Php multiple mySQL query - php

is it possible to retrieve an array of data from more than one table within one query? For example , I am getting an array from table1, but I want to retrieve data from several other tables too:
<?php
$con = mysql_connect($hostname,$username, $password);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($dbname, $con);
$today = date('Y-m-d H:i:s', time());
$today1DayAgo = date('Y-m-d H:i:s', strtotime("$today -1 day"));
$query = "SELECT * FROM table1 WHERE omtr_date BETWEEN '$today1DayAgo' AND '$today'";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
echo $row["omtr_page_view"]);
}
mysql_close($con);
?>
Thanks

Use Mysql Joins.
Here is an example:
<?php
// Make a MySQL Connection
// Construct our join query
$query = "SELECT family.Position, food.Meal ";
$query .= "FROM family INNER JOIN food ";
$query .= "WHERE family.Position = food.Position";
//Execute query
$result = mysql_query($query) or die(mysql_error());
// Print out the contents of each row into a table
while($row = mysql_fetch_array($result)){
echo $row['Position']. " - ". $row['Meal'];
echo "<br />";
}
?>
More examples of mysql joins are listed here: http://phpweby.com/tutorials/mysql/32

You can use joins to do this:
E.g.
SELECT t1.*, t2.id, t2.someothercolumn FROM table1 t1 LEFT JOIN table2 t2 ON t1.id=t2.t1_id WHERE omtr_date BETWEEN '$today1DayAgo' AND '$today'
(Untested)
Might be worth reading up on them.. http://www.sitepoint.com/understanding-sql-joins-mysql-database/

If your tables have something in common, like 1 column of table1 is the primary key of table2, or any kind of a relation (like same column), you can use JOINS.
Otherwise you can use UNION as well, like
SELECT omtr_date1.a AS a1, omtr_date1.b AS b1 FROM table1 WHERE omtr_date1 BETWEEN '$today1DayAgo' AND '$today'
UNION
SELECT omtr_date2.c AS a1, omtr_date2.d AS b1 FROM table1 WHERE omtr_date2 BETWEEN '$today1DayAgo' AND '$today'
But both the select statements must produce same number of columns with same column names.
That will do you good.

Related

PHP SQL INSERT INTO statement not working directly after table creation [duplicate]

<?php
$query1 = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query2 = "CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query3 = "CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query4) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
All the queries work independently but am really struggling putting all the pieces together in one single result so I can use it with mysql_fetch_array.
I've tried to create views as well as temporary tables but each time it either says table does not exist or return an empty fetch array loop...logic is there but syntax is messed up I think as it's the 1st time I had to deal with multiple queries I need to merge all together. Looking forward to some support. Many thanks.
Thanks to php.net I've come up with a solution : you have to use (mysqli_multi_query($link, $query)) to run multiple concatenated queries.
/* create sql connection*/
$link = mysqli_connect("server", "user", "password", "database");
$query = "SQL STATEMENTS;"; /* first query : Notice the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS"; /* last query : Notice the dot before = at the end ! */
/* Execute queries */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_array($result))
/* print your results */
{
echo $row['column1'];
echo $row['column2'];
}
mysqli_free_result($result);
}
} while (mysqli_next_result($link));
}
EDIT - The solution above works if you really want to do one big query but it's also possible to execute as many queries as you wish and execute them separately.
$query1 = "Create temporary table A select c1 from t1";
$result1 = mysqli_query($link, $query1) or die(mysqli_error());
$query2 = "select c1 from A";
$result2 = mysqli_query($link, $query2) or die(mysqli_error());
while($row = mysqli_fetch_array($result2)) {
echo $row['c1'];
}
It seems you are not executing $query1 - $query3. You have just skipped to $query4 which won't work if the others have not been executed first.
Also
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
should probably be
$query4 = "SELECT *, #rank_change := prev_rank - current_rank as rank_change from final_output";
or else the value of rank_change will just be a boolean, true if #rank_change is equal to (prev_rank - current_rank), false if it is not. But do you need #rank_change at all? Will you use it in a subsequent query? Maybe you can remove it altogether.
Even better, you could just combine all the queries into one like this:
SELECT
curr.player,
curr.rank AS current_rank,
#rank_change := prev.rank - curr.rank AS rank_change
FROM
main_table AS curr
LEFT JOIN main_table AS prev
ON curr.player = prev.player
WHERE
curr.date = X
AND prev.date = date_sub('X', INTERVAL 1 MONTH)
You should concatenate them:
<?php
$query = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query .= " CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query .= " CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query .= " SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>

