Get what page the visitor visit in PHP - php

Question

I was trying to get what page the visitor visit:
Here is my code:
$url = $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
$urlcomplete = $url;
$url = explode(".com/",$url);
$urlcount = count($url);
$newurl = '';
for ($start = 1; $start < $urlcount; $start++) {
if ($newurl != '') {
$newurl .= '.com/';
}
$newurl .= $url[$start];
}
$url = explode('/',$newurl);
$urlcount = explode('?',end($url));
$url[count($url) - 1] = $urlcount[0];
$urlcount = count($url);
By using the code above, all the subpage will be store in the $url.
https://stackoverflow.com/questions/ask
$url[0] = 'questions'
$url[1] = 'ask'
Just want to ask, is this good way, or there are others better way?

Answer 1

First prepending SERVER_NAME to the REQUEST_URI, and then trying to split it off, is pointless. This should be a simpler solution:
# first, split off the query string, if any:
list( $path ) = explode( '?', $_SERVER['REQUEST_URI'], 2 );
# then just split the URL path into its components:
$url = explode( '/', ltrim( $path, '/' ) );
The ltrim removes any leading slashes from the path, so that $url[0] won't be empty.
Note that there might still be an empty element at the end of the $url array, if the path ends in a slash. You could get rid of it by using trim instead of ltrim, but you may not want to, since the trailing slash is significant for things like resolving relative URLs.