PHP preg_match get the last item - php

Question

I have a PHP string with a list of items, and I would like to get the last one.
The reality is much more complex, but it boils down to:
$Line = 'First|Second|Third';
if ( preg_match( '#^.*|(?P<last>.+)$#', $Line, $Matches ) > 0 )
{
print_r($Matches);
}
I expect Matches['last'] to contain 'Third', but it does not work. Rather, I get Matches[0] to contain the full string and nothing else.
What am I doing wrong?
Please no workarounds, I can do it myself but I would really like to have this working with preg_match

Answer 1

You have this:
'#^.*|(?P<last>.+)$#'
^
... but I guess you are looking for a literal |:
'#^.*\|(?P<last>.+)$#'
^^

Answer 2

Just use :
$Line = 'First|Second|Third' ;
$lastword = explode('|', $line);
echo $lastword['2'];

Answer 3

If your syntax is always kinda the same, and by that I mean that uses the | as separator, you could do the following, if you like it.
$Line = 'First|Second|Third' ;
$line_array = explode('|', $Line);
$line_count = count($line_array) - 1;
echo $line_array[$line_count];
or
$Line = 'First|Second|Third' ;
$line_array = explode('|', $Line);
end($line_array);
echo $line_array[key($line_array)];

Answer 4

Example of PHP preg_match to get the last match:
<?php
$mystring = "stuff://sometext/2010-01-01/foobar/2016-12-12.csv";
preg_match_all('/\d{4}\-\d{2}\-\d{2}/', $mystring, $matches);
print_r($matches);
print("\nlast match: \n");
print_r($matches[0][count($matches[0])-1]);
print("\n");
?>
Prints the whole object returned and the last match:
Array
(
[0] => Array
(
[0] => 2010-01-01
[1] => 2016-12-12
)
)
last match:
2016-12-12