I want to display content from the database with dates up to 2hours ahead of time.
Example:
2018-11-09 20:00:00.000000
2018-11-08 19:00:00.000000
2018-11-06 19:00:00.000000
2018-11-06 18:00:00.000000
Lets say the time and date is
Nov 6th at 6pm. I want the bottom two entries to be displayed and the two future dates to not show until the current time is within 2hours of that time.
My code is as follows:
$cT = strtotime($row3['MissionTime']) - strtotime("now");
if($cT <= strtotime('-2 hours')) {
echo $row3['MissionTime']."<br>";
}
I've tried several different ways but I can't seem to get this to work right. Help and tips?
The reason your code doesn't work is that strtotime returns a number of seconds since the unix epoch. When you subtract two results of strtotime you will get a number of seconds difference which is as you expect. However you cannot compare that value to strtotime('-2 hours') as the output of that will be the timestamp for 2 hours before now (which right now is 1541539906), so the test will always pass. You should just compare it to 7200 instead (I'm pretty sure based on your question description that +7200 is more appropriate than -7200). so change
if($cT <= strtotime('-2 hours')) {
to
if($cT <= 7200) {
Note that it is almost certainly better to do this in your query. Try adding a condition on your time column as something like
WHERE MissionTime <= NOW() + INTERVAL 2 HOUR
And then you won't need to check in the PHP at all.
strtotime() returns a timestamp in seconds. Subtracting two timestamps gives you a difference between those two timestamps, in seconds.
So if strtotime($row3['MissionTime']) is a timestamp that's 1.5 hours in the future, and you subtract strtotime("now") from it, you end up with a difference of 5400 seconds (60 seconds * 60 minutes * 1.5 hours).
strtotime('-2 hours') gives you the timestamp for 2 hours ago, which is currently somewhere around 1.5 billion. This is not very useful for your situation.
Here are two ways to modify your code:
$cT = strtotime($row3['MissionTime']) - strtotime("now");
if($cT <= 7200) {
echo $row3['MissionTime']."<br>";
}
If the difference between $row['MissionTime'] and now is less than 7200 seconds (60 seconds * 60 minutes * two hours), $row3['MissionTime'] is either in the past or it's within the next two hours.
Alternatively:
if(strtotime($row3['MissionTime']) <= strtotime('+2 hours')) {
echo $row3['MissionTime']."<br>";
}
Basically the same, but perhaps more readable if you're not planning to use $cT for anything else. This simply checks if $row3['MissionTime'] is earlier than whatever time it will be in +2 hours.
Related
I have a file called "file.txt".
I get its last change time with this:
$lastTime = filemtime("file.txt");
Then I make
$lastDate = date("Y-m-d",strtotime( $lastTime ));
$todaysDate = date("Y-m-d",strtotime('now'));
Then I substract lastDate from todaysDate and find the difference.
Is there a quicker way to do this?
I don't want to check whether the difference of seconds is >= 86400 or not.
For example the difference between these two dates must be "1".
2013-03-31 10:00
2013-03-30 19:00
If i check for the difference of seconds I will have 54K seconds, which is smaller than 86400 seconds.
Get the difference in seconds, then convert to days and round the result.
$diff = time()-filemtime("file.txt");
$days = round($diff/86400);
You could also use floor or ceil in place of round depending on exactly how you want to handle partial days.
Is there a simple straight forward way to find the remaining time between a start date - ex: 2013-01-10 12:34:55 and 5 minutes later?
What I mean is I have the start date and want to check that 5 or 60 minutes later gives a time difference of 0. Kind of a time out to be checked on server side.
You have 2 dates, correct ?
$date1 = strtotime('2013-01-10 12:34:33'); // converto to time
$date2 = strtotime('2013-01-10 12:45:33'); // or else it won't work
$diff = date('u', $date1) - date('u', $date2); // the difference in seconds between the two
// if you want $date2 to be now, just use date('u')
if ($diff > 3600) { // an hour later
echo 'The difference between $date1 and $date2 is more than an hour';
}
If you want to do something like "session time out" for the user. Use Javascript setintervel() and do ajax() call to logout user from the application.
Well, seems like I was going the harder way... found that it would be easier and more reliable to get it from an sql check than in php.
