Is there a simple straight forward way to find the remaining time between a start date - ex: 2013-01-10 12:34:55 and 5 minutes later?
What I mean is I have the start date and want to check that 5 or 60 minutes later gives a time difference of 0. Kind of a time out to be checked on server side.
You have 2 dates, correct ?
$date1 = strtotime('2013-01-10 12:34:33'); // converto to time
$date2 = strtotime('2013-01-10 12:45:33'); // or else it won't work
$diff = date('u', $date1) - date('u', $date2); // the difference in seconds between the two
// if you want $date2 to be now, just use date('u')
if ($diff > 3600) { // an hour later
echo 'The difference between $date1 and $date2 is more than an hour';
}
If you want to do something like "session time out" for the user. Use Javascript setintervel() and do ajax() call to logout user from the application.
Well, seems like I was going the harder way... found that it would be easier and more reliable to get it from an sql check than in php.
I've implemented this with success. Leave it here just in case it might be useful.
$query = "SELECT * FROM db_table
WHERE DATE_ADD(my_start_date, INTERVAL 5 MINUTE) > NOW()";
Where 5 is the interval that can be set in seconds (SECOND), minutes (MINUTE), hours (HOUR), days (DAY) etc.
Related
I want to display content from the database with dates up to 2hours ahead of time.
Example:
2018-11-09 20:00:00.000000
2018-11-08 19:00:00.000000
2018-11-06 19:00:00.000000
2018-11-06 18:00:00.000000
Lets say the time and date is
Nov 6th at 6pm. I want the bottom two entries to be displayed and the two future dates to not show until the current time is within 2hours of that time.
My code is as follows:
$cT = strtotime($row3['MissionTime']) - strtotime("now");
if($cT <= strtotime('-2 hours')) {
echo $row3['MissionTime']."<br>";
}
I've tried several different ways but I can't seem to get this to work right. Help and tips?
The reason your code doesn't work is that strtotime returns a number of seconds since the unix epoch. When you subtract two results of strtotime you will get a number of seconds difference which is as you expect. However you cannot compare that value to strtotime('-2 hours') as the output of that will be the timestamp for 2 hours before now (which right now is 1541539906), so the test will always pass. You should just compare it to 7200 instead (I'm pretty sure based on your question description that +7200 is more appropriate than -7200). so change
if($cT <= strtotime('-2 hours')) {
to
if($cT <= 7200) {
Note that it is almost certainly better to do this in your query. Try adding a condition on your time column as something like
WHERE MissionTime <= NOW() + INTERVAL 2 HOUR
And then you won't need to check in the PHP at all.
strtotime() returns a timestamp in seconds. Subtracting two timestamps gives you a difference between those two timestamps, in seconds.
So if strtotime($row3['MissionTime']) is a timestamp that's 1.5 hours in the future, and you subtract strtotime("now") from it, you end up with a difference of 5400 seconds (60 seconds * 60 minutes * 1.5 hours).
strtotime('-2 hours') gives you the timestamp for 2 hours ago, which is currently somewhere around 1.5 billion. This is not very useful for your situation.
Here are two ways to modify your code:
$cT = strtotime($row3['MissionTime']) - strtotime("now");
if($cT <= 7200) {
echo $row3['MissionTime']."<br>";
}
If the difference between $row['MissionTime'] and now is less than 7200 seconds (60 seconds * 60 minutes * two hours), $row3['MissionTime'] is either in the past or it's within the next two hours.
Alternatively:
if(strtotime($row3['MissionTime']) <= strtotime('+2 hours')) {
echo $row3['MissionTime']."<br>";
}
Basically the same, but perhaps more readable if you're not planning to use $cT for anything else. This simply checks if $row3['MissionTime'] is earlier than whatever time it will be in +2 hours.
I'm working on a chat / activity system. My site currently logs all activity being page, button submission and if a message is sent its added to a table called activity. With a time stamp and date in format: 12:44:06 (time) 2016-10-19 (date)
I need to check if there is no activity for a user after 5 minutes.
Therefore I can determine if the user is online or not online. Each activity row has a u_id (user id)
I would prefer it was PHP based. I just need a basic php function. So I have $time $date and to check if 5 minuets has passed from that set $time $date value
If you're using OOP php, you could do that this way:
$last = DateTime::createFromFormat('Y-m-d H:i:s', $yourDate.' '.$yourTime);
$now = new Datetime('now');
$minutes = abs( $last->getTimestamp() - $now->getTimestamp() ) / 60;
Then check if it's bigger than 5 and do stuff.
You can also install Carbon, which is an extension of the DateTime class and it makes your life easier when handling dates in php.
Check here: http://carbon.nesbot.com/
Then you could do it this way:
$then = Carbon::createFromFormat('Y-m-d H:i:s', $yourDate.' '.$yourTime);
if($then->addMinutes(5)->isPast()) {
// stuff
}
Way cleaner.
You can do it using mysql like below:
SELECT TIMESTAMPDIFF(MINUTE, datatime_col, now())
With above query you will get the difference in minutes, which you can compare as it is greater than 5 minutes or not.
