preg_match_all Output with Multiple Possibilities - php

Question

I am searching a line using preg_match_all, but it is not known exactly what this line will look like. For example, it could look like this:
XXX012-013-015-######
Or it could look like this:
XXX012-013-015-XXX001-002-######
Where the 'X's are any letter and the '#'s are any number.
This is the relevant portion of the preg_match_all code that works exactly as expected if the line was always setup like the first example:
if (preg_match_all('([A-Z]{3})((?:[0-9]{3}[->]{1}){1,32})([0-9]{2})([0-9]{2})([0-9]{2})...rest of code...#', $wwalist, $matches)) {
$wwaInfo['locationabbrev'][$wwanum] = $matches[2][$keys[$wwanum]];
}
The $matches[2] will display "012-013-015" as expected. Since the first part, xxx012-013-015, can repeat, I need for the preg_match_all $matches[2] to display the following if it is run on the second example:
012-013-015-001-002
This was my attempt, but it does not work:
if (preg_match_all('#([A-Z]{3})((?:[0-9]{3}[->]{1}){1,32})((?:[A-Z]{3}){0,1})(?:((?:[0-9]{3}[->]{1}){1,3}){0,3})([0-9]{2})([0-9]{2})([0-9]{2})...rest of code...#', $wwalist, $matches)) {
Hopefully this makes sense. Any help would be much appreciated! Thanks!

Answer 1

You aren't going to be able to match and join matches in the same step.
Will this work for you:
Code: (Pattern Demo) (PHP Demo)
$strings=[
'ABC012-013-015-XYZ001-002-345435',
'ABC012-013-015-345453',
'XYZ013-014-015-016-EFG017-123456'
];
foreach($strings as $s){
if(preg_match('/[A-Z]{3}\d{3}/',$s)){ // check if string qualifies
echo 'Match found. Prepared string: ';
$s=preg_replace('/([A-Z]{3}|-\d{6})/','',$s); // remove unwanted substrings
echo "$s\n";
}
}
Output:
Match found. Prepared string: 012-013-015-001-002
Match found. Prepared string: 012-013-015
Match found. Prepared string: 013-014-015-016-017

Answer 2

You could use a replace call and then output a new string with the matches, so for example:
ABC012-013-015-XYZ001-002-345435
ABC012-013-015-345453
XYZ013-014-015-016-EFG017-123456
$rep = preg_replace( '/(?mi-Us)([^0-9-\n]{3,})|-[0-9]{4,}/', '', $str) ;
echo ( $rep );
Should result in:
012-013-015-001-002
012-013-015
013-014-015-016-017
To output to an array:
$mat = preg_match_all( '/([0-9-]+)\n/', $rep, $res) ;
print_r( $res[1] ) ;
foreach( $res[1] as $result ) {
echo $result . "\n" ;
}
For the code you've shown you could probably do:
$rep = preg_replace( '/(?mi-Us)([^0-9-\n]{3,})|-[0-9]{4,}/', '', $wwalist ) ;
if (preg_match_all('/([0-9-]+)\n/', $rep, $matches)) {
$wwaInfo['locationabbrev'][$wwanum] = $matches[1][$keys[$wwanum]];
print_r( $wwaInfo['locationabbrev'][$wwanum] ); // comment out when done testing
}
Which should return the array:
Array
(
[0] => 012-013-015-001-002
[1] => 012-013-015
[2] => 013-014-015-016-017
)