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I'm trying to find a fast way to remove zero decimals from number values like this:
echo cleanNumber('125.00');
// 125
echo cleanNumber('966.70');
// 966.7
echo cleanNumber(844.011);
// 844.011
Does exists some optimized way to do that?
$num + 0 does the trick.
echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7
Internally, this is equivalent to casting to float with (float)$num or floatval($num) but I find it simpler.
you could just use the floatval function
echo floatval('125.00');
// 125
echo floatval('966.70');
// 966.7
echo floatval('844.011');
// 844.011
This is what I use:
function TrimTrailingZeroes($nbr) {
return strpos($nbr,'.')!==false ? rtrim(rtrim($nbr,'0'),'.') : $nbr;
}
N.B. This assumes . is the decimal separator. It has the advantage that it will work on arbitrarily large (or small) numbers since there is no float cast. It also won't turn numbers into scientific notation (e.g. 1.0E-17).
If you want to remove the zero digits just before to display on the page or template.
You can use the sprintf() function
sprintf('%g','125.00');
// 125
sprintf('%g','966.70');
// 966.7
sprintf('%g',844.011);
// 844.011
Simply adding + to your string variable will cause typecast to (float) and removes zeros:
var_dump(+'125.00'); // double(125)
var_dump(+'966.70'); // double(966.7)
var_dump(+'844.011'); // double(844.011)
var_dump(+'844.011asdf');// double(844.011)
For everyone coming to this site having the same problem with commata instead, change:
$num = number_format($value, 1, ',', '');
to:
$num = str_replace(',0', '', number_format($value, 1, ',', '')); // e.g. 100,0 becomes 100
If there are two zeros to be removed, then change to:
$num = str_replace(',00', '', number_format($value, 2, ',', '')); // e.g. 100,00 becomes 100
More here: PHP number: decimal point visible only if needed
You should cast your numbers as floats, which will do this for you.
$string = "42.422005000000000000000000000000";
echo (float)$string;
Output of this will be what you are looking for.
42.422005
$x = '100.10';
$x = preg_replace("/\.?0*$/",'',$x);
echo $x;
There is nothing that can't be fixed with a simple regex ;)
http://xkcd.com/208/
Typecast to a float.
$int = 4.324000;
$int = (float) $int;
Be careful with adding +0.
echo number_format(1500.00, 2,".",",")+0;
//1
Result of this is 1.
echo floatval('1,000.00');
// 1
echo floatval('1000.00');
//1000
Sometimes, especially in case of monetary amounts, you want to remove the zeros only if they are 2, you don't want to print € 2.1 instead of € 2.10.
An implementation could be:
function formatAmount(string|float|int $value, int $decimals = 2): string
{
if (floatval(intval($value)) === floatval($value)) {
// The number is an integer. Remove all the decimals
return (string)intval($value);
}
return number_format($value, $decimals);
}
Examples of expected outputs:
0.1000 => 0.10
20.000 => 20
1.25 => 1.25
Example 1
$value =81,500.00;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
81,500
Example 2
$value=110,763.14;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
110,763.14
Due to this question is old. First, I'm sorry about this.
The question is about number xxx.xx but in case that it is x,xxx.xxxxx or difference decimal separator such as xxxx,xxxx this can be harder to find and remove zero digits from decimal value.
/**
* Remove zero digits (include zero trails - 123.450, 123.000) from decimal value.
*
* #param string|int|float $number The number can be any format, any where use in the world such as 123, 1,234.56, 1234.56789, 12.345,67, -98,765.43
* #param string The decimal separator. You have to set this parameter to exactly what it is. For example: in Europe it is mostly use "," instead of ".".
* #return string Return removed zero digits from decimal value. Only return as string!
*/
function removeZeroDigitsFromDecimal($number, $decimal_sep = '.')
{
$explode_num = explode($decimal_sep, $number);
if (is_countable($explode_num) && count($explode_num) > 1) {
// if exploded number is more than 1 (Example: explode with . for nnnn.nnn is 2)
// replace `is_countable()` with `is_array()` if you are using PHP older than 7.3.
