Remove useless zero digits from decimals in PHP - php

Question

I'm trying to find a fast way to remove zero decimals from number values like this:
echo cleanNumber('125.00');
// 125
echo cleanNumber('966.70');
// 966.7
echo cleanNumber(844.011);
// 844.011
Does exists some optimized way to do that?

Answer 1

$num + 0 does the trick.
echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7
Internally, this is equivalent to casting to float with (float)$num or floatval($num) but I find it simpler.

Answer 2

you could just use the floatval function
echo floatval('125.00');
// 125
echo floatval('966.70');
// 966.7
echo floatval('844.011');
// 844.011

Answer 3

This is what I use:
function TrimTrailingZeroes($nbr) {
return strpos($nbr,'.')!==false ? rtrim(rtrim($nbr,'0'),'.') : $nbr;
}
N.B. This assumes . is the decimal separator. It has the advantage that it will work on arbitrarily large (or small) numbers since there is no float cast. It also won't turn numbers into scientific notation (e.g. 1.0E-17).

Answer 4

If you want to remove the zero digits just before to display on the page or template.
You can use the sprintf() function
sprintf('%g','125.00');
// 125
‌‌sprintf('%g','966.70');
// 966.7
‌‌‌‌sprintf('%g',844.011);
// 844.011

Answer 5

Simply adding + to your string variable will cause typecast to (float) and removes zeros:
var_dump(+'125.00'); // double(125)
var_dump(+'966.70'); // double(966.7)
var_dump(+'844.011'); // double(844.011)
var_dump(+'844.011asdf');// double(844.011)

Answer 6

For everyone coming to this site having the same problem with commata instead, change:
$num = number_format($value, 1, ',', '');
to:
$num = str_replace(',0', '', number_format($value, 1, ',', '')); // e.g. 100,0 becomes 100
If there are two zeros to be removed, then change to:
$num = str_replace(',00', '', number_format($value, 2, ',', '')); // e.g. 100,00 becomes 100
More here: PHP number: decimal point visible only if needed

Answer 7

You should cast your numbers as floats, which will do this for you.
$string = "42.422005000000000000000000000000";
echo (float)$string;
Output of this will be what you are looking for.
42.422005

Answer 8

$x = '100.10';
$x = preg_replace("/\.?0*$/",'',$x);
echo $x;
There is nothing that can't be fixed with a simple regex ;)
http://xkcd.com/208/

Answer 9

Typecast to a float.
$int = 4.324000;
$int = (float) $int;

Answer 10

Be careful with adding +0.
echo number_format(1500.00, 2,".",",")+0;
//1
Result of this is 1.
echo floatval('1,000.00');
// 1
echo floatval('1000.00');
//1000

Answer 11

Sometimes, especially in case of monetary amounts, you want to remove the zeros only if they are 2, you don't want to print € 2.1 instead of € 2.10.
An implementation could be:
function formatAmount(string|float|int $value, int $decimals = 2): string
{
if (floatval(intval($value)) === floatval($value)) {
// The number is an integer. Remove all the decimals
return (string)intval($value);
}
return number_format($value, $decimals);
}
Examples of expected outputs:
0.1000 => 0.10
20.000 => 20
1.25 => 1.25

Answer 12

Example 1
$value =81,500.00;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
81,500
Example 2
$value=110,763.14;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
110,763.14