SQL query working in phpmyadmin but not in php

i have made a query to select only the last date for each user. It works in phpmyadmin but when i want to execute it in a mysqli_query() in PHP it doesnt give anything back, not even an error.
the code is:
select * from table t inner join ( select User_ID, max(Date) as MaxDate from table group by User_ID ) tm on t.User_ID = tm.User_ID and t.Date = tm.MaxDate
If you have any idea why please let me know :)
EDIT
the PHP code is :
$id = $_SESSION["ID"];
$SqlQuery = "SELECT * from 'tablename' t inner join ( select 'User_ID', max('Date') as 'MaxDate' from 'tablename' group by 'User_ID' ) tm on 't.User_ID' = 'tm.User_ID' and 't.Date' = 'tm.MaxDate'";
$Result = mysqli_query($link, $SqlQuery) or die ("not possible to execute query: $sql on $link");
if ($Result->num_rows > 0) {
while($row = $Result->fetch_assoc()) {
echo "<br> id: ". $row['Sick_ID']. " - UserID: ". $row['User_ID']. "- Reason " . $row['Reason'] . "<br>";
}
} else {
echo "0 results";
}
Add the schema owner prefix to the select query. It usually happens when executing mysql queries on PHP.
Select * from data.table_name as t1 inner join data.table_name_2 as t2 .....
Better if:
Select data.t1.id, data.t2.name from data_table_name as t1 .....

Get data from two different tables in the same query

I'm starting to learn php. I'm able to extract the list of CD from the SQL query in [in this table][1] but there's another query which contains the Category which is linked via ID in this table.
How do I get all the columns in the same result set using one query?
<?php
include 'database_conn.php';
$sql = "SELECT id, title, year, price FROM table_cd";
$queryresult = mysqli_query($conn, $sql)
or die (mysqli_error($conn));
while($row = mysqli_fetch_assoc($queryresult)) {
$iid = $row['id'];
$title = $row['title'];
$year = $row['year'];
$price = $row['price'];
echo "<div>
$title
</div>\n";
echo $row['year'];
echo $row['price'];
}
?>
editCDForm.php:
<?php
$code = $_GET['itemCode'];
$sql = "SELECT * FROM table_cd WHERE table_category.ID = $code
JOIN table_category ON (table_category.Desc = table_cd.ID)";
?>
What you're looking for is called a JOIN which allows you to merge the rows from two or more tables into the same result set.
You can modify your query as illustrated below, by using a LEFT JOIN of the nmc_cd table and the nmc_category table on the catID column, as the common primary attribute between them, giving you the desired result set...
$sql = "SELECT nmc_cd.CDID, nmc_cd.CDTitle, nmc_cd.CDYear,
nmc_cd.CDPrice, nmc_category.catDesc
FROM nmc_cd
JOIN nmc_category on nmc_cd.catID = nmc_cd.catID";
Here's a nice article that may help you visualize what a JOIN looks like in your SQL.
Syntax for joins:
SELECT * FROM table1
JOIN table2 ON (table2.colunmname = table1.columnname)
use can get the data from both tables when joining them:
$sql = "SELECT FT.CDID, FT.CDTitle, FT.CDYear, FT.CDPrice,
ST.catDesc FROM nmc_cd AS FT LEFT JOIN nmc_category as ST ON
FT.catID=ST.catID";

How to retrieve data from multiple tables using a PHP form?