$explode_num[count($explode_num)-1] = preg_replace('/(0+)$/', '', $explode_num[count($explode_num)-1]);
if ($explode_num[count($explode_num)-1] === '') {
// if the decimal value is now empty.
// unset it to prevent nnn. without any number.
unset($explode_num[count($explode_num)-1]);
}
$number = implode($decimal_sep, $explode_num);
}
unset($explode_num);
return (string) $number;
}
And here is the code for test.
$tests = [
1234 => 1234,
-1234 => -1234,
'12,345.67890' => '12,345.6789',
'-12,345,678.901234' => '-12,345,678.901234',
'12345.000000' => '12345',
'-12345.000000' => '-12345',
'12,345.000000' => '12,345',
'-12,345.000000000' => '-12,345',
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number);
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
echo '<hr>' . PHP_EOL;
$tests = [
1234 => 1234,
-1234 => -1234,
'12.345,67890' => '12.345,6789',
'-12.345.678,901234' => '-12.345.678,901234',
'12345,000000' => '12345',
'-12345,000000' => '-12345',
'-12.345,000000000' => '-12.345',
'-12.345,000000,000' => '-12.345,000000',// this is correct assertion. Weird ,000000,000 but only last 000 will be removed.
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number, ',');
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
All tests should be pass and no errors.
Why '-12.345,000000,000' will be '-12.345,000000' not '-12.345'?
Because this function is for remove zero digits (include zero trails) from decimal value. It is not validation for the correct number format. That should be another function.
Why always return as string?
Because it is better to use in calculation with bcxxx functions, or use with big number.
$str = 15.00;
$str2 = 14.70;
echo rtrim(rtrim(strval($str), "0"), "."); //15
echo rtrim(rtrim(strval($str2), "0"), "."); //14.7
I found this solution is the best:
public function priceFormat(float $price): string
{
//https://stackoverflow.com/a/14531760/5884988
$price = $price + 0;
$split = explode('.', $price);
return number_format($price, isset($split[1]) ? strlen($split[1]) : 2, ',', '.');
}
The following is much simpler
if(floor($num) == $num) {
echo number_format($num);
} else {
echo $num;
}
You can try the following:
rtrim(number_format($coin->current_price,6),'0.')
Complicated way but works:
$num = '125.0100';
$index = $num[strlen($num)-1];
$i = strlen($num)-1;
while($index == '0') {
if ($num[$i] == '0') {
$num[$i] = '';
$i--;
}
$index = $num[$i];
}
//remove dot if no numbers exist after dot
$explode = explode('.', $num);
if (isset($explode[1]) && intval($explode[1]) <= 0) {
$num = intval($explode[0]);
}
echo $num; //125.01
the solutions above are the optimal way but in case you want to have your own you could use this. What this algorithm does it starts at the end of string and checks if its 0, if it is it sets to empty string and then goes to the next character from back untill the last character is > 0
$value = preg_replace('~\.0+$~','',$value);
You can use:
print (floatval)(number_format( $Value), 2 ) );
Thats my small solution...
Can included to a class and set vars
private $dsepparator = '.'; // decimals
private $tsepparator= ','; // thousand
That can be set by constructor and change to users lang.
class foo
{
private $dsepparator;
private $tsepparator;
function __construct(){
$langDatas = ['en' => ['dsepparator' => '.', 'tsepparator' => ','], 'de' => ['dsepparator' => ',', 'tsepparator' => '.']];
$usersLang = 'de'; // set iso code of lang from user
$this->dsepparator = $langDatas[$usersLang]['dsepparator'];
$this->tsepparator = $langDatas[$usersLang]['tsepparator'];
}
public function numberOmat($amount, $decimals = 2, $hideByZero = false)
{
return ( $hideByZero === true AND ($amount-floor($amount)) <= 0 ) ? number_format($amount, 0, $this->dsepparator, $this->tsepparator) : number_format($amount, $decimals, $this->dsepparator, $this->tsepparator);
}
/*
* $bar = new foo();
* $bar->numberOmat('5.1234', 2, true); // returns: 5,12
* $bar->numberOmat('5', 2); // returns: 5,00
* $bar->numberOmat('5.00', 2, true); // returns: 5
*/
}
This is my solution.