Answer 13

Due to this question is old. First, I'm sorry about this.
The question is about number xxx.xx but in case that it is x,xxx.xxxxx or difference decimal separator such as xxxx,xxxx this can be harder to find and remove zero digits from decimal value.
/**
* Remove zero digits (include zero trails - 123.450, 123.000) from decimal value.
*
* #param string|int|float $number The number can be any format, any where use in the world such as 123, 1,234.56, 1234.56789, 12.345,67, -98,765.43
* #param string The decimal separator. You have to set this parameter to exactly what it is. For example: in Europe it is mostly use "," instead of ".".
* #return string Return removed zero digits from decimal value. Only return as string!
*/
function removeZeroDigitsFromDecimal($number, $decimal_sep = '.')
{
$explode_num = explode($decimal_sep, $number);
if (is_countable($explode_num) && count($explode_num) > 1) {
// if exploded number is more than 1 (Example: explode with . for nnnn.nnn is 2)
// replace `is_countable()` with `is_array()` if you are using PHP older than 7.3.
$explode_num[count($explode_num)-1] = preg_replace('/(0+)$/', '', $explode_num[count($explode_num)-1]);
if ($explode_num[count($explode_num)-1] === '') {
// if the decimal value is now empty.
// unset it to prevent nnn. without any number.
unset($explode_num[count($explode_num)-1]);
}
$number = implode($decimal_sep, $explode_num);
}
unset($explode_num);
return (string) $number;
}
And here is the code for test.
$tests = [
1234 => 1234,
-1234 => -1234,
'12,345.67890' => '12,345.6789',
'-12,345,678.901234' => '-12,345,678.901234',
'12345.000000' => '12345',
'-12345.000000' => '-12345',
'12,345.000000' => '12,345',
'-12,345.000000000' => '-12,345',
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number);
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
echo '<hr>' . PHP_EOL;
$tests = [
1234 => 1234,
-1234 => -1234,
'12.345,67890' => '12.345,6789',
'-12.345.678,901234' => '-12.345.678,901234',
'12345,000000' => '12345',
'-12345,000000' => '-12345',
'-12.345,000000000' => '-12.345',
'-12.345,000000,000' => '-12.345,000000',// this is correct assertion. Weird ,000000,000 but only last 000 will be removed.
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number, ',');
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
All tests should be pass and no errors.
Why '-12.345,000000,000' will be '-12.345,000000' not '-12.345'?
Because this function is for remove zero digits (include zero trails) from decimal value. It is not validation for the correct number format. That should be another function.
Why always return as string?
Because it is better to use in calculation with bcxxx functions, or use with big number.

Answer 14

$str = 15.00;
$str2 = 14.70;
echo rtrim(rtrim(strval($str), "0"), "."); //15
echo rtrim(rtrim(strval($str2), "0"), "."); //14.7

Answer 15

I found this solution is the best:
public function priceFormat(float $price): string
{
//https://stackoverflow.com/a/14531760/5884988
$price = $price + 0;
$split = explode('.', $price);
return number_format($price, isset($split[1]) ? strlen($split[1]) : 2, ',', '.');
}

Answer 16

The following is much simpler
if(floor($num) == $num) {
echo number_format($num);
} else {
echo $num;
}

Answer 17

You can try the following:
rtrim(number_format($coin->current_price,6),'0.')

Answer 18

Complicated way but works:
$num = '125.0100';
$index = $num[strlen($num)-1];
$i = strlen($num)-1;
while($index == '0') {
if ($num[$i] == '0') {
$num[$i] = '';
$i--;
}
$index = $num[$i];
}
//remove dot if no numbers exist after dot
$explode = explode('.', $num);
if (isset($explode[1]) && intval($explode[1]) <= 0) {
$num = intval($explode[0]);
}
echo $num; //125.01
the solutions above are the optimal way but in case you want to have your own you could use this. What this algorithm does it starts at the end of string and checks if its 0, if it is it sets to empty string and then goes to the next character from back untill the last character is > 0

Answer 19

$value = preg_replace('~\.0+$~','',$value);

Answer 20

You can use:
print (floatval)(number_format( $Value), 2 ) );

