<?php
$query1 = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query2 = "CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query3 = "CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query4) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
All the queries work independently but am really struggling putting all the pieces together in one single result so I can use it with mysql_fetch_array.
I've tried to create views as well as temporary tables but each time it either says table does not exist or return an empty fetch array loop...logic is there but syntax is messed up I think as it's the 1st time I had to deal with multiple queries I need to merge all together. Looking forward to some support. Many thanks.
Thanks to php.net I've come up with a solution : you have to use (mysqli_multi_query($link, $query)) to run multiple concatenated queries.
/* create sql connection*/
$link = mysqli_connect("server", "user", "password", "database");
$query = "SQL STATEMENTS;"; /* first query : Notice the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS"; /* last query : Notice the dot before = at the end ! */
/* Execute queries */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_array($result))
/* print your results */
{
echo $row['column1'];
echo $row['column2'];
}
mysqli_free_result($result);
}
} while (mysqli_next_result($link));
}
EDIT - The solution above works if you really want to do one big query but it's also possible to execute as many queries as you wish and execute them separately.
$query1 = "Create temporary table A select c1 from t1";
$result1 = mysqli_query($link, $query1) or die(mysqli_error());
$query2 = "select c1 from A";
$result2 = mysqli_query($link, $query2) or die(mysqli_error());
while($row = mysqli_fetch_array($result2)) {
echo $row['c1'];
}
It seems you are not executing $query1 - $query3. You have just skipped to $query4 which won't work if the others have not been executed first.
Also
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
should probably be
$query4 = "SELECT *, #rank_change := prev_rank - current_rank as rank_change from final_output";
or else the value of rank_change will just be a boolean, true if #rank_change is equal to (prev_rank - current_rank), false if it is not. But do you need #rank_change at all? Will you use it in a subsequent query? Maybe you can remove it altogether.
Even better, you could just combine all the queries into one like this:
SELECT
curr.player,
curr.rank AS current_rank,
#rank_change := prev.rank - curr.rank AS rank_change
FROM
main_table AS curr
LEFT JOIN main_table AS prev
ON curr.player = prev.player
WHERE
curr.date = X
AND prev.date = date_sub('X', INTERVAL 1 MONTH)
You should concatenate them:
<?php
$query = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query .= " CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query .= " CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query .= " SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
Related
<?php
$query1 = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query2 = "CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query3 = "CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query4) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
All the queries work independently but am really struggling putting all the pieces together in one single result so I can use it with mysql_fetch_array.
I've tried to create views as well as temporary tables but each time it either says table does not exist or return an empty fetch array loop...logic is there but syntax is messed up I think as it's the 1st time I had to deal with multiple queries I need to merge all together. Looking forward to some support. Many thanks.
Thanks to php.net I've come up with a solution : you have to use (mysqli_multi_query($link, $query)) to run multiple concatenated queries.
/* create sql connection*/
$link = mysqli_connect("server", "user", "password", "database");
$query = "SQL STATEMENTS;"; /* first query : Notice the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS;"; /* Notice the dot before = and the 2 semicolons at the end ! */
$query .= "SQL STATEMENTS"; /* last query : Notice the dot before = at the end ! */
/* Execute queries */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_array($result))
/* print your results */
{
echo $row['column1'];
echo $row['column2'];
}
mysqli_free_result($result);
}
} while (mysqli_next_result($link));
}
EDIT - The solution above works if you really want to do one big query but it's also possible to execute as many queries as you wish and execute them separately.
$query1 = "Create temporary table A select c1 from t1";
$result1 = mysqli_query($link, $query1) or die(mysqli_error());
$query2 = "select c1 from A";
$result2 = mysqli_query($link, $query2) or die(mysqli_error());
while($row = mysqli_fetch_array($result2)) {
echo $row['c1'];
}
It seems you are not executing $query1 - $query3. You have just skipped to $query4 which won't work if the others have not been executed first.
Also
$query4 = "SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
should probably be
$query4 = "SELECT *, #rank_change := prev_rank - current_rank as rank_change from final_output";
or else the value of rank_change will just be a boolean, true if #rank_change is equal to (prev_rank - current_rank), false if it is not. But do you need #rank_change at all? Will you use it in a subsequent query? Maybe you can remove it altogether.
Even better, you could just combine all the queries into one like this:
SELECT
curr.player,
curr.rank AS current_rank,
#rank_change := prev.rank - curr.rank AS rank_change
FROM
main_table AS curr
LEFT JOIN main_table AS prev
ON curr.player = prev.player
WHERE
curr.date = X
AND prev.date = date_sub('X', INTERVAL 1 MONTH)
You should concatenate them:
<?php
$query = "CREATE VIEW current_rankings AS SELECT * FROM main_table WHERE date = X";
$query .= " CREATE VIEW previous_rankings AS SELECT rank FROM main_table WHERE date = date_sub('X', INTERVAL 1 MONTH)";
$query .= " CREATE VIEW final_output AS SELECT current_rankings.player, current_rankings.rank as current_rank LEFT JOIN previous_rankings.rank as prev_rank
ON (current_rankings.player = previous_rankings.player)";
$query .= " SELECT *, #rank_change = prev_rank - current_rank as rank_change from final_output";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['player']. $row['current_rank']. $row['prev_rank']. $row['rank_change'];
}
?>
I have a SELECT query from one table that works great as follows:
$sql = "SELECT count(max720) AS anzahlpositive1 from table where (((max720 - lastsignal)/lastsignal)*100) >= 1 AND (((max720 - lastsignal)/lastsignal)*100) < 2 AND max720 != ''";
$result = $conn->query($sql);
But I had 20-30 of them with other values.