I want to keep ability to add thousands separator
$precision = 5;
$number = round($number, $precision);
$decimals = strlen(substr(strrchr($number, '.'), 1));
return number_format($number, $precision, '.', ',');
This is a simple one line function using rtrim, save separator and decimal point :
function myFormat($num,$dec)
{
return rtrim(rtrim(number_format($num,$dec),'0'),'.');
}
Simple and accurate!
function cleanNumber($num){
$explode = explode('.', $num);
$count = strlen(rtrim($explode[1],'0'));
return bcmul("$num",'1', $count);
}
I use this simple code:
define('DECIMAL_SEPARATOR', ','); //To prove that it works with different separators than "."
$input = "50,00";
$number = rtrim($input, '0'); // 50,00 --> 50,
$number = rtrim($number, DECIMAL_SEPARATOR); // 50, --> 50
echo $number;
Seems a bit too easy to be the really correct solution, but it works just fine for me. You should do some tests with the inputs you'll be getting before using this.
Assuming the amount is a string with 2 decimal places, then you can use:
protected function removeZerosDecimals(string $money): string
{
$formatter = new NumberFormatter('en_US', NumberFormatter::CURRENCY);
$uselessDecimals = sprintf(
'%s00',
$formatter->getSymbol(NumberFormatter::DECIMAL_SEPARATOR_SYMBOL)
);
if (!str_ends_with($money, $uselessDecimals)) {
return $money;
}
$len = mb_strlen($money);
return mb_substr($money, 0, $len - mb_strlen($uselessDecimals));
}
That will work as expected for ?any? currency, like $500.00 and R$ 500,00.
function removeZerosAfterDecimals($number) {
$number = trim($number);
if($number <= 0 || empty($number)) {
return $number;
}
$ary = explode('.', $number);
if(count($ary) <= 1) {
return $number;
}
$reverseAry = array_reverse($ary);
$endSearch = false;
$newNumber = [];
for($i=0; $i<count($reverseAry); $i++) {
if($reverseAry[$i] != 0 && $endSearch === false) {
$newNumber[] = $reverseAry[$i];
$endSearch = true;
} else if ($endSearch === true) {
$newNumber[] = $reverseAry[$i];
}
}
return implode('.',array_reverse($newNumber));
}
//output: 10.0.1.0 => 10.0.1
//output: 10.0.1 => 10.0.1
//output: 10.1.2 => 10.1.2
//output: 10.0.0 => 10
This function will only remove the trailing zero decimals
This Code will remove zero after point and will return only two decimal digits.
$number=1200.0000;
str_replace('.00', '',number_format($number, 2, '.', ''));
Output will be: 1200
Ultimate Solution: The only safe way is to use regex:
echo preg_replace("/\.?0+$/", "", 3.0); // 3
echo preg_replace("/\d+\.?\d*(\.?0+)/", "", 3.0); // 3
it will work for any case
After a lot of research I am actually using the following function to format numbers to the locale setted by the user:
function number_format_i18n($number, $decimals=0) {
$locale = localeconv();
return number_format($number,$decimals, $locale['decimal_point'], $locale['thousands_sep']);
}
I'll use this to format numbers from DB.
But if I have a form where a user can enter a number, I need a function to format it back so I can save into the DB. Here I found this solution:
function number_format_en($number) {
// $_SESSION['lang']['locale'] has the locale like de_DE, ar_AE, tr_TR, ...
$fmt = numfmt_create($_SESSION['lang']['locale'], NumberFormatter::DECIMAL);
return numfmt_parse($fmt, $number);
}
This works with the most locales I tested but not with everyone! As an example: if I use arabic (ar_AE):
$randomNumber = 3171003633.95;
$number2locale = number_format_i18n($randomNumber, 2);
// works as expected: 3,171,003,633.95
// now format it back:
$locale2number = number_format_en($number2locale);
// here I get this: 3.171
How can I format a locale entered number in a secure way "back" to en-format? Or is there a way to detect any kind of numberformat and format it to en-format so I can save it in the DB?
