}
Hope that helps.
Try this:
$parts = explode("/", "folder1/folder2/folder3/folder4");
$base = "";
for($i=0;$i<count($parts);$i++){
$base .= ($base ? "/" : "") . $parts[$i];
echo $base . "<br/>";
}
I would use preg_match() for regular expression method:
$m = preg_match('%http://([.+?])/([.+?])/([.+?])/([.+?])/([.+?])/?%',$link)
// $m[1]: domain.ext
// $m[2]: folder1
// $m[3]: folder2
// $m[4]: folder3
// $m[5]: folder4
1) List approach: use split to get an array of folders, then concatenate them in a loop.
2) String approach: use strpos with an offset parameter which changes from 0 to 1 + last position where a slash was found, then use substr to extract the part of the folder string.
EDIT:
<?php
$folders = 'folder1/folder2/folder3/folder4';
function fn($folder) {
echo $folder, "\n";
}
echo "\narray approach\n";
$folder_array = split('/', $folders);
foreach ($folder_array as $folder) {
if ($result != '')
$result .= '/';
$result .= $folder;
fn($result);
}
echo "\nstring approach\n";
$pos = 0;
while ($pos = strpos($folders, '/', $pos)) {
fn(substr($folders, 0, $pos++));
}
fn($folders);
?>
If I had time, I could do a cleaner job. But this works and gets across come ideas: http://codepad.org/ITJVCccT
Use parse_url, trim, explode, array_pop, and implode