Using PHP to find part of a URL - php

Question

Take this domain:
http://www.?.co.uk/elderly-care-advocacy/mental-capacity-act-advance-medical-directive.html
How could i use PHP to find the everything between the first and second slash regardless of whether it changes or no?
Ie. elderly-care-advocacy
Any helo would be greatly appreciated.

Answer 1

//strip the "http://" part. Note: Doesn't work for HTTPS!
$url = substr("http://www.example.com/elderly-care-advocacy/mental-capacity-act-advance-medical-directive.html", 7);
// split the URL in parts
$parts = explode("/", $url);
// The second part (offset 1) is the part we look for
if (count($parts) > 1) {
$segment = $parts[1];
} else {
throw new Exception("Full URLs please!");
}

Answer 2

$url = "http://www.example.co.uk/elderly-care-advocacy/mental-capacity-act-advance-medical-directive.html";
$parts = parse_url($url);
$host = $parts['host'];
$path = $parts['path'];
$items = preg_split('/\//',$path,null,PREG_SPLIT_NO_EMPTY);
$firstPart = $items[0];

Answer 3

off the top of my head:
$url = http://www.example.co.uk/elderly-care-advocacy/mental-capacity-act-advance-medical-directive.html
$urlParts = parse_url($url); // An array
$target_string = $urlParts[1] // 'elderly-care-advocacy'
Cheers

Answer 4

explode('/', $a);

Answer 5

All you should do, is parse url first, and then explode string and get first part. With some sanity checks that would lok like following:
$url = 'http://www.?.co.uk/elderly-care-advocacy/mental-capacity-act-advance-medical-directive.html';
$url_parts = parse_url($url);
if (isset($url_parts['path'])) {
$path_components = explode('/', $ul_parts['path']);
if (count($path_components) > 1) {
// All is OK. Path's first component is in $path_components[0]
} else {
// Throw an error, since there is no directory specified in path
// Or you could assume, that $path_components[0] is the actual path
}
} else {
// Throw an error, since there is no path component was found
}

Answer 6

I was surprised too, but this works.
$url='http://www.?.co.uk/elderly-care-advocacy/...'
$result=explode('/',$url)[3];

Answer 7

I think a Regular Expression should be fine for that.
Try using e.g.: /[^/]+/ that should give you /elderly-care-advocacy/ as the second index of an array in your example.
(The first string is /www.?.com/)

Answer 8

Parse_URL is your best option. It breaks the URL string down into components, which you can selectively query.
This function could be used:
function extract_domain($url){
if ($url_parts = parse_url($url), $prefix = 'www.', $suffix = '.co.uk') {
$host = $url_parts['host'];
$host = str_replace($prefix,'',$host);
$host = str_replace($suffix,'',$host);
return $host;
}
return false;
}
$host_component = extract_domain($_SERVER['REQUEST_URI']);