So, don't know really if this is a good solution or not - but it seems to be working fine:
function number_format_en($number) {
// first remove everything execpt -,.
$cleanNumber = preg_replace('/[^\\d-,.]+/', '', $number);
$last_dot = strrpos($cleanNumber, '.');
$last_comma = strrpos($cleanNumber, ',');
if($last_dot !== false || $last_comma !== false) {
if($last_dot > $last_comma) { // decimal seperator = dot
$decimal_point = '.';
if(substr_count($cleanNumber, '.') > 1) {
// could be totaly wrong 1,234.567.890
// or there are no decimals 1.234.567.890
// removing all dots and commas and returning the value
return preg_replace('/[^\\d-]+/', '', $cleanNumber);
}
} else { // decimal seperator = comma
$decimal_point = ',';
if(substr_count($cleanNumber, ',') > 1) {
// could be totaly wrong 1.234,567,890
// or there are no decimals 1,234,567,890
// removing all dots and commas and returning the value
return preg_replace('/[^\\d-]+/', '', $cleanNumber);
}
}
} else { // no decimals
$decimal_point = false;
$decimals = 0;
}
if($decimal_point !== false) {
// if decimals are delivered, get the count of them
$length = strlen($cleanNumber);
$position = strpos($cleanNumber, $decimal_point);
$decimals = $length - $position - 1;
if($decimal_point == '.') {
// remove all commas if seperator = .
$cleanNumber = str_replace(',', '', $cleanNumber);
} elseif($decimal_point == ',') {
// remove all dots if seperator = ,
$cleanNumber = str_replace('.', '', $cleanNumber);
// now switch comma with dot
$cleanNumber = str_replace(',', '.', $cleanNumber);
}
}
return $cleanNumber;
}
I'll check the last dot or comma and depending on that I format the number, function returns the same count of decimals as the original number. there is a "known" bug: if someone enters a full number like 1.000.000 or 1,000,000 it returns 1000000.
As an example:
number_format_en('1.234.567,89') // 1234567.89
number_format_en('-1,234,567.89') // -1234567.89
number_format_en('1.234.567.89') // 123456789 (only dots)
number_format_en('1,234,567,89') // 123456789 (only commas)
Would be nice if someone can post a comment if this is a good way or not or an answer with a better solution :)
I'm trying to find a fast way to remove zero decimals from number values like this:
echo cleanNumber('125.00');
// 125
echo cleanNumber('966.70');
// 966.7
echo cleanNumber(844.011);
// 844.011
Does exists some optimized way to do that?
$num + 0 does the trick.
echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7
Internally, this is equivalent to casting to float with (float)$num or floatval($num) but I find it simpler.
you could just use the floatval function
echo floatval('125.00');
// 125
echo floatval('966.70');
// 966.7
echo floatval('844.011');
// 844.011
This is what I use:
function TrimTrailingZeroes($nbr) {
return strpos($nbr,'.')!==false ? rtrim(rtrim($nbr,'0'),'.') : $nbr;
}
N.B. This assumes . is the decimal separator. It has the advantage that it will work on arbitrarily large (or small) numbers since there is no float cast. It also won't turn numbers into scientific notation (e.g. 1.0E-17).
If you want to remove the zero digits just before to display on the page or template.
You can use the sprintf() function
sprintf('%g','125.00');
// 125
sprintf('%g','966.70');
// 966.7
sprintf('%g',844.011);
// 844.011
Simply adding + to your string variable will cause typecast to (float) and removes zeros:
var_dump(+'125.00'); // double(125)
var_dump(+'966.70'); // double(966.7)
var_dump(+'844.011'); // double(844.011)
var_dump(+'844.011asdf');// double(844.011)
For everyone coming to this site having the same problem with commata instead, change:
$num = number_format($value, 1, ',', '');
to:
$num = str_replace(',0', '', number_format($value, 1, ',', '')); // e.g. 100,0 becomes 100
If there are two zeros to be removed, then change to:
$num = str_replace(',00', '', number_format($value, 2, ',', '')); // e.g. 100,00 becomes 100
More here: PHP number: decimal point visible only if needed
You should cast your numbers as floats, which will do this for you.