I want to retrieve data from multiple tables using dot operator/join where arguments are passed from an HTML/PHP form.
HTML CODE
<input name="rollno" type="text" placeholder="Roll Number" required>
<input name="submit_view_details" type="submit" value="Proceed">
PHP CODE
if(isset($_POST['submit_view_details']))
{
$rollno = (int) $_POST['rollno'];
$query = "select * from table1, table2 where table1.{$rollno}=table2.{$rollno}";
$result=mysqli_query($connection,$query);
}
In the browser if enter the input 1 and echo this query then it looks like follows:
select * from table1, table2 where table1.1=table2.1
and no row is fetched despite of having data in the table(s).
it only works if the query looks like follows:
select * from table1,table2 where table1.rollno=table2.rollno
However, in that case it fetches all the rows but I need only the row of the rollno that user entered in the above mentioned form.
I am just not able to work this out. Help would be much appreciated. Thanks!
Use the AND keyword to specify the rollno.
SELECT * FROM table1, table2 WHERE table1.rollno = table2.rollno
AND table1.rollno = {$rollno};
You could probably use the keyword JOIN instead like this :
SELECT * FROM table1 NATURAL JOIN table2
WHERE rollno = {$rollno};
You need joins
take a reference of joins from here,
i am sure it will help
http://www.tutorialspoint.com/mysql/mysql-using-joins.htm
You should use join like this
$query = "SELECT tbl1.*, tbl2.*
FROM tbl1
INNER JOIN tbl2 ON tbl1.id = tbl2.id
WHERE tbl1.column = value ";
foreach ($pieces_2 AS $value) {
$pieces_3[] ="(CONCAT_WS('|',$presql2) like '%$value%')"; //concat all columns from one table
}
$serch_jyouken = implode(" and ",$pieces_3); // for multiple keywords
$result1 = mysqli_query($connection, "select p.p_no from pfr_data p where (" .$serch_jyouken .")");
$res1 = array();
while($r1 = mysqli_fetch_array($result1){
$res1[] = $r1['p_no'] ; //fetch primary key from table and store it into array
}
foreach ($pieces_2 AS $value) {
$pieces_4[] ="(CONCAT_WS('|',$presql3) like '%$value%')"; // same as above
}
$serch_jyouken1 = implode(" and ",$pieces_4);
$result2 = mysqli_query($connection, "select p2.p_no from pfr_mod_inform p2 where (" .$serch_jyouken1 .")" );
$res2 = array();
while($r2 = mysqli_fetch_array($result2)){
$res2[] = $r2['p_no'];
}
$res_mrg = array_merge($res1 , $res2); //merge array
$result = implode("','",$res_mrg ); // array to sring
$sql5 = $presql ." from pfr_data p where p.p_no in ('$result') order by p.section_p,p.status,p.no";

php/mysql with multiple queries

<?php
$query1 = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query2 = "CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query3 = "CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query4) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
All the queries work independently but am really struggling putting all the pieces together in one single result so I can use it with mysql_fetch_array.
I've tried to create views as well as temporary tables but each time it either says table does not exist or return an empty fetch array loop...logic is there but syntax is messed up I think as it's the 1st time I had to deal with multiple queries I need to merge all together. Looking forward to some support. Many thanks.
Thanks to php.net I've come up with a solution : you have to use (mysqli_multi_query($link, $query)) to run multiple concatenated queries.
/* create sql connection*/
$link = mysqli_connect("server", "user", "password", "database");
$query = "SQL STATEMENTS;"; /* first query : Notice the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS"; /* last query : Notice the dot before = at the end ! */
/* Execute queries */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_array($result))
/* print your results */
{
echo $row['column1'];
echo $row['column2'];
}
mysqli_free_result($result);
}
} while (mysqli_next_result($link));
}
EDIT - The solution above works if you really want to do one big query but it's also possible to execute as many queries as you wish and execute them separately.
$query1 = "Create temporary table A select c1 from t1";
$result1 = mysqli_query($link, $query1) or die(mysqli_error());
$query2 = "select c1 from A";
$result2 = mysqli_query($link, $query2) or die(mysqli_error());
while($row = mysqli_fetch_array($result2)) {
echo $row['c1'];
}
It seems you are not executing $query1 - $query3. You have just skipped to $query4 which won't work if the others have not been executed first.
Also
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
should probably be
$query4 = "SELECT *, #rank_change := prev_rank - current_rank as rank_change from final_output";
or else the value of rank_change will just be a boolean, true if #rank_change is equal to (prev_rank - current_rank), false if it is not. But do you need #rank_change at all? Will you use it in a subsequent query? Maybe you can remove it altogether.
Even better, you could just combine all the queries into one like this:
SELECT
curr.player,
curr.rank AS current_rank,
#rank_change := prev.rank - curr.rank AS rank_change
FROM
main_table AS curr
LEFT JOIN main_table AS prev
ON curr.player = prev.player
WHERE
curr.date = X
AND prev.date = date_sub('X', INTERVAL 1 MONTH)
You should concatenate them:
<?php
$query = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query .= " CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query .= " CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query .= " SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>

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