I've implemented this with success. Leave it here just in case it might be useful.
$query = "SELECT * FROM db_table
WHERE DATE_ADD(my_start_date, INTERVAL 5 MINUTE) > NOW()";
Where 5 is the interval that can be set in seconds (SECOND), minutes (MINUTE), hours (HOUR), days (DAY) etc.
I'm looking for an easy way to see if more than two hours has passed between two dates. I can either do this with a MySQL DATETIME value, or if needed, I can convert that to a UNIX timestamp. I just need an easy way to to compare those two dates and see if more than 2 hours has passed.
try to look into DATEDIFF function in MySQL.
A UNIX timestamp is just the number of seconds that have elapsed since 12:00AM UTC, January 1, 1970.
Two hours in seconds is 60 * 60 * 2 = 7200. So,
if($secondTimestamp - $firstTimestamp >= 7200)
{
echo '2 hours have elapsed.';
}
Since you tagged with php, you could use PHP's DateTime::diff (DateTime::diff) to get a diff between two datetime objects. I guess it depends on where in your application you are doing the comparison.
In PHP
$time = strtotime($date2) - strtotime($date1); //this will give difference in seconds between two dates
if(($time/3600) >= 2) { // 2 hours has left }
i have to sent an email when a user register email contain a link that is become invalid after six hours
what i m doing when email is sent i update the db with field emailSentDate of type "datetime"
now i got the curent date and time and has made to the same formate as it is in db now i want to find that both these dates and time have differenc of 6 hours or not so that i can make link invalid but i donot know how to do this
my code is look like this i m using hardcoded value for db just for example
$current_date_time=date("Y-m-d h:i:s");
$current=explode(" ",$current_date_time);
$current_date=$current[0];
$current_time=$current[1];
$db_date_time="2010-07-30 13:11:50";
$db=explode(" ",$db_date_time);
$db_date=$db[0];
$db_time=$db[1];
i do not know how to proceed plz help
<?php
//$now = new DateTime(); // current date/time
$now = new DateTime("2010-07-28 01:11:50");
$ref = new DateTime("2010-07-30 05:56:40");
$diff = $now->diff($ref);
printf('%d days, %d hours, %d minutes', $diff->d, $diff->h, $diff->i);
prints 2 days, 4 hours, 44 minutes
see http://docs.php.net/datetime.diff
edit: But you could also shift the problem more to the database side, e.g. by storing the expiration date/time in the table and then do a query like
... WHERE key='7gedufgweufg' AND expires<Now()
Many rdbms have reasonable/good support for date/time arithmetic.
What you can do is convert both of your dates to Unix epoch times, that is, the equivalent number of seconds since midnight on the 31st of December 1969. From that you can easily deduce the amount of time elapsed between the two dates. To do this you can either use mktime() or strtotime()
All the best.
$hoursDiff = ( time() - strtotime("2010-07-30 13:11:50") )/(60 * 60);
I'd rather work with a timestamp: Save the value which is returned by "time()" as "savedTime" to your database (that's a timestamp in seconds). Subtract that number from "time()" when you check for your six hours.
if ((time() - savedTime) > 6 * 3600)
// more than 6h ago
or
"SELECT FROM table WHERE savedTime < " . (time() - 6 * 3600)
This might be the solution to your problem -> How to calculate the difference between two dates using PHP?
How would I construct a statement like if current time ($time) is more than 30 seconds past time ($djs['currenttime'])? Would it be something like
if ($time => $djs['currenttime'])? I can't figure it out with the 30 seconds..:).
Thanks :).
The 30 seconds you are struggling with it's simply a +30 added on the conditional incrementing the value of $djs['currenttime'].
You can use the time() function to get the actual time. I'm assuming that djs['currenttime'] is a value extracted from the database. Therefore the comparison would be the following:
if(time() > $djs['currenttime'] + 30){
//actions here;
}
time() returns the number of seconds since Jan 1st 1970 00:00:00 GMT so for this to work, the format of the $djs['currenttime'] variable should also be a unix timestamp. If not, you will need to convert one of them to the appropriate format first.
if ($time > ($djs['currenttime'] + 30))
Assumes that both values are actual timestamps and not formatted strings