For every SELECT query a new connection established.. I think thats a lot of perfomance.
Thats the 2nd:
$sql = "SELECT count(max720) AS anzahlpositive2 from table where (((max720 - lastsignal)/lastsignal)*100) >= 2 AND (((max720 - lastsignal)/lastsignal)*100) < 3 AND max720 != ''";
$result = $conn->query($sql);
Is is possible to do this in ONE select? (better performance)
I have tried with UNION (but i think its for 2 or more tables)
Is that a solution?
$sql = "SELECT 1";
$sql .= "SELECT 2";
$sql .= "SELECT 3";
...
$result = $conn->query($sql);
while($row = $result->fetch_assoc()) {
echo $anzahlpositive1 ;
echo $anzahlpositive2 ;
echo $anzahlpositive3 ;
....
}
select count(max720) AS ...
union all
select count(max720) AS ...
You can use as many unions as you want, read the difference between union and union all, union will discard duplicates.
I want to use the result set of a query in the where statement of a subsequent query.
Running into a problem because the first query returns multiple results and I don't know how to convert these to a comma-separated string for use in an 'IN' () statement.
$Result1 = mysql_query ("
select id from Table1
where
upper('$Input') = Employee_number
")
or die(mysql_error());
$Result2 = mysql_query ("
Select * from table2 where ID in ($Result1)")
You can combine this into a single MySQL statement like this:
SELECT * FROM Table2 WHERE id IN
(SELECT id FROM Table1 where upper('$Input') = Employee_number);
But if you really want to do it like in your question, you will probably have to lookup how to work with the results from mysql_query, just look that up in a function reference.
$query1 = mysql_query("
select id from Table1
where upper('$Input') = Employee_number
") or die(mysql_error());
$ids = array();
while($Result1 = mysql_fetch_array($query1))
{
$ids[] = $Result1['id'];
}
if(sizeof($ids))
{
$n_ids = implode(',', $ids);
$query2 = mysql_query("
select * from Table2
where ID IN (" . $n_ids . ")
") or die(mysql_error());
}
i need to select one row where slot_left is the biggest. i tried
for ( $i=1;$i<3;$i++) {
$sql5 = "SELECT * from user u where (
select max(slot_left) from company c,user u
where c.id=u.company_id and c.id='$name'
)";
$result5 = mysqli_query($link, $sql5) or die(mysqli_error($link));
while($row=mysqli_fetch_array($result5)) {
// echo the id which the slot_left is the biggest
echo $i['slot_left'];
}
}
but still cannot. please help!
You have to use GROUP BY in your query.
And query execution in Loop is not recommended, it will decrees performance.
Try this.
$sql5 = "select c.id, max(slot_left) from company c,user u
where c.id=u.company_id and c.id='$id' GROUP by c.id";
$result5 = mysqli_query($link, $sql5) or die(mysqli_error($link));
while($row=mysqli_fetch_array($result5)) {
echo $row['slot_left'];
}
SQL can be. You select all rows from DB.
$sql5 = "select max(slot_left) AS slot_left from company c,user u where c.id=u.company_id and c.id='$name' GROUP by u.company_id";
$name variable used in query not set
Variable $i is not array. Array is $row
echo $row['slot_left'];
I write a lot of queries resembling the query example code below. I was wondering whether there was a more efficient code/script?
$query1 ="SELECT * FROM table1 WHERE date >= '$todaysdate' ";
$result1 = mysql_query($query1)
or die ("Error in query: $query1. " . mysql_error());
if (mysql_num_rows($result1) > 0) {
while($row1 = mysql_fetch_object($result1)) {
echo "$row1-date";
$query2 ="SELECT * FROM table2 WHERE table1ID >= '$row1-table1ID' ";
$result2 = mysql_query($query2)
or die ("Error in query: $query2. " . mysql_error());
if (mysql_num_rows($result2) > 0) {
while($row2 = mysql_fetch_object($result2)) {
echo "$row->datatable2";
}
}
}
}
Try using SQL JOINs, like the following example:
SELECT
*
FROM
table1
INNER JOIN
table2 ON (table2.table1ID = table1.ID)
WHERE
table1.date >= '2009-12-20';
I don't know about the structure of your tables, but I've modified your code so that it uses a join:
$query = 'SELECT table1.date, table2.datatable2 FROM table1, table2 WHERE table1.date >= \''.$todaysdate.'\' AND table2.table1ID >= table1.table1ID';
$result = mysql_query($query)
or exit('Error in query: '.$query.' '.mysql_error());
if (mysql_num_rows($result) > 0)
{
while($row = mysql_fetch_object($result))
{
echo $row->date;
echo $row->datatable2;
}
}
In this case you select multiple tables with FROM separated with commas, but you can also use INNER/OUTER/LEFT/RIGHT JOIN (see the link in the first answer).
You can use PDO.
Your queries should look like this..
$sth = $dbh->prepare("SELECT name, colour FROM fruit");
$sth->execute();
$result = $sth->fetchAll(PDO::FETCH_COLUMN);
// OR
$result = $sth->fetchAll(PDO::FETCH_OBJ);
var_dump($result);
PDO MANUAL: http://php.net/manual/en/book.pdo.php