Answer 21

Thats my small solution...
Can included to a class and set vars
private $dsepparator = '.'; // decimals
private $tsepparator= ','; // thousand
That can be set by constructor and change to users lang.
class foo
{
private $dsepparator;
private $tsepparator;
function __construct(){
$langDatas = ['en' => ['dsepparator' => '.', 'tsepparator' => ','], 'de' => ['dsepparator' => ',', 'tsepparator' => '.']];
$usersLang = 'de'; // set iso code of lang from user
$this->dsepparator = $langDatas[$usersLang]['dsepparator'];
$this->tsepparator = $langDatas[$usersLang]['tsepparator'];
}
public function numberOmat($amount, $decimals = 2, $hideByZero = false)
{
return ( $hideByZero === true AND ($amount-floor($amount)) <= 0 ) ? number_format($amount, 0, $this->dsepparator, $this->tsepparator) : number_format($amount, $decimals, $this->dsepparator, $this->tsepparator);
}
/*
* $bar = new foo();
* $bar->numberOmat('5.1234', 2, true); // returns: 5,12
* $bar->numberOmat('5', 2); // returns: 5,00
* $bar->numberOmat('5.00', 2, true); // returns: 5
*/
}

Answer 22

This is my solution.
I want to keep ability to add thousands separator
$precision = 5;
$number = round($number, $precision);
$decimals = strlen(substr(strrchr($number, '.'), 1));
return number_format($number, $precision, '.', ',');

Answer 23

This is a simple one line function using rtrim, save separator and decimal point :
function myFormat($num,$dec)
{
return rtrim(rtrim(number_format($num,$dec),'0'),'.');
}

Answer 24

Simple and accurate!
function cleanNumber($num){
$explode = explode('.', $num);
$count = strlen(rtrim($explode[1],'0'));
return bcmul("$num",'1', $count);
}

Answer 25

I use this simple code:
define('DECIMAL_SEPARATOR', ','); //To prove that it works with different separators than "."
$input = "50,00";
$number = rtrim($input, '0'); // 50,00 --> 50,
$number = rtrim($number, DECIMAL_SEPARATOR); // 50, --> 50
echo $number;
Seems a bit too easy to be the really correct solution, but it works just fine for me. You should do some tests with the inputs you'll be getting before using this.

Answer 26

Assuming the amount is a string with 2 decimal places, then you can use:
protected function removeZerosDecimals(string $money): string
{
$formatter = new NumberFormatter('en_US', NumberFormatter::CURRENCY);
$uselessDecimals = sprintf(
'%s00',
$formatter->getSymbol(NumberFormatter::DECIMAL_SEPARATOR_SYMBOL)
);
if (!str_ends_with($money, $uselessDecimals)) {
return $money;
}
$len = mb_strlen($money);
return mb_substr($money, 0, $len - mb_strlen($uselessDecimals));
}
That will work as expected for ?any? currency, like $500.00 and R$ 500,00.

Answer 27

function removeZerosAfterDecimals($number) {
$number = trim($number);
if($number <= 0 || empty($number)) {
return $number;
}
$ary = explode('.', $number);
if(count($ary) <= 1) {
return $number;
}
$reverseAry = array_reverse($ary);
$endSearch = false;
$newNumber = [];
for($i=0; $i<count($reverseAry); $i++) {
if($reverseAry[$i] != 0 && $endSearch === false) {
$newNumber[] = $reverseAry[$i];
$endSearch = true;
} else if ($endSearch === true) {
$newNumber[] = $reverseAry[$i];
}
}
return implode('.',array_reverse($newNumber));
}
//output: 10.0.1.0 => 10.0.1
//output: 10.0.1 => 10.0.1
//output: 10.1.2 => 10.1.2
//output: 10.0.0 => 10
This function will only remove the trailing zero decimals

Answer 28

This Code will remove zero after point and will return only two decimal digits.
$number=1200.0000;
str_replace('.00', '',number_format($number, 2, '.', ''));
Output will be: 1200

Answer 29

Ultimate Solution: The only safe way is to use regex:
echo preg_replace("/\.?0+$/", "", 3.0); // 3
echo preg_replace("/\d+\.?\d*(\.?0+)/", "", 3.0); // 3
it will work for any case