I run this script which works sweet estimating how much time before something weather related happens. But a midnight it goes crazy and for the whole midnight hour, it returns crazy negative times like -1100 minutes and stuff, then when it gets to 0100 hrs it's back to normal and reports, like 20 mintues etc.
Script:
$timenow = date("H:i:s");
$eventtime= strtotime("$gettimefromtextfile"); //time the weather event will happen in the near future
$TimeEnd = strtotime($timenow);
$Difference = ($eventtime - $TimeEnd);
if ($Difference >= 0) {
$minutes = floor(($Difference / 60));
// print how many minutes until an event happens, discard it if event is in the past
I know the date function had issues with midnight up to PHP 5.3. But I am running PHP 5.3 so shouldn't be an issue. I don't need the date, it is only time I need, weather related stuff is reported only hours difference at most.
Any suggestions on an alternative function or coding that will stop this spasm at midnight?
What about using DateTime::diff? Don't reinvent the wheel!
<?php
date_default_timezone_set('Europe/Lisbon');
$next = new DateTime('18:00:01');
$now = new DateTime();
$diff = $next->diff($now);
echo $diff->format('%h hours, %i minutes');
?>
Reference: http://php.net/manual/en/datetime.diff.php
I'm a novice to php's date() and strtotime, and have been attempting to find out the solution to this for the great portion of the day with no real solution (I've come close, but to no avail).
What I have is a typical database row with a 'submitted' column, which is entered via a submitted=NOW() (in datetime format). I'm attempting to get the current datetime and find the difference between both values in "x Hours and x minutes". To make matters a little more interesting my web server is an hour behind me in terms of timezones. I've tried the "date_default_timezone_set('EST');" and it does help doing the straight date() function but obviously doesn't help me with my already inserted datetimes.
$lastEntryDate = date('l, F dS Y', strtotime($entryDate));
$lastEntryTime = date('g:ia', strtotime($entryDate.'+1 hour'));
$currDate = date('l, F dS Y');
$currTime = date('g:ia');
So, tried doing $lastEntryTime - $currTime, but that obviously gets messed up depending on the time of day (as it's in 24 hour format, I believe).
I've googled around and found a couple of posts on forums indicating using the 3600 (seconds in an hour), and I'm still trying to wrap my head around this.
Is there something basic I'm missing? Or is this quite complex as I think it is?
$now = time();
$entrytime = strtotime($entryDate) + (60 * 60) //60 seconds times 60 minutes = 1 hour
$difference = $now - $entrytime;
$hours = floor($difference / (60 * 60));
$minutes = $difference - ($hours * 60 * 60);
a solution that may be helpful to you is instead of using the MySQL now function why not make your submitted field of the INT type and then store a unix timestamp in it using the php time() function, then before inserting that into the database just add 1 hour in seconds to the timestamp. Then when you retrieve the data from your table you should be able to work with the timestamp and the php date and time function to create whatever timestamp you want. Here is a link on the php time() function which may help:
http://php.net/manual/en/function.time.php
i have to sent an email when a user register email contain a link that is become invalid after six hours
what i m doing when email is sent i update the db with field emailSentDate of type "datetime"
now i got the curent date and time and has made to the same formate as it is in db now i want to find that both these dates and time have differenc of 6 hours or not so that i can make link invalid but i donot know how to do this
my code is look like this i m using hardcoded value for db just for example
$current_date_time=date("Y-m-d h:i:s");
$current=explode(" ",$current_date_time);
$current_date=$current[0];
$current_time=$current[1];
$db_date_time="2010-07-30 13:11:50";
$db=explode(" ",$db_date_time);
$db_date=$db[0];
$db_time=$db[1];
i do not know how to proceed plz help
<?php
//$now = new DateTime(); // current date/time
$now = new DateTime("2010-07-28 01:11:50");
$ref = new DateTime("2010-07-30 05:56:40");
$diff = $now->diff($ref);
printf('%d days, %d hours, %d minutes', $diff->d, $diff->h, $diff->i);
prints 2 days, 4 hours, 44 minutes
see http://docs.php.net/datetime.diff
edit: But you could also shift the problem more to the database side, e.g. by storing the expiration date/time in the table and then do a query like
... WHERE key='7gedufgweufg' AND expires<Now()
Many rdbms have reasonable/good support for date/time arithmetic.
What you can do is convert both of your dates to Unix epoch times, that is, the equivalent number of seconds since midnight on the 31st of December 1969. From that you can easily deduce the amount of time elapsed between the two dates. To do this you can either use mktime() or strtotime()
All the best.
$hoursDiff = ( time() - strtotime("2010-07-30 13:11:50") )/(60 * 60);
I'd rather work with a timestamp: Save the value which is returned by "time()" as "savedTime" to your database (that's a timestamp in seconds). Subtract that number from "time()" when you check for your six hours.
if ((time() - savedTime) > 6 * 3600)
// more than 6h ago
or
"SELECT FROM table WHERE savedTime < " . (time() - 6 * 3600)
This might be the solution to your problem -> How to calculate the difference between two dates using PHP?