$string = "42.422005000000000000000000000000";
echo (float)$string;
Output of this will be what you are looking for.
42.422005
$x = '100.10';
$x = preg_replace("/\.?0*$/",'',$x);
echo $x;
There is nothing that can't be fixed with a simple regex ;)
http://xkcd.com/208/
Typecast to a float.
$int = 4.324000;
$int = (float) $int;
Be careful with adding +0.
echo number_format(1500.00, 2,".",",")+0;
//1
Result of this is 1.
echo floatval('1,000.00');
// 1
echo floatval('1000.00');
//1000
Sometimes, especially in case of monetary amounts, you want to remove the zeros only if they are 2, you don't want to print € 2.1 instead of € 2.10.
An implementation could be:
function formatAmount(string|float|int $value, int $decimals = 2): string
{
if (floatval(intval($value)) === floatval($value)) {
// The number is an integer. Remove all the decimals
return (string)intval($value);
}
return number_format($value, $decimals);
}
Examples of expected outputs:
0.1000 => 0.10
20.000 => 20
1.25 => 1.25
Example 1
$value =81,500.00;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
81,500
Example 2
$value=110,763.14;
{{rtrim(rtrim(number_format($value,2),0),'.')}}
output
110,763.14
Due to this question is old. First, I'm sorry about this.
The question is about number xxx.xx but in case that it is x,xxx.xxxxx or difference decimal separator such as xxxx,xxxx this can be harder to find and remove zero digits from decimal value.
/**
* Remove zero digits (include zero trails - 123.450, 123.000) from decimal value.
*
* #param string|int|float $number The number can be any format, any where use in the world such as 123, 1,234.56, 1234.56789, 12.345,67, -98,765.43
* #param string The decimal separator. You have to set this parameter to exactly what it is. For example: in Europe it is mostly use "," instead of ".".
* #return string Return removed zero digits from decimal value. Only return as string!
*/
function removeZeroDigitsFromDecimal($number, $decimal_sep = '.')
{
$explode_num = explode($decimal_sep, $number);
if (is_countable($explode_num) && count($explode_num) > 1) {
// if exploded number is more than 1 (Example: explode with . for nnnn.nnn is 2)
// replace `is_countable()` with `is_array()` if you are using PHP older than 7.3.
$explode_num[count($explode_num)-1] = preg_replace('/(0+)$/', '', $explode_num[count($explode_num)-1]);
if ($explode_num[count($explode_num)-1] === '') {
// if the decimal value is now empty.
// unset it to prevent nnn. without any number.
unset($explode_num[count($explode_num)-1]);
}
$number = implode($decimal_sep, $explode_num);
}
unset($explode_num);
return (string) $number;
}
And here is the code for test.
$tests = [
1234 => 1234,
-1234 => -1234,
'12,345.67890' => '12,345.6789',
'-12,345,678.901234' => '-12,345,678.901234',
'12345.000000' => '12345',
'-12345.000000' => '-12345',
'12,345.000000' => '12,345',
'-12,345.000000000' => '-12,345',
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number);
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
echo '<hr>' . PHP_EOL;
$tests = [
1234 => 1234,
-1234 => -1234,
'12.345,67890' => '12.345,6789',
'-12.345.678,901234' => '-12.345.678,901234',
'12345,000000' => '12345',
'-12345,000000' => '-12345',
'-12.345,000000000' => '-12.345',
'-12.345,000000,000' => '-12.345,000000',// this is correct assertion. Weird ,000000,000 but only last 000 will be removed.
];
foreach ($tests as $number => $assert) {
$result = removeZeroDigitsFromDecimal($number, ',');
assert($result === (string) $assert, new \Exception($result . ' (' . gettype($result) . ') is not matched ' . $assert . ' (' . gettype($assert) . ')'));
echo $number . ' => ' . (string) $assert . '<br>';
}
All tests should be pass and no errors.
Why '-12.345,000000,000' will be '-12.345,000000' not '-12.345'?
Because this function is for remove zero digits (include zero trails) from decimal value. It is not validation for the correct number format. That should be another function.
Why always return as string?
Because it is better to use in calculation with bcxxx functions, or use with big number.
$str = 15.00;
$str2 = 14.70;
echo rtrim(rtrim(strval($str), "0"), "."); //15
echo rtrim(rtrim(strval($str2), "0"), "."); //14.7
I found this solution is the best:
public function priceFormat(float $price): string
{
//https://stackoverflow.com/a/14531760/5884988
$price = $price + 0;
$split = explode('.', $price);
return number_format($price, isset($split[1]) ? strlen($split[1]) : 2, ',', '.');
}
The following is much simpler
if(floor($num) == $num) {
echo number_format($num);
} else {
echo $num;
}
You can try the following:
rtrim(number_format($coin->current_price,6),'0.')
Complicated way but works:
$num = '125.0100';
$index = $num[strlen($num)-1];
$i = strlen($num)-1;
while($index == '0') {
if ($num[$i] == '0') {
$num[$i] = '';
$i--;
}
$index = $num[$i];
}
//remove dot if no numbers exist after dot
$explode = explode('.', $num);
if (isset($explode[1]) && intval($explode[1]) <= 0) {
$num = intval($explode[0]);
}
echo $num; //125.01
the solutions above are the optimal way but in case you want to have your own you could use this. What this algorithm does it starts at the end of string and checks if its 0, if it is it sets to empty string and then goes to the next character from back untill the last character is > 0
$value = preg_replace('~\.0+$~','',$value);
You can use:
print (floatval)(number_format( $Value), 2 ) );
Thats my small solution...
Can included to a class and set vars
private $dsepparator = '.'; // decimals
private $tsepparator= ','; // thousand
That can be set by constructor and change to users lang.
class foo
{
private $dsepparator;
private $tsepparator;
function __construct(){
$langDatas = ['en' => ['dsepparator' => '.', 'tsepparator' => ','], 'de' => ['dsepparator' => ',', 'tsepparator' => '.']];
$usersLang = 'de'; // set iso code of lang from user
$this->dsepparator = $langDatas[$usersLang]['dsepparator'];
$this->tsepparator = $langDatas[$usersLang]['tsepparator'];
}
public function numberOmat($amount, $decimals = 2, $hideByZero = false)
{
return ( $hideByZero === true AND ($amount-floor($amount)) <= 0 ) ? number_format($amount, 0, $this->dsepparator, $this->tsepparator) : number_format($amount, $decimals, $this->dsepparator, $this->tsepparator);
}
/*
* $bar = new foo();
* $bar->numberOmat('5.1234', 2, true); // returns: 5,12
* $bar->numberOmat('5', 2); // returns: 5,00
* $bar->numberOmat('5.00', 2, true); // returns: 5
*/
}
This is my solution.
I want to keep ability to add thousands separator
$precision = 5;
$number = round($number, $precision);
$decimals = strlen(substr(strrchr($number, '.'), 1));
return number_format($number, $precision, '.', ',');
This is a simple one line function using rtrim, save separator and decimal point :
function myFormat($num,$dec)
{
return rtrim(rtrim(number_format($num,$dec),'0'),'.');
}
Simple and accurate!
function cleanNumber($num){
$explode = explode('.', $num);
$count = strlen(rtrim($explode[1],'0'));
return bcmul("$num",'1', $count);
}
I use this simple code:
define('DECIMAL_SEPARATOR', ','); //To prove that it works with different separators than "."
$input = "50,00";
$number = rtrim($input, '0'); // 50,00 --> 50,
$number = rtrim($number, DECIMAL_SEPARATOR); // 50, --> 50
echo $number;
Seems a bit too easy to be the really correct solution, but it works just fine for me. You should do some tests with the inputs you'll be getting before using this.
Assuming the amount is a string with 2 decimal places, then you can use:
protected function removeZerosDecimals(string $money): string
{
$formatter = new NumberFormatter('en_US', NumberFormatter::CURRENCY);
$uselessDecimals = sprintf(
'%s00',
$formatter->getSymbol(NumberFormatter::DECIMAL_SEPARATOR_SYMBOL)
);
if (!str_ends_with($money, $uselessDecimals)) {
return $money;
}
$len = mb_strlen($money);
return mb_substr($money, 0, $len - mb_strlen($uselessDecimals));
}
That will work as expected for ?any? currency, like $500.00 and R$ 500,00.
function removeZerosAfterDecimals($number) {
$number = trim($number);
if($number <= 0 || empty($number)) {
return $number;
}
$ary = explode('.', $number);
if(count($ary) <= 1) {
return $number;
}
$reverseAry = array_reverse($ary);
$endSearch = false;
$newNumber = [];
for($i=0; $i<count($reverseAry); $i++) {
if($reverseAry[$i] != 0 && $endSearch === false) {
$newNumber[] = $reverseAry[$i];
$endSearch = true;
} else if ($endSearch === true) {
$newNumber[] = $reverseAry[$i];
}
}
return implode('.',array_reverse($newNumber));
}
//output: 10.0.1.0 => 10.0.1
//output: 10.0.1 => 10.0.1
//output: 10.1.2 => 10.1.2
//output: 10.0.0 => 10
This function will only remove the trailing zero decimals
This Code will remove zero after point and will return only two decimal digits.
$number=1200.0000;
str_replace('.00', '',number_format($number, 2, '.', ''));
Output will be: 1200
Ultimate Solution: The only safe way is to use regex:
echo preg_replace("/\.?0+$/", "", 3.0); // 3
echo preg_replace("/\d+\.?\d*(\.?0+)/", "", 3.0); // 3
it will work for any case
I like to convert string with a price to a float value. The price comes from different languages and countries and can look like this:
1,00 €
€ 1.00
1'000,00 EUR
1 000.00$
1,000.00$
1.000,00 EURO
or whatever you can think of...
Not sure I got the full range of possibilities with my examples. I am also not sure if it is possible to make in international convert blindly, maybe I have to use a language code? So for the start Euro and Dollar would be enough.
floatval() is kind of stupid so I need something more here. I think I should first remove all chars beside numbers, , and .. Then fix the , / . and use floatval finally.
Has someone done this before and can help me a little?
I would prefer a solution without regexp ;)
Ok, I tried it myself. What do you think of this?
function priceToFloat($s){
// is negative number
$neg = strpos((string)$s, '-') !== false;
// convert "," to "."
$s = str_replace(',', '.', $s);
// remove everything except numbers and dot "."
$s = preg_replace("/[^0-9\.]/", "", $s);
// remove all seperators from first part and keep the end
$s = str_replace('.', '',substr($s, 0, -3)) . substr($s, -3);
// Set negative number
if( $neg ) {
$s = '-' . $s;
}
// return float
return (float) $s;
}
Here some tests: http://codepad.org/YtiHqsgz
Sorry. I couldn't include the other functions because codepad did not like them. But I compared them and there was trouble with strings like "22 000,76" or "22.000"
Update: As Limitless isa pointed out you might have a look at the build in function money-format.
Removing all the non-numeric characters should give you the price in cents. You can then divide that by 100 to get the 'human readable' price. You could do this with something like the filter_var FILTER_SANITIZE_NUMBER_INT. For example:
$cents = filter_var($input, FILTER_SANITIZE_NUMBER_INT);
$price = floatval($cents / 100);
Above is untested, but something like that is probably what you're looking for.
This function will fix your problem:
function priceToSQL($price)
{
$price = preg_replace('/[^0-9\.,]*/i', '', $price);
$price = str_replace(',', '.', $price);
if(substr($price, -3, 1) == '.')
{
$price = explode('.', $price);
$last = array_pop($price);
$price = join($price, '').'.'.$last;
}
else
{
$price = str_replace('.', '', $price);
}
return $price;
}
price to number
number to price examples
<?php
$number="1.050,50";
$result=str_replace(',','.',str_replace('.','',$number));
echo $result. "<br/>";
// 1050.50
setlocale(LC_MONETARY, 'tr_TR');
echo money_format('%!.2n', $result) ;
// 1.050,50
?>
To remove all but numbers, commas and full stops:
<?php
$prices = array( "1,00 €",
"€ 1.00",
"1'000,00 EUR",
"1 000.99$",
"1,000.01$",
"1.000,10 EURO");
$new_prices = array();
foreach ($prices as $price) {
$new_prices[] = preg_replace("/[^0-9,\.]/", "", $price);
}
print_r($new_prices);
Output:
Array ( [0] => 1,00 [1] => 1.00 [2] => 1000,00 [3] => 1000.99 [4] => 1,000.01 [5] => 1.000,10 )
Now lets utilize the parseFloat function from Michiel - php.net (I won't paste it here since it's a pretty big function):
<?php
$prices = array( "1,00 €",
"€ 1.00",
"1'000,00 EUR",
"1 000.99$",
"1,000.01$",
"1.000,10 EURO");
$new_prices = array();
foreach ($prices as $price) {
$new_prices[] = parseFloat(preg_replace("/[^0-9,\.]/", "", $price));
}
print_r($new_prices);
Output will be:
Array ( [0] => 1 [1] => 1 [2] => 1000 [3] => 1000.99 [4] => 1000.01 [5] => 1000.1 )
not perfect, but it work
function priceToFloat($s){
// clear witespaces
$s = trim($s);
$s = str_replace(' ', '', $s);
// is it minus value
$is_minus = false;
if(strpos($s, '(') !== false)
$is_minus = true;
if(strpos($s, '-') !== false)
$is_minus = true;
// check case where string has "," and "."
$dot = strpos($s, '.');
$semi = strpos($s, ',');
if($dot !== false && $semi !== false){
// change fraction sign to #, we change it again later
$s = str_replace('#', '', $s);
if($dot < $semi) $s = str_replace(',','#', $s);
else $s = str_replace('.','#', $s);
// remove another ",", "." and change "#" to "."
$s = str_replace([',','.', '#'], ['','', '.'], $s);
}
$s = str_replace(',', '.', $s);
// clear usless elements
$s = preg_replace("/[^0-9\.]/", "", $s);
// if it minus value put the "-" sign
if($is_minus) $s = -$s;
return (float) $s;
}
working cases
$prices = [
'123.456,789',
'123,456.789',
'123 456,789',
'123 456.789',
'-123,456.789',
'(123,456.789)',
];
foreach($prices as $price)
echo priceToFloat($price).'<br />';
return
123456.789
123456.789
123456.789
123456.789
-123456.789
-123456.789
I am using an api to retrieve data from another server the data returned is something like this:
accountid=10110 type=prem servertime=1263752255 validuntil=1266163393
username= curfiles=11 curspace=188374868 bodkb=5000000 premkbleft=24875313
This is a whole string I need two values out of whole string, I am currently using preg_match to get it, but just to learn more and improve my coding is there any other way or function in which all values are automatically convert to array?
Thank You.
Sooo, my faster-than-preg_split, strpos-based function looks like this:
function unpack_server_data($serverData)
{
$output = array();
$keyStart = 0;
$keepParsing = true;
do
{
$keyEnd = strpos($serverData, '=', $keyStart);
$valueStart = $keyEnd + 1;
$valueEnd = strpos($serverData, ' ', $valueStart);
if($valueEnd === false)
{
$valueEnd = strlen($serverData);
$keepParsing = false;
}
$key = substr($serverData, $keyStart, $keyEnd - $keyStart);
$value = substr($serverData, $valueStart, $valueEnd - $valueStart);
$output[$key] = $value;
$keyStart = $valueEnd + 1;
}
while($keepParsing);
return $output;
}
It looks for an equals character, then looks for a space character, and uses these two to decide where a key name begins, and when a value name begins.
Using explode is the fastest for this, no matter what.
However, to answer you question, you can do this many ways. But just because you can, doesn't mean you should. But if you really wanna make it weird, try this.
UPdated using strpos
$arr = array();
$begin = 0;
$str = trim($str); # remove leading and trailing whitespace
while ($end = strpos($str, ' ', $begin)) {
$split = strpos($str, '=', $begin);
if ($split > $end) break;
$arr[substr($str, $begin, $split-$begin)] = substr($str, $split+1, $end-$split-1);
$begin = $end+1;
}
try out parse_str maybe you need to do str_replace(' ', '